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dudeperuvian
Group Title
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d.
2(√3x^24)/(3x)dx
there is an E choice but it cut off, is it E??...
 2 years ago
 2 years ago
dudeperuvian Group Title
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d. 2(√3x^24)/(3x)dx there is an E choice but it cut off, is it E??...
 2 years ago
 2 years ago

This Question is Closed

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Dude, we're not here to do problems for you. I'm here to help work through them. Your question should be: Help me find the differential dy given \[y=\sqrt x^24\]
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
So do you need help differentiating or not? Also, your function's not clear. Is this it? \[y=\sqrt{3x^24}\]
 2 years ago

dudeperuvian Group TitleBest ResponseYou've already chosen the best response.0
yes vf321, sorry but \[y=\sqrt{3x^24}\] is right
 2 years ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
When dealing with chain rule, it often helps to make your own functions up. Let: \[f(x) = \sqrt x\]\[g(x)=3x^24\]Then,\[y=f(g(x))\]Well let's take d/dx of both sides.\[\frac{dy}{dx}=f'(g(x))g'(x)\]Now, all you have to do is multiply by dx on both sides and replace all the f's and g's with their actual values. \[\frac{dy}{dx}dx=f'(g(x))g'(x)dx\]\[dy = f'(g(x))g'(x)dx\]
 2 years ago
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