## a.galvan2 Group Title solve. sqrt(x+5)-1=sqrt(x) one year ago one year ago

1. a.galvan2 Group Title

$\sqrt{x+5}-1=\sqrt{x}$

2. pratu043 Group Title

$\sqrt{x + 5} - 1 = \sqrt{x}$

3. pratu043 Group Title

Take 1 to the other side and square on both sides.

4. a.galvan2 Group Title

ok so i got: $x+5=x+2\sqrt{x}+1$

5. pratu043 Group Title

|dw:1345014199718:dw|

6. a.galvan2 Group Title

then I subtract a x and the 1 from both sides?

7. pratu043 Group Title

yep, you were faster than me. @TuringTest any ideas how to remove the square root?

8. a.galvan2 Group Title

to isolate the squareroot? this is where I get lost every time..

9. pratu043 Group Title

|dw:1345014331464:dw|

10. TuringTest Group Title

no I was mistake it goes away when you get rid of x and square both sides

11. pratu043 Group Title

ok, i got this.

12. TuringTest Group Title

mistaken*

13. TuringTest Group Title

yes you do :)

14. pratu043 Group Title

|dw:1345014366077:dw| done

15. a.galvan2 Group Title

ok, then divide both sides by 2. then square both sides. thank you!

16. pratu043 Group Title

welcome.

17. a.galvan2 Group Title

could one of you give me a different problem that is still similar math?

18. pratu043 Group Title

|dw:1345014658648:dw| same format, different terms.

19. a.galvan2 Group Title

k. thank you. give me a minute to do it, then could you let me know if i did it right?

20. pratu043 Group Title

sure.

21. pratu043 Group Title

It will come as a negative fraction, don't bother simplifying.

22. pratu043 Group Title

Its ok if the answer looks too complicated, I made up the question on the spot.

23. a.galvan2 Group Title

i got 169/32=x

24. pratu043 Group Title

|dw:1345015382310:dw| you made a mistake there.

25. a.galvan2 Group Title

i thought when you divide a fraction by another fraction you are really just multiplying it by the reciprocal.

26. a.galvan2 Group Title

ohh..... never mind... I get it 1/2 is the reciprocal of 2... duh.

27. pratu043 Group Title

right.

28. curiousshubham Group Title

√(x+5) - 1 = √x √x + 1 = √(x+5) by squaring both sides, (√x + 1)² = [√(x + 5)]² (√x)² + 2 * √x * 1 + 1² = x + 5 x + 2√x + 1 = x + 5 2√x = 5 - 1 √x = 4/2 x = 2² x = 4