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MathSofiya Group Title

how can I determine what x and y is from this: \[\hat r t=<t+sin\frac12 \pi t+cos \frac12 \pi t>\]

  • one year ago
  • one year ago

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  1. MathSofiya Group Title
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    oh I wrote it wrong

    • one year ago
  2. MathSofiya Group Title
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    \[\hat r t=<t+sin\frac12 \pi t,cos \frac12 \pi t>\]

    • one year ago
  3. MathSofiya Group Title
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    much better!

    • one year ago
  4. MathSofiya Group Title
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    got it

    • one year ago
  5. mukushla Group Title
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    still something wrong !!

    • one year ago
  6. MathSofiya Group Title
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    yeah still wrong \[\hat r t=<t+sin\frac12 \pi t,t+cos \frac12 \pi t>\]

    • one year ago
  7. MathSofiya Group Title
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    how about now?

    • one year ago
  8. TuringTest Group Title
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    \[t\vec r=<t+\sin\frac12 \pi t,t+\cos \frac12 \pi t>\]makes more sense

    • one year ago
  9. TuringTest Group Title
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    but wait, brb

    • one year ago
  10. TuringTest Group Title
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    \[t\vec r=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]is this right is 1/2pit the argument of the trig function

    • one year ago
  11. TuringTest Group Title
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    ?

    • one year ago
  12. TuringTest Group Title
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    and is t being multiplied by r on the left? this notation is confuzzling me

    • one year ago
  13. MathSofiya Group Title
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    no it r(t), my bad

    • one year ago
  14. TuringTest Group Title
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    \[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]correct?

    • one year ago
  15. MathSofiya Group Title
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    yes

    • one year ago
  16. TuringTest Group Title
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    \[\vec r(t)=\langle x(t),y(t)\rangle\]so that implies that\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]leads to\[x(t)=t+\sin(\frac\pi2t)\]\[y(t)=t+\cos(\frac\pi2t)\]

    • one year ago
  17. TuringTest Group Title
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    so it is just a matter of identifying the components

    • one year ago
  18. MathSofiya Group Title
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    yep. It makes sense now. I initially wrote it without putting a comma in, and i forgot a "t" somewhere which made it more confusing. But yeah that makes perfect sense.

    • one year ago
  19. TuringTest Group Title
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    no prob, this is not one of the harder parts of vector calculus fortunately :)

    • one year ago
  20. MathSofiya Group Title
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    :P

    • one year ago
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