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sara1234
 3 years ago
Determine the domain of the function.
f(x) is equal to the square root of two minus x.
x ≤ 2
All real numbers
x > 2
All real numbers except 2
sara1234
 3 years ago
Determine the domain of the function. f(x) is equal to the square root of two minus x. x ≤ 2 All real numbers x > 2 All real numbers except 2

This Question is Closed

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2Hint: You cannot take the square root of a negative number (and get some real number)

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2So the radicand (the stuff inside the square root) can't be negative

sara1234
 3 years ago
Best ResponseYou've already chosen the best response.1can you please teach me how to do this step by step PLEASE

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2Similar example: Find the domain of \[\Large g(x) = \sqrt{x+3}\] You can't take the square root of a negative number, so the radicand must be either 0 or positive. So... \[\Large x+3 \ge 0\] \[\Large x+33 \ge 03\] \[\Large x \ge 3\] is the domain

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2I'm not sure what you mean

sara1234
 3 years ago
Best ResponseYou've already chosen the best response.1you said you can't take the square root of a negative number

jim_thompson5910
 3 years ago
Best ResponseYou've already chosen the best response.2yes exactly, so whatever number that is in the square root is either a) zero or b) positive

nickhouraney
 3 years ago
Best ResponseYou've already chosen the best response.0if your finding the domain of a square root your rules are that the number cant be negative. if you were taking the domain of a fraction the rules would be you cant have a zero on the denominator

ganeshie8
 3 years ago
Best ResponseYou've already chosen the best response.0correct! good work !!

sara1234
 3 years ago
Best ResponseYou've already chosen the best response.1i missed you @ganeshie8
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