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joyce153 Group Title

Solve for x: 9^(3x)=81^(x-4)

  • 2 years ago
  • 2 years ago

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  1. Tomas.A Group Title
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    would you know how to solve \(5^{2x}=5^{x+1}\)?

    • 2 years ago
  2. panlac01 Group Title
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    same link from earlier, joyce. exponents are covered in that chapter :)

    • 2 years ago
  3. dpaInc Group Title
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    change that 81 as some power of 9 so your equation will be: \[\large 9^{3x}={(9^2)}^{(x-4)} \]

    • 2 years ago
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