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\[sint]_0^{\pi}+\int_0^0 udu+[-tcost+sint]_0^{\pi}\]

mukushla is not typing a replyâ€¦whats wrong with site...lol
let me check it

LOL...i think mukushla should type a reply

its allright but what is that middle integral !!?

u substitution
u =sint
du=cost dt
sin(pi)=0
sin(0)=0

almost done

0?

yes

cos Pi is -1 though

so negative pi should be the answer?

and cos (0) is 1 oh it cancels out!

no that still doesn't seem right... :(

i meant 0 for middle integral

answer is \(\pi\) ?

the first integral would be zero too
and then we have left
\[[-tcost+sint]_0^{\pi}=\pi\]

YAY!

We are DONE.....;-D