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- anonymous

am i doing these problems correctly?
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1

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- anonymous

am i doing these problems correctly?
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1

- katieb

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- anonymous

x – 3 > –9
+3 +3
x > -6

- anonymous

–2x + 1 ≤ –11
-1 -1
-2x ≤ -12

- anonymous

10 < –3x + 1
-1 -1
9 < -3x

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- cwrw238

thats fine as far as you've gone

- anonymous

i feel like i forgot somthing

- anonymous

partially yes, but
-2x ≤ -12 is not an answer you need to have just x
how to remove that -2 from x? just divide by -2 both sides
also don't forget when dividing multiplying by negative number this < becomes > and viceversa

- cwrw238

well you need to finish the last two

- anonymous

oh ya i forgot to divide thank you

- anonymous

show your answers when you done it

- anonymous

–2x + 1 ≤ –11
-1 -1
-2x ≤ -12
-2 -2
x≤6
10 < –3x + 1
-1 -1
9 < -3x
-3 -3
-3

- anonymous

is that right?

- anonymous

u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\)
and \(-3>x\)

- anonymous

ok thank you

- anonymous

also its nicer to write x<-3 than -3>x but both of them are correct answers

- anonymous

ok thank you

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