anonymous
  • anonymous
Solve for x: 9^(3x)=81^(x-4)
Mathematics
katieb
  • katieb
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anonymous
  • anonymous
would you know how to solve \(5^{2x}=5^{x+1}\)?
anonymous
  • anonymous
same link from earlier, joyce. exponents are covered in that chapter :)
anonymous
  • anonymous
change that 81 as some power of 9 so your equation will be: \[\large 9^{3x}={(9^2)}^{(x-4)} \]

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