anonymous
  • anonymous
There are three suspects for a murder: Adams, Brown, and Clark. Adams says "I didn't do it. The victim was an old acquaintance of Brown's. But Clark hated him." Brown states "I didn't do it. I didn't know the guy. Besides I was out of town all week." Clark says "I didn't do it. I saw both Adams and Brown in town around the victim that day; one of them must have done it." We know that exactly one of the suspects is guilty. Assume that the two innocent men are telling the truth, but that the guilty man might not be. Let the propositional variables have the following definitions:
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
jamiebookeater
  • jamiebookeater
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
Let the propositional variables have the following definitions: A = Adams is innocent B = Brown is innocent C = Clark is innocent X = Brown knew the victim Y = Brown was out of town Z = Adams was out of town W = Clark hated the victim
anonymous
  • anonymous
Formalize the description of each of the sentences below in propositional logic sentences using the variables above. Exactly one of the suspects is guilty: (A->~B)^(B->(~A^~C))^(C->~B)
anonymous
  • anonymous
A word on notation: In all of the HTML pages (problems and exercises) we are using the following notation for propositional logic: ^ (caret) for and, v (lower case v) for or, ~ for not, -> (hyphen, >) for implication, and <-> (<, hyphen, >) for biconditionals. Propositional variables are upper case letters (and possibly numbers). The symbols true and false are written out in lower case.

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
I FOUND MY LOGIC IS FALSE IN : Exactly one of the suspects is guilty: (A->~B)^(B->(~A^~C))^(C->~B) HOW SHOULD I CHANGE THIS
anonymous
  • anonymous
I EVEN TRIED THIS ONE, TOO. BUT IT DIDN'T WORK : (~A -> B^C) ^ (~B-> A^C) ^ (~C -> A^B)
anonymous
  • anonymous
SORRY, I FINALLY SOLVE THIS ONE (A^B^~C)v(B^~A^C)v(C^A^~B)
anonymous
  • anonymous
Reference : 6.034(artificial intelligence) pset4

Looking for something else?

Not the answer you are looking for? Search for more explanations.