sin(arcsin(-11π/13)
I'd really just like an explanation of this one.

- anonymous

sin(arcsin(-11π/13)
I'd really just like an explanation of this one.

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- schrodinger

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- anonymous

I don't know why I'm forgetting how to do this, but it's been awhile and my final is coming up and I want a better understanding of it.

- anonymous

do you know the init Circle?

- anonymous

Yep

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## More answers

- anonymous

when you at look the unit circle what quard would Sin be in?

- anonymous

I see that it goes -11π, so I believe it's going clockwise around the unit circle and I think it gets to Q3.

- anonymous

yes correct, so in the problem what does that tell you?

- anonymous

I don't know...hahaha, rephrase that maybe?

- anonymous

from looking at this problem and taking the information you already have what would you say the answer is? sin(arcsin(-11π/13)

- anonymous

do you understand arcsin and what that means??

- anonymous

crap, I wrote it down wrong. It was arcsin(sin(-11π/13))

- anonymous

I have a pretty good understanding of how to use it. I'm rusty, though.

- anonymous

okay, let us take this and break it down on what you know, you start I will fill in if needed.

- anonymous

I believe sin(ø) = arcsin (-11π/13) in this situation.

- anonymous

you are right, but how did you do that?

- anonymous

I just kind of have that memorized. I guess I never really grasped that...

- anonymous

okay, now I have a stupid what is the question asking for??? I am a little lost with the question here does it ask to solve or what?

- anonymous

Find the exact value of the given expression. Simplify your answer (rationalize the denom)

- anonymous

I also have that the answer is -2π/13

- anonymous

I don't really understand where the 2π comes from.

- anonymous

because recall the unit circle has a total of 360 degrees right?

- anonymous

Yep and 2π is 360º

- anonymous

2/pie is a point on the Unit the circle in which the angle is 360.. you beat to that one good job

- anonymous

So, my picture shows the line -11π/13 and the distance between that line and the 180º line is 2π/13.

- anonymous

Having a hard time understanding why it's 2π and not just π.

- anonymous

Probably just overthinking it.

- anonymous

what I am questioning here the negative here in this case?

- anonymous

because you start with a negative you will most likely end that way..

- anonymous

2pie is at the 360 degrees which has points 0,0 so how can that be a negative result help here?

- anonymous

One sec, gonna post a photo of what is giving me a headache.

- anonymous

I think we are both getting the same headache on this. This problem is going down..

- anonymous

Hahaha, I'm tellin' you. I haven't had any problems with any other questions, but this one is just destroying my brain.

- anonymous

yeah, the same thing only that my brain is dead because I am stuying Vectors myself.

- anonymous

what I am missing here????

- lgbasallote

is the question still \[\sin (arcsin (-11 \pi/3)\]

- anonymous

arcsin(sin(-11π/3))

- anonymous

yes sir, please help me I am getting a major headache here

- anonymous

Messed up the on the original post

- lgbasallote

here's a hint..
arcsin( sin x) = x
sin (arcsin x) = x
cos( arc cos x) = x
arc cos (cos x) = x
tan (arctan x) = x
arctan (tan x) = x
does that help?

- anonymous

##### 1 Attachment

- anonymous

There is the picture that I was trying to describe.

- anonymous

I wish that helped, but I still can't figure out why it is -2π/13

- lgbasallote

is that included in the question? or is that your solytion?

- anonymous

Solution. It's an answer key and I'm trying to decipher it.

- anonymous

I know it is -2π/13 because of the range, but I don't know where the 2π came from.

- lgbasallote

use the hint i gave you...here's a demo \[\sin (\sin^{-1} ( \frac{\pi}{2} ) ) = \frac{\pi}{2}\]
\[\sin^{-1} (\sin ( \frac{2 \pi}{5} ) ) = \frac{2 \pi}{5}\]
getting it now?

- lgbasallote

\[\sin^{-1} (\sin ( \frac{-11\pi}{3} ) ) = -\frac{11\pi}{3}\]
then simplify that you get \[-\frac{2\pi}{3}\]
make sense?

- anonymous

lgbasallote what did I miss here? I mean I thought for sure I was going the right way what did I do in my steps that went wrong here? Help me to understand..

- anonymous

How'd you simplify to that?

- lgbasallote

i think i wrote the wrong thingies lol...

- lgbasallote

but that's the concept

- anonymous

Yeah, I knew what you were saying with the others. It's this deal here. I don't understand how it is simplifying from 11π to 2π.

- anonymous

It's like it just magically disappears.

- lgbasallote

reference angles

- anonymous

Heh, I feel dumb for not knowing still.

- anonymous

Mrcarey I am so sorry I took the long way here.

- anonymous

Haha, no problem at all. I've been at it for so long, it didn't even feel that long.

- anonymous

ha ha yeah better next time right? HA HA..

- anonymous

Exactly! Thanks for trying at least. Good luck with the vector calc. I'll be THERE soon enough.

- anonymous

I am Physics Engineering major myelf

- anonymous

Mech E. for me. Math math math math and more math!

- anonymous

you got this now

- anonymous

Yeah, I feel better about it. Got one more day of review in class, so I'll probably bring it up with him anyway. Thanks again!

- anonymous

do you another problem you need help on? Just asking here

- anonymous

Nope, this one seemed to be the only one I kept coming back to. This stupid thing made everything else seem easy!

- anonymous

yeah, I only hope for me it is just one problem that will allow everything to be easy after that. Fat chance ha ha

- anonymous

Hahahaha, no way. I've peeked at that stuff and needed to take a nap after.

- anonymous

did that one already.. I took a 5hrs nap

- anonymous

I am doing Calc1 andPhysics 1 with Calc

- anonymous

I'll be doing that in the Fall. Well, no Physics yet, couldn't get in the class. General Chem 1 and Calc 1. Gonna be exciting.

- anonymous

what school?

- anonymous

Doing community for now, so I can transfer to University of Washington Seattle.

- anonymous

You?

- anonymous

cool I live Iin Portland Ore myself..

- anonymous

I will start Sept 24th at Jr College than transfer to Tarleton ST university in TX in Spring 2013

- anonymous

Awesome, TX should be pretty fun. Definitely a change of scenery.

- anonymous

I am studying math and Physics by watching videos and taking notes on my own

- anonymous

Khan Academy?

- anonymous

yeah StephenVille is very small town though

- anonymous

who is Khan A?

- anonymous

www.khanacademy.com
MIT grad who made his own site that teaches every kind of math and most sciences.

- anonymous

Free site for learning. I've used it for awhile now. Especially when I get bad professors.

- anonymous

funny you just posted MIT, Because I am using thier open courses on line for the video in math and Physics

- anonymous

Haha, that works, too! You'd probably like his teaching style. He is very helpful and has tons of videos. I always recommend the site.

- anonymous

thanks will check it out, hey you have a great night and if you need me to help me message me

- anonymous

you

- anonymous

Sounds like a plan! Have a good night!

- anonymous

you too.

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