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chungerforever

  • 2 years ago

would the answer of (a − b)(a − b) be a^2 - ab^2 - b^2

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  1. TransendentialPI
    • 2 years ago
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    FOIL First: a*a = a^2 Outside = -ab Inside = -ab Last = -b(-b) = +b^2 What do we do with the -ab and the -ab?

  2. TransendentialPI
    • 2 years ago
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    Tkink -x + -x = -2x

  3. chungerforever
    • 2 years ago
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    I know to combine itt

  4. satellite73
    • 2 years ago
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    @chungerforever remember when we had \(5x+5x=10x\)? don't change the exponents here either

  5. satellite73
    • 2 years ago
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    \(-ab-ab=?\)

  6. chungerforever
    • 2 years ago
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    oh minus! so just ab?

  7. satellite73
    • 2 years ago
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    \(-10-10=?\)

  8. chungerforever
    • 2 years ago
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    oh I understand, so the answer is just a^2 - b^2?

  9. satellite73
    • 2 years ago
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    hold the phone, careful arithmetic \(-10-10=?\)

  10. satellite73
    • 2 years ago
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    hint, it is not 0

  11. chungerforever
    • 2 years ago
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    I'm sorry I have no idea, I'm not good at algebra ):

  12. chungerforever
    • 2 years ago
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    -10?

  13. satellite73
    • 2 years ago
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    don't fret, we will work it out, but i was asking an arithmetic question \(-10-10=-20\)

  14. satellite73
    • 2 years ago
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    \(-100-100=?\)

  15. chungerforever
    • 2 years ago
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    -200?

  16. satellite73
    • 2 years ago
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    yes that is it !

  17. satellite73
    • 2 years ago
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    \(-7-7=?\)

  18. chungerforever
    • 2 years ago
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    -14

  19. satellite73
    • 2 years ago
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    ok good now we can move on to variables

  20. satellite73
    • 2 years ago
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    \[-10-10=-20\] \[-100-100=-200\] \[-7-7=-14\] \[-12-12=-24\] and so on how about \[-x-x\]? well this must be the same as the others, namely \[-x-x=-2x\]

  21. chungerforever
    • 2 years ago
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    so -2ab?

  22. satellite73
    • 2 years ago
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    notice that the exponent does not change spend $20, spend another $20 you have spent \(2\times 20=40\) yes you have it !

  23. satellite73
    • 2 years ago
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    so "final answer" for \((a-b)(a-b)\) is ??

  24. chungerforever
    • 2 years ago
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    a^2 - 2ab - b^2?

  25. satellite73
    • 2 years ago
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    yes that is it!

  26. chungerforever
    • 2 years ago
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    thank you so much! and sorry I was taking a while to reply. But thanks again I appreciate it (:

  27. satellite73
    • 2 years ago
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    yw good work, hope you are understanding a bit more about combining like terms

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