## Solmyr 3 years ago am i doing these problems correctly? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1

1. Solmyr

x – 3 > –9 +3 +3 x > -6

2. Solmyr

–2x + 1 ≤ –11 -1 -1 -2x ≤ -12

3. Solmyr

10 < –3x + 1 -1 -1 9 < -3x

4. cwrw238

thats fine as far as you've gone

5. Solmyr

i feel like i forgot somthing

6. Tomas.A

partially yes, but -2x ≤ -12 is not an answer you need to have just x how to remove that -2 from x? just divide by -2 both sides also don't forget when dividing multiplying by negative number this < becomes > and viceversa

7. cwrw238

well you need to finish the last two

8. Solmyr

oh ya i forgot to divide thank you

9. Tomas.A

10. Solmyr

–2x + 1 ≤ –11 -1 -1 -2x ≤ -12 -2 -2 x≤6 10 < –3x + 1 -1 -1 9 < -3x -3 -3 -3<x

11. Solmyr

is that right?

12. Tomas.A

u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\) and \(-3>x\)

13. Solmyr

ok thank you

14. Tomas.A

also its nicer to write x<-3 than -3>x but both of them are correct answers

15. Solmyr

ok thank you