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MathSofiya
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how can I determine what x and y is from this:
\[\hat r t=<t+sin\frac12 \pi t+cos \frac12 \pi t>\]
 2 years ago
 2 years ago
MathSofiya Group Title
how can I determine what x and y is from this: \[\hat r t=<t+sin\frac12 \pi t+cos \frac12 \pi t>\]
 2 years ago
 2 years ago

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MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
oh I wrote it wrong
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
\[\hat r t=<t+sin\frac12 \pi t,cos \frac12 \pi t>\]
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
much better!
 2 years ago

mukushla Group TitleBest ResponseYou've already chosen the best response.0
still something wrong !!
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
yeah still wrong \[\hat r t=<t+sin\frac12 \pi t,t+cos \frac12 \pi t>\]
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
how about now?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
\[t\vec r=<t+\sin\frac12 \pi t,t+\cos \frac12 \pi t>\]makes more sense
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
but wait, brb
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
\[t\vec r=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]is this right is 1/2pit the argument of the trig function
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
and is t being multiplied by r on the left? this notation is confuzzling me
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
no it r(t), my bad
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]correct?
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
\[\vec r(t)=\langle x(t),y(t)\rangle\]so that implies that\[\vec r(t)=\langle t+\sin(\frac\pi2 t),t+\cos(\frac\pi2t)\rangle\]leads to\[x(t)=t+\sin(\frac\pi2t)\]\[y(t)=t+\cos(\frac\pi2t)\]
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
so it is just a matter of identifying the components
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.1
yep. It makes sense now. I initially wrote it without putting a comma in, and i forgot a "t" somewhere which made it more confusing. But yeah that makes perfect sense.
 2 years ago

TuringTest Group TitleBest ResponseYou've already chosen the best response.3
no prob, this is not one of the harder parts of vector calculus fortunately :)
 2 years ago
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