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how can I determine what x and y is from this: \[\hat r t=\]

Mathematics
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oh I wrote it wrong
\[\hat r t=\]
much better!

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Other answers:

got it
still something wrong !!
yeah still wrong \[\hat r t=\]
how about now?
\[t\vec r=\]makes more sense
but wait, brb
\[t\vec r=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]is this right is 1/2pit the argument of the trig function
?
and is t being multiplied by r on the left? this notation is confuzzling me
no it r(t), my bad
\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]correct?
yes
\[\vec r(t)=\langle x(t),y(t)\rangle\]so that implies that\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]leads to\[x(t)=t+\sin(\frac\pi2t)\]\[y(t)=t+\cos(\frac\pi2t)\]
so it is just a matter of identifying the components
yep. It makes sense now. I initially wrote it without putting a comma in, and i forgot a "t" somewhere which made it more confusing. But yeah that makes perfect sense.
no prob, this is not one of the harder parts of vector calculus fortunately :)
:P

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