a.galvan2
solve.
sqrt(x+5)1=sqrt(x)



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a.galvan2
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\[\sqrt{x+5}1=\sqrt{x}\]

pratu043
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\[\sqrt{x + 5}  1 = \sqrt{x}\]

pratu043
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Take 1 to the other side and square on both sides.

a.galvan2
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ok so i got:
\[x+5=x+2\sqrt{x}+1\]

pratu043
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dw:1345014199718:dw

a.galvan2
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then I subtract a x and the 1 from both sides?

pratu043
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yep, you were faster than me.
@TuringTest any ideas how to remove the square root?

a.galvan2
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to isolate the squareroot? this is where I get lost every time..

pratu043
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dw:1345014331464:dw

TuringTest
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no I was mistake
it goes away when you get rid of x and square both sides

pratu043
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ok, i got this.

TuringTest
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mistaken*

TuringTest
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yes you do :)

pratu043
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dw:1345014366077:dw
done

a.galvan2
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ok, then divide both sides by 2. then square both sides.
thank you!

pratu043
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welcome.

a.galvan2
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could one of you give me a different problem that is still similar math?

pratu043
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dw:1345014658648:dw
same format, different terms.

a.galvan2
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k. thank you. give me a minute to do it, then could you let me know if i did it right?

pratu043
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sure.

pratu043
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It will come as a negative fraction, don't bother simplifying.

pratu043
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Its ok if the answer looks too complicated, I made up the question on the spot.

a.galvan2
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i got 169/32=x

pratu043
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dw:1345015382310:dw
you made a mistake there.

a.galvan2
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i thought when you divide a fraction by another fraction you are really just multiplying it by the reciprocal.

a.galvan2
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ohh..... never mind... I get it 1/2 is the reciprocal of 2... duh.

pratu043
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right.

curiousshubham
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√(x+5)  1 = √x
√x + 1 = √(x+5)
by squaring both sides,
(√x + 1)² = [√(x + 5)]²
(√x)² + 2 * √x * 1 + 1² = x + 5
x + 2√x + 1 = x + 5
2√x = 5  1
√x = 4/2
x = 2²
x = 4