Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
sin(arcsin(11π/13)
I'd really just like an explanation of this one.
 one year ago
 one year ago
sin(arcsin(11π/13) I'd really just like an explanation of this one.
 one year ago
 one year ago

This Question is Closed

MrCareyBest ResponseYou've already chosen the best response.0
I don't know why I'm forgetting how to do this, but it's been awhile and my final is coming up and I want a better understanding of it.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
do you know the init Circle?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
when you at look the unit circle what quard would Sin be in?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I see that it goes 11π, so I believe it's going clockwise around the unit circle and I think it gets to Q3.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yes correct, so in the problem what does that tell you?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I don't know...hahaha, rephrase that maybe?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
from looking at this problem and taking the information you already have what would you say the answer is? sin(arcsin(11π/13)
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
do you understand arcsin and what that means??
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
crap, I wrote it down wrong. It was arcsin(sin(11π/13))
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I have a pretty good understanding of how to use it. I'm rusty, though.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
okay, let us take this and break it down on what you know, you start I will fill in if needed.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I believe sin(ø) = arcsin (11π/13) in this situation.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
you are right, but how did you do that?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I just kind of have that memorized. I guess I never really grasped that...
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
okay, now I have a stupid what is the question asking for??? I am a little lost with the question here does it ask to solve or what?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Find the exact value of the given expression. Simplify your answer (rationalize the denom)
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I also have that the answer is 2π/13
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I don't really understand where the 2π comes from.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
because recall the unit circle has a total of 360 degrees right?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
2/pie is a point on the Unit the circle in which the angle is 360.. you beat to that one good job
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
So, my picture shows the line 11π/13 and the distance between that line and the 180º line is 2π/13.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Having a hard time understanding why it's 2π and not just π.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Probably just overthinking it.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
what I am questioning here the negative here in this case?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
because you start with a negative you will most likely end that way..
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
2pie is at the 360 degrees which has points 0,0 so how can that be a negative result help here?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
One sec, gonna post a photo of what is giving me a headache.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I think we are both getting the same headache on this. This problem is going down..
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Hahaha, I'm tellin' you. I haven't had any problems with any other questions, but this one is just destroying my brain.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yeah, the same thing only that my brain is dead because I am stuying Vectors myself.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
what I am missing here????
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
is the question still \[\sin (arcsin (11 \pi/3)\]
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yes sir, please help me I am getting a major headache here
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Messed up the on the original post
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
here's a hint.. arcsin( sin x) = x sin (arcsin x) = x cos( arc cos x) = x arc cos (cos x) = x tan (arctan x) = x arctan (tan x) = x does that help?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
There is the picture that I was trying to describe.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I wish that helped, but I still can't figure out why it is 2π/13
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
is that included in the question? or is that your solytion?
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Solution. It's an answer key and I'm trying to decipher it.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I know it is 2π/13 because of the range, but I don't know where the 2π came from.
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
use the hint i gave you...here's a demo \[\sin (\sin^{1} ( \frac{\pi}{2} ) ) = \frac{\pi}{2}\] \[\sin^{1} (\sin ( \frac{2 \pi}{5} ) ) = \frac{2 \pi}{5}\] getting it now?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
\[\sin^{1} (\sin ( \frac{11\pi}{3} ) ) = \frac{11\pi}{3}\] then simplify that you get \[\frac{2\pi}{3}\] make sense?
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
lgbasallote what did I miss here? I mean I thought for sure I was going the right way what did I do in my steps that went wrong here? Help me to understand..
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
How'd you simplify to that?
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
i think i wrote the wrong thingies lol...
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.1
but that's the concept
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Yeah, I knew what you were saying with the others. It's this deal here. I don't understand how it is simplifying from 11π to 2π.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
It's like it just magically disappears.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Heh, I feel dumb for not knowing still.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
Mrcarey I am so sorry I took the long way here.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Haha, no problem at all. I've been at it for so long, it didn't even feel that long.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
ha ha yeah better next time right? HA HA..
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Exactly! Thanks for trying at least. Good luck with the vector calc. I'll be THERE soon enough.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I am Physics Engineering major myelf
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Mech E. for me. Math math math math and more math!
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Yeah, I feel better about it. Got one more day of review in class, so I'll probably bring it up with him anyway. Thanks again!
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
do you another problem you need help on? Just asking here
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Nope, this one seemed to be the only one I kept coming back to. This stupid thing made everything else seem easy!
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yeah, I only hope for me it is just one problem that will allow everything to be easy after that. Fat chance ha ha
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Hahahaha, no way. I've peeked at that stuff and needed to take a nap after.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
did that one already.. I took a 5hrs nap
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I am doing Calc1 andPhysics 1 with Calc
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
I'll be doing that in the Fall. Well, no Physics yet, couldn't get in the class. General Chem 1 and Calc 1. Gonna be exciting.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Doing community for now, so I can transfer to University of Washington Seattle.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
cool I live Iin Portland Ore myself..
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I will start Sept 24th at Jr College than transfer to Tarleton ST university in TX in Spring 2013
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Awesome, TX should be pretty fun. Definitely a change of scenery.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
I am studying math and Physics by watching videos and taking notes on my own
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
yeah StephenVille is very small town though
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
www.khanacademy.com MIT grad who made his own site that teaches every kind of math and most sciences.
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Free site for learning. I've used it for awhile now. Especially when I get bad professors.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
funny you just posted MIT, Because I am using thier open courses on line for the video in math and Physics
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Haha, that works, too! You'd probably like his teaching style. He is very helpful and has tons of videos. I always recommend the site.
 one year ago

godorovgBest ResponseYou've already chosen the best response.1
thanks will check it out, hey you have a great night and if you need me to help me message me
 one year ago

MrCareyBest ResponseYou've already chosen the best response.0
Sounds like a plan! Have a good night!
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.