A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
GIven that \(f(x) = \sqrt{9  x^2}\), and that \(g(x) = f(x  4)\), rewrite g(x) in terms of x. Please tell me how to do it and not just the answer.
anonymous
 4 years ago
GIven that \(f(x) = \sqrt{9  x^2}\), and that \(g(x) = f(x  4)\), rewrite g(x) in terms of x. Please tell me how to do it and not just the answer.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[g(x)=f(x4)\]Notice that\[f(x4)=\sqrt{9(x4)^2}\] Follow so far?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1344985583558:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh...so you plugged in f(x  4) which is formed by plugging in (x  4) for x in f(x)?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yup\[g(x)=f(x4)=\sqrt{9(x4^2)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So it would be: \[g(x) = \sqrt{x^2 + 8x  7}~?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes you could simplify it further to what you did,. Just another example: If it was \[g(x)=f(x+5x^2)\] Then:\[g(x)=f(x+5x^2)=\sqrt{9(x+5x^2)^2}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh I get it...but for more practical uses, it would be just left as \[g(x) = \sqrt{9  (x  4)^2}~?\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That's how I would leave it, unless your professor told you otherwise

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Alright. THank you :) Just needed a quick refresher since I forgot how to do these momentarily!
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.