Solmyr
am i doing these problems correctly?
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1
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Solmyr
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x – 3 > –9
+3 +3
x > -6
Solmyr
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–2x + 1 ≤ –11
-1 -1
-2x ≤ -12
Solmyr
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10 < –3x + 1
-1 -1
9 < -3x
cwrw238
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thats fine as far as you've gone
Solmyr
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i feel like i forgot somthing
Tomas.A
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partially yes, but
-2x ≤ -12 is not an answer you need to have just x
how to remove that -2 from x? just divide by -2 both sides
also don't forget when dividing multiplying by negative number this < becomes > and viceversa
cwrw238
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well you need to finish the last two
Solmyr
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oh ya i forgot to divide thank you
Tomas.A
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show your answers when you done it
Solmyr
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–2x + 1 ≤ –11
-1 -1
-2x ≤ -12
-2 -2
x≤6
10 < –3x + 1
-1 -1
9 < -3x
-3 -3
-3<x
Solmyr
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is that right?
Tomas.A
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u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\)
and \(-3>x\)
Solmyr
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ok thank you
Tomas.A
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also its nicer to write x<-3 than -3>x but both of them are correct answers
Solmyr
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ok thank you