anonymous
  • anonymous
am i doing these problems correctly? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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schrodinger
  • schrodinger
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anonymous
  • anonymous
x – 3 > –9 +3 +3 x > -6
anonymous
  • anonymous
–2x + 1 ≤ –11 -1 -1 -2x ≤ -12
anonymous
  • anonymous
10 < –3x + 1 -1 -1 9 < -3x

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cwrw238
  • cwrw238
thats fine as far as you've gone
anonymous
  • anonymous
i feel like i forgot somthing
anonymous
  • anonymous
partially yes, but -2x ≤ -12 is not an answer you need to have just x how to remove that -2 from x? just divide by -2 both sides also don't forget when dividing multiplying by negative number this < becomes > and viceversa
cwrw238
  • cwrw238
well you need to finish the last two
anonymous
  • anonymous
oh ya i forgot to divide thank you
anonymous
  • anonymous
show your answers when you done it
anonymous
  • anonymous
–2x + 1 ≤ –11 -1 -1 -2x ≤ -12 -2 -2 x≤6 10 < –3x + 1 -1 -1 9 < -3x -3 -3 -3
anonymous
  • anonymous
is that right?
anonymous
  • anonymous
u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\) and \(-3>x\)
anonymous
  • anonymous
ok thank you
anonymous
  • anonymous
also its nicer to write x<-3 than -3>x but both of them are correct answers
anonymous
  • anonymous
ok thank you

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