sin(arcsin(-11π/13) I'd really just like an explanation of this one.

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sin(arcsin(-11π/13) I'd really just like an explanation of this one.

Mathematics
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I don't know why I'm forgetting how to do this, but it's been awhile and my final is coming up and I want a better understanding of it.
do you know the init Circle?
Yep

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when you at look the unit circle what quard would Sin be in?
I see that it goes -11π, so I believe it's going clockwise around the unit circle and I think it gets to Q3.
yes correct, so in the problem what does that tell you?
I don't know...hahaha, rephrase that maybe?
from looking at this problem and taking the information you already have what would you say the answer is? sin(arcsin(-11π/13)
do you understand arcsin and what that means??
crap, I wrote it down wrong. It was arcsin(sin(-11π/13))
I have a pretty good understanding of how to use it. I'm rusty, though.
okay, let us take this and break it down on what you know, you start I will fill in if needed.
I believe sin(ø) = arcsin (-11π/13) in this situation.
you are right, but how did you do that?
I just kind of have that memorized. I guess I never really grasped that...
okay, now I have a stupid what is the question asking for??? I am a little lost with the question here does it ask to solve or what?
Find the exact value of the given expression. Simplify your answer (rationalize the denom)
I also have that the answer is -2π/13
I don't really understand where the 2π comes from.
because recall the unit circle has a total of 360 degrees right?
Yep and 2π is 360º
2/pie is a point on the Unit the circle in which the angle is 360.. you beat to that one good job
So, my picture shows the line -11π/13 and the distance between that line and the 180º line is 2π/13.
Having a hard time understanding why it's 2π and not just π.
Probably just overthinking it.
what I am questioning here the negative here in this case?
because you start with a negative you will most likely end that way..
2pie is at the 360 degrees which has points 0,0 so how can that be a negative result help here?
One sec, gonna post a photo of what is giving me a headache.
I think we are both getting the same headache on this. This problem is going down..
Hahaha, I'm tellin' you. I haven't had any problems with any other questions, but this one is just destroying my brain.
yeah, the same thing only that my brain is dead because I am stuying Vectors myself.
what I am missing here????
is the question still \[\sin (arcsin (-11 \pi/3)\]
arcsin(sin(-11π/3))
yes sir, please help me I am getting a major headache here
Messed up the on the original post
here's a hint.. arcsin( sin x) = x sin (arcsin x) = x cos( arc cos x) = x arc cos (cos x) = x tan (arctan x) = x arctan (tan x) = x does that help?
There is the picture that I was trying to describe.
I wish that helped, but I still can't figure out why it is -2π/13
is that included in the question? or is that your solytion?
Solution. It's an answer key and I'm trying to decipher it.
I know it is -2π/13 because of the range, but I don't know where the 2π came from.
use the hint i gave you...here's a demo \[\sin (\sin^{-1} ( \frac{\pi}{2} ) ) = \frac{\pi}{2}\] \[\sin^{-1} (\sin ( \frac{2 \pi}{5} ) ) = \frac{2 \pi}{5}\] getting it now?
\[\sin^{-1} (\sin ( \frac{-11\pi}{3} ) ) = -\frac{11\pi}{3}\] then simplify that you get \[-\frac{2\pi}{3}\] make sense?
lgbasallote what did I miss here? I mean I thought for sure I was going the right way what did I do in my steps that went wrong here? Help me to understand..
How'd you simplify to that?
i think i wrote the wrong thingies lol...
but that's the concept
Yeah, I knew what you were saying with the others. It's this deal here. I don't understand how it is simplifying from 11π to 2π.
It's like it just magically disappears.
reference angles
Heh, I feel dumb for not knowing still.
Mrcarey I am so sorry I took the long way here.
Haha, no problem at all. I've been at it for so long, it didn't even feel that long.
ha ha yeah better next time right? HA HA..
Exactly! Thanks for trying at least. Good luck with the vector calc. I'll be THERE soon enough.
I am Physics Engineering major myelf
Mech E. for me. Math math math math and more math!
you got this now
Yeah, I feel better about it. Got one more day of review in class, so I'll probably bring it up with him anyway. Thanks again!
do you another problem you need help on? Just asking here
Nope, this one seemed to be the only one I kept coming back to. This stupid thing made everything else seem easy!
yeah, I only hope for me it is just one problem that will allow everything to be easy after that. Fat chance ha ha
Hahahaha, no way. I've peeked at that stuff and needed to take a nap after.
did that one already.. I took a 5hrs nap
I am doing Calc1 andPhysics 1 with Calc
I'll be doing that in the Fall. Well, no Physics yet, couldn't get in the class. General Chem 1 and Calc 1. Gonna be exciting.
what school?
Doing community for now, so I can transfer to University of Washington Seattle.
You?
cool I live Iin Portland Ore myself..
I will start Sept 24th at Jr College than transfer to Tarleton ST university in TX in Spring 2013
Awesome, TX should be pretty fun. Definitely a change of scenery.
I am studying math and Physics by watching videos and taking notes on my own
Khan Academy?
yeah StephenVille is very small town though
who is Khan A?
www.khanacademy.com MIT grad who made his own site that teaches every kind of math and most sciences.
Free site for learning. I've used it for awhile now. Especially when I get bad professors.
funny you just posted MIT, Because I am using thier open courses on line for the video in math and Physics
Haha, that works, too! You'd probably like his teaching style. He is very helpful and has tons of videos. I always recommend the site.
thanks will check it out, hey you have a great night and if you need me to help me message me
you
Sounds like a plan! Have a good night!
you too.

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