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 2 years ago
am i doing these problems correctly?
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1
 2 years ago
am i doing these problems correctly? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1

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Solmyr
 2 years ago
Best ResponseYou've already chosen the best response.0–2x + 1 ≤ –11 1 1 2x ≤ 12

Solmyr
 2 years ago
Best ResponseYou've already chosen the best response.010 < –3x + 1 1 1 9 < 3x

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0thats fine as far as you've gone

Solmyr
 2 years ago
Best ResponseYou've already chosen the best response.0i feel like i forgot somthing

Tomas.A
 2 years ago
Best ResponseYou've already chosen the best response.2partially yes, but 2x ≤ 12 is not an answer you need to have just x how to remove that 2 from x? just divide by 2 both sides also don't forget when dividing multiplying by negative number this < becomes > and viceversa

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.0well you need to finish the last two

Solmyr
 2 years ago
Best ResponseYou've already chosen the best response.0oh ya i forgot to divide thank you

Tomas.A
 2 years ago
Best ResponseYou've already chosen the best response.2show your answers when you done it

Solmyr
 2 years ago
Best ResponseYou've already chosen the best response.0–2x + 1 ≤ –11 1 1 2x ≤ 12 2 2 x≤6 10 < –3x + 1 1 1 9 < 3x 3 3 3<x

Tomas.A
 2 years ago
Best ResponseYou've already chosen the best response.2u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\) and \(3>x\)

Tomas.A
 2 years ago
Best ResponseYou've already chosen the best response.2also its nicer to write x<3 than 3>x but both of them are correct answers
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