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dudeperuvian
 3 years ago
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d.
2(√3x^24)/(3x)dx
there is an E choice but it cut off, is it E??...
dudeperuvian
 3 years ago
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d. 2(√3x^24)/(3x)dx there is an E choice but it cut off, is it E??...

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vf321
 3 years ago
Best ResponseYou've already chosen the best response.1Dude, we're not here to do problems for you. I'm here to help work through them. Your question should be: Help me find the differential dy given \[y=\sqrt x^24\]

vf321
 3 years ago
Best ResponseYou've already chosen the best response.1So do you need help differentiating or not? Also, your function's not clear. Is this it? \[y=\sqrt{3x^24}\]

dudeperuvian
 3 years ago
Best ResponseYou've already chosen the best response.0yes vf321, sorry but \[y=\sqrt{3x^24}\] is right

vf321
 3 years ago
Best ResponseYou've already chosen the best response.1When dealing with chain rule, it often helps to make your own functions up. Let: \[f(x) = \sqrt x\]\[g(x)=3x^24\]Then,\[y=f(g(x))\]Well let's take d/dx of both sides.\[\frac{dy}{dx}=f'(g(x))g'(x)\]Now, all you have to do is multiply by dx on both sides and replace all the f's and g's with their actual values. \[\frac{dy}{dx}dx=f'(g(x))g'(x)dx\]\[dy = f'(g(x))g'(x)dx\]
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