At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!

\[\sqrt{x+5}-1=\sqrt{x}\]

\[\sqrt{x + 5} - 1 = \sqrt{x}\]

Take 1 to the other side and square on both sides.

ok so i got:
\[x+5=x+2\sqrt{x}+1\]

|dw:1345014199718:dw|

then I subtract a x and the 1 from both sides?

yep, you were faster than me.
@TuringTest any ideas how to remove the square root?

to isolate the squareroot? this is where I get lost every time..

|dw:1345014331464:dw|

no I was mistake
it goes away when you get rid of x and square both sides

ok, i got this.

mistaken*

yes you do :)

|dw:1345014366077:dw|
done

ok, then divide both sides by 2. then square both sides.
thank you!

welcome.

could one of you give me a different problem that is still similar math?

|dw:1345014658648:dw|
same format, different terms.

k. thank you. give me a minute to do it, then could you let me know if i did it right?

sure.

It will come as a negative fraction, don't bother simplifying.

Its ok if the answer looks too complicated, I made up the question on the spot.

i got 169/32=x

|dw:1345015382310:dw|
you made a mistake there.

ohh..... never mind... I get it 1/2 is the reciprocal of 2... duh.

right.