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joyce153

  • 3 years ago

Solve for x: 9^(3x)=81^(x-4)

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  1. Tomas.A
    • 3 years ago
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    would you know how to solve \(5^{2x}=5^{x+1}\)?

  2. panlac01
    • 3 years ago
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    same link from earlier, joyce. exponents are covered in that chapter :)

  3. dpaInc
    • 3 years ago
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    change that 81 as some power of 9 so your equation will be: \[\large 9^{3x}={(9^2)}^{(x-4)} \]

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