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Solmyr

  • 2 years ago

am i doing these problems correctly? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1

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  1. Solmyr
    • 2 years ago
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    x – 3 > –9 +3 +3 x > -6

  2. Solmyr
    • 2 years ago
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    –2x + 1 ≤ –11 -1 -1 -2x ≤ -12

  3. Solmyr
    • 2 years ago
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    10 < –3x + 1 -1 -1 9 < -3x

  4. cwrw238
    • 2 years ago
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    thats fine as far as you've gone

  5. Solmyr
    • 2 years ago
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    i feel like i forgot somthing

  6. Tomas.A
    • 2 years ago
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    partially yes, but -2x ≤ -12 is not an answer you need to have just x how to remove that -2 from x? just divide by -2 both sides also don't forget when dividing multiplying by negative number this < becomes > and viceversa

  7. cwrw238
    • 2 years ago
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    well you need to finish the last two

  8. Solmyr
    • 2 years ago
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    oh ya i forgot to divide thank you

  9. Tomas.A
    • 2 years ago
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    show your answers when you done it

  10. Solmyr
    • 2 years ago
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    –2x + 1 ≤ –11 -1 -1 -2x ≤ -12 -2 -2 x≤6 10 < –3x + 1 -1 -1 9 < -3x -3 -3 -3<x

  11. Solmyr
    • 2 years ago
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    is that right?

  12. Tomas.A
    • 2 years ago
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    u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\) and \(-3>x\)

  13. Solmyr
    • 2 years ago
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    ok thank you

  14. Tomas.A
    • 2 years ago
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    also its nicer to write x<-3 than -3>x but both of them are correct answers

  15. Solmyr
    • 2 years ago
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    ok thank you

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