## anonymous 3 years ago if y=(√3x^2-4), then dy = a. 6x(√3x^2-4)dx b. (3x)/(√3x^2-4)dx c. (6x)/(√3x^2-4) d. 2(√3x^2-4)/(3x)dx there is an E choice but it cut off, is it E??...

1. anonymous

Dude, we're not here to do problems for you. I'm here to help work through them. Your question should be: Help me find the differential dy given $y=\sqrt x^2-4$

2. anonymous

So do you need help differentiating or not? Also, your function's not clear. Is this it? $y=\sqrt{3x^2-4}$

3. anonymous

yes vf321, sorry but $y=\sqrt{3x^2-4}$ is right

4. anonymous

When dealing with chain rule, it often helps to make your own functions up. Let: $f(x) = \sqrt x$$g(x)=3x^2-4$Then,$y=f(g(x))$Well let's take d/dx of both sides.$\frac{dy}{dx}=f'(g(x))g'(x)$Now, all you have to do is multiply by dx on both sides and replace all the f's and g's with their actual values. $\frac{dy}{dx}dx=f'(g(x))g'(x)dx$$dy = f'(g(x))g'(x)dx$