Here's the question you clicked on:

55 members online
  • 0 replying
  • 0 viewing

dudeperuvian

  • 3 years ago

if y=(√3x^2-4), then dy = a. 6x(√3x^2-4)dx b. (3x)/(√3x^2-4)dx c. (6x)/(√3x^2-4) d. 2(√3x^2-4)/(3x)dx there is an E choice but it cut off, is it E??...

  • This Question is Closed
  1. vf321
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    Dude, we're not here to do problems for you. I'm here to help work through them. Your question should be: Help me find the differential dy given \[y=\sqrt x^2-4\]

  2. vf321
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    So do you need help differentiating or not? Also, your function's not clear. Is this it? \[y=\sqrt{3x^2-4}\]

  3. dudeperuvian
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 0

    yes vf321, sorry but \[y=\sqrt{3x^2-4}\] is right

  4. vf321
    • 3 years ago
    Best Response
    You've already chosen the best response.
    Medals 1

    When dealing with chain rule, it often helps to make your own functions up. Let: \[f(x) = \sqrt x\]\[g(x)=3x^2-4\]Then,\[y=f(g(x))\]Well let's take d/dx of both sides.\[\frac{dy}{dx}=f'(g(x))g'(x)\]Now, all you have to do is multiply by dx on both sides and replace all the f's and g's with their actual values. \[\frac{dy}{dx}dx=f'(g(x))g'(x)dx\]\[dy = f'(g(x))g'(x)dx\]

  5. Not the answer you are looking for?
    Search for more explanations.

    • Attachments:

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy