## a.galvan2 Group Title solve. sqrt(x+5)-1=sqrt(x) 2 years ago 2 years ago

1. a.galvan2

$\sqrt{x+5}-1=\sqrt{x}$

2. pratu043

$\sqrt{x + 5} - 1 = \sqrt{x}$

3. pratu043

Take 1 to the other side and square on both sides.

4. a.galvan2

ok so i got: $x+5=x+2\sqrt{x}+1$

5. pratu043

|dw:1345014199718:dw|

6. a.galvan2

then I subtract a x and the 1 from both sides?

7. pratu043

yep, you were faster than me. @TuringTest any ideas how to remove the square root?

8. a.galvan2

to isolate the squareroot? this is where I get lost every time..

9. pratu043

|dw:1345014331464:dw|

10. TuringTest

no I was mistake it goes away when you get rid of x and square both sides

11. pratu043

ok, i got this.

12. TuringTest

mistaken*

13. TuringTest

yes you do :)

14. pratu043

|dw:1345014366077:dw| done

15. a.galvan2

ok, then divide both sides by 2. then square both sides. thank you!

16. pratu043

welcome.

17. a.galvan2

could one of you give me a different problem that is still similar math?

18. pratu043

|dw:1345014658648:dw| same format, different terms.

19. a.galvan2

k. thank you. give me a minute to do it, then could you let me know if i did it right?

20. pratu043

sure.

21. pratu043

It will come as a negative fraction, don't bother simplifying.

22. pratu043

Its ok if the answer looks too complicated, I made up the question on the spot.

23. a.galvan2

i got 169/32=x

24. pratu043

|dw:1345015382310:dw| you made a mistake there.

25. a.galvan2

i thought when you divide a fraction by another fraction you are really just multiplying it by the reciprocal.

26. a.galvan2

ohh..... never mind... I get it 1/2 is the reciprocal of 2... duh.

27. pratu043

right.

28. curiousshubham

√(x+5) - 1 = √x √x + 1 = √(x+5) by squaring both sides, (√x + 1)² = [√(x + 5)]² (√x)² + 2 * √x * 1 + 1² = x + 5 x + 2√x + 1 = x + 5 2√x = 5 - 1 √x = 4/2 x = 2² x = 4