anonymous
  • anonymous
how can I determine what x and y is from this: \[\hat r t=\]
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
katieb
  • katieb
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
oh I wrote it wrong
anonymous
  • anonymous
\[\hat r t=\]
anonymous
  • anonymous
much better!

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
got it
anonymous
  • anonymous
still something wrong !!
anonymous
  • anonymous
yeah still wrong \[\hat r t=\]
anonymous
  • anonymous
how about now?
TuringTest
  • TuringTest
\[t\vec r=\]makes more sense
TuringTest
  • TuringTest
but wait, brb
TuringTest
  • TuringTest
\[t\vec r=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]is this right is 1/2pit the argument of the trig function
TuringTest
  • TuringTest
?
TuringTest
  • TuringTest
and is t being multiplied by r on the left? this notation is confuzzling me
anonymous
  • anonymous
no it r(t), my bad
TuringTest
  • TuringTest
\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]correct?
anonymous
  • anonymous
yes
TuringTest
  • TuringTest
\[\vec r(t)=\langle x(t),y(t)\rangle\]so that implies that\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]leads to\[x(t)=t+\sin(\frac\pi2t)\]\[y(t)=t+\cos(\frac\pi2t)\]
TuringTest
  • TuringTest
so it is just a matter of identifying the components
anonymous
  • anonymous
yep. It makes sense now. I initially wrote it without putting a comma in, and i forgot a "t" somewhere which made it more confusing. But yeah that makes perfect sense.
TuringTest
  • TuringTest
no prob, this is not one of the harder parts of vector calculus fortunately :)
anonymous
  • anonymous
:P

Looking for something else?

Not the answer you are looking for? Search for more explanations.