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dudeperuvian
Group Title
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d.
2(√3x^24)/(3x)dx
there is an E choice but it cut off, is it E??...
 one year ago
 one year ago
dudeperuvian Group Title
if y=(√3x^24), then dy = a. 6x(√3x^24)dx b. (3x)/(√3x^24)dx c. (6x)/(√3x^24) d. 2(√3x^24)/(3x)dx there is an E choice but it cut off, is it E??...
 one year ago
 one year ago

This Question is Closed

vf321 Group TitleBest ResponseYou've already chosen the best response.1
Dude, we're not here to do problems for you. I'm here to help work through them. Your question should be: Help me find the differential dy given \[y=\sqrt x^24\]
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
So do you need help differentiating or not? Also, your function's not clear. Is this it? \[y=\sqrt{3x^24}\]
 one year ago

dudeperuvian Group TitleBest ResponseYou've already chosen the best response.0
yes vf321, sorry but \[y=\sqrt{3x^24}\] is right
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.1
When dealing with chain rule, it often helps to make your own functions up. Let: \[f(x) = \sqrt x\]\[g(x)=3x^24\]Then,\[y=f(g(x))\]Well let's take d/dx of both sides.\[\frac{dy}{dx}=f'(g(x))g'(x)\]Now, all you have to do is multiply by dx on both sides and replace all the f's and g's with their actual values. \[\frac{dy}{dx}dx=f'(g(x))g'(x)dx\]\[dy = f'(g(x))g'(x)dx\]
 one year ago
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