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do you know the init Circle?

Yep

when you at look the unit circle what quard would Sin be in?

yes correct, so in the problem what does that tell you?

I don't know...hahaha, rephrase that maybe?

do you understand arcsin and what that means??

crap, I wrote it down wrong. It was arcsin(sin(-11π/13))

I have a pretty good understanding of how to use it. I'm rusty, though.

okay, let us take this and break it down on what you know, you start I will fill in if needed.

I believe sin(ø) = arcsin (-11π/13) in this situation.

you are right, but how did you do that?

I just kind of have that memorized. I guess I never really grasped that...

Find the exact value of the given expression. Simplify your answer (rationalize the denom)

I also have that the answer is -2π/13

I don't really understand where the 2π comes from.

because recall the unit circle has a total of 360 degrees right?

Yep and 2π is 360º

2/pie is a point on the Unit the circle in which the angle is 360.. you beat to that one good job

So, my picture shows the line -11π/13 and the distance between that line and the 180º line is 2π/13.

Having a hard time understanding why it's 2π and not just π.

Probably just overthinking it.

what I am questioning here the negative here in this case?

because you start with a negative you will most likely end that way..

2pie is at the 360 degrees which has points 0,0 so how can that be a negative result help here?

One sec, gonna post a photo of what is giving me a headache.

I think we are both getting the same headache on this. This problem is going down..

yeah, the same thing only that my brain is dead because I am stuying Vectors myself.

what I am missing here????

is the question still \[\sin (arcsin (-11 \pi/3)\]

arcsin(sin(-11π/3))

yes sir, please help me I am getting a major headache here

Messed up the on the original post

There is the picture that I was trying to describe.

I wish that helped, but I still can't figure out why it is -2π/13

is that included in the question? or is that your solytion?

Solution. It's an answer key and I'm trying to decipher it.

I know it is -2π/13 because of the range, but I don't know where the 2π came from.

How'd you simplify to that?

i think i wrote the wrong thingies lol...

but that's the concept

It's like it just magically disappears.

reference angles

Heh, I feel dumb for not knowing still.

Mrcarey I am so sorry I took the long way here.

Haha, no problem at all. I've been at it for so long, it didn't even feel that long.

ha ha yeah better next time right? HA HA..

Exactly! Thanks for trying at least. Good luck with the vector calc. I'll be THERE soon enough.

I am Physics Engineering major myelf

Mech E. for me. Math math math math and more math!

you got this now

do you another problem you need help on? Just asking here

Hahahaha, no way. I've peeked at that stuff and needed to take a nap after.

did that one already.. I took a 5hrs nap

I am doing Calc1 andPhysics 1 with Calc

what school?

Doing community for now, so I can transfer to University of Washington Seattle.

You?

cool I live Iin Portland Ore myself..

I will start Sept 24th at Jr College than transfer to Tarleton ST university in TX in Spring 2013

Awesome, TX should be pretty fun. Definitely a change of scenery.

I am studying math and Physics by watching videos and taking notes on my own

Khan Academy?

yeah StephenVille is very small town though

who is Khan A?

Free site for learning. I've used it for awhile now. Especially when I get bad professors.

thanks will check it out, hey you have a great night and if you need me to help me message me

you

Sounds like a plan! Have a good night!

you too.