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am i doing these problems correctly?
1. x – 3 > –9
2. –2x + 1 ≤ –11
3. 10 < –3x + 1
 one year ago
 one year ago
am i doing these problems correctly? 1. x – 3 > –9 2. –2x + 1 ≤ –11 3. 10 < –3x + 1
 one year ago
 one year ago

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SolmyrBest ResponseYou've already chosen the best response.0
x – 3 > –9 +3 +3 x > 6
 one year ago

SolmyrBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11 1 1 2x ≤ 12
 one year ago

SolmyrBest ResponseYou've already chosen the best response.0
10 < –3x + 1 1 1 9 < 3x
 one year ago

cwrw238Best ResponseYou've already chosen the best response.0
thats fine as far as you've gone
 one year ago

SolmyrBest ResponseYou've already chosen the best response.0
i feel like i forgot somthing
 one year ago

Tomas.ABest ResponseYou've already chosen the best response.2
partially yes, but 2x ≤ 12 is not an answer you need to have just x how to remove that 2 from x? just divide by 2 both sides also don't forget when dividing multiplying by negative number this < becomes > and viceversa
 one year ago

cwrw238Best ResponseYou've already chosen the best response.0
well you need to finish the last two
 one year ago

SolmyrBest ResponseYou've already chosen the best response.0
oh ya i forgot to divide thank you
 one year ago

Tomas.ABest ResponseYou've already chosen the best response.2
show your answers when you done it
 one year ago

SolmyrBest ResponseYou've already chosen the best response.0
–2x + 1 ≤ –11 1 1 2x ≤ 12 2 2 x≤6 10 < –3x + 1 1 1 9 < 3x 3 3 3<x
 one year ago

Tomas.ABest ResponseYou've already chosen the best response.2
u forgot that u need to change direction of sign when multiplying or dividing as i said so it should be \(x\geq6\) and \(3>x\)
 one year ago

Tomas.ABest ResponseYou've already chosen the best response.2
also its nicer to write x<3 than 3>x but both of them are correct answers
 one year ago
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