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Mimi_x3Best ResponseYou've already chosen the best response.1
I assume its an integral \[\int\limits x\sqrt{8+2xx^{2}}dx \] Well, complete the square first; then looks like a sub
 one year ago

wafaaBest ResponseYou've already chosen the best response.0
yes. I've done the completing the square but not sure whats the next step. by part or substitution?
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
looks like a substitution would be easier
 one year ago

wafaaBest ResponseYou've already chosen the best response.0
ok. i"ll try again. tq :)
 one year ago

wafaaBest ResponseYou've already chosen the best response.0
still dont get it. help me plez :(
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
\[\int\limits x\sqrt{x^{2}+2x+8} dx => \int\limits x\sqrt{(x^{2}2x8)} dx => \int\limits x\sqrt{((x^{2}1)^{2}(1)^{2}+8))} dx\] \[=> \int\limits x\sqrt{(x^{2}1)9} dx => \int\limits x\sqrt{9(x1)^{2}} dx\] let u = x1 > x = u+1 \[=> \int\limits\left(u+1\right)\sqrt{9u^{2}}du \]
 one year ago

wafaaBest ResponseYou've already chosen the best response.0
ok mimi.i'll try. thanks again.
 one year ago

Mimi_x3Best ResponseYou've already chosen the best response.1
np and for this u = 3sin\theta
 one year ago
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