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sara1234 Group Title

Determine the domain of the function. f(x) is equal to the square root of two minus x. x ≤ 2 All real numbers x > 2 All real numbers except 2

  • 2 years ago
  • 2 years ago

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  1. sara1234 Group Title
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    \[f(x)=\sqrt{2-x}\]

    • 2 years ago
  2. jim_thompson5910 Group Title
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    Hint: You cannot take the square root of a negative number (and get some real number)

    • 2 years ago
  3. jim_thompson5910 Group Title
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    So the radicand (the stuff inside the square root) can't be negative

    • 2 years ago
  4. sara1234 Group Title
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    can you please teach me how to do this step by step PLEASE

    • 2 years ago
  5. jim_thompson5910 Group Title
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    Similar example: Find the domain of \[\Large g(x) = \sqrt{x+3}\] You can't take the square root of a negative number, so the radicand must be either 0 or positive. So... \[\Large x+3 \ge 0\] \[\Large x+3-3 \ge 0-3\] \[\Large x \ge -3\] is the domain

    • 2 years ago
  6. sara1234 Group Title
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    but its positive ??

    • 2 years ago
  7. jim_thompson5910 Group Title
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    I'm not sure what you mean

    • 2 years ago
  8. sara1234 Group Title
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    you said you can't take the square root of a negative number

    • 2 years ago
  9. jim_thompson5910 Group Title
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    yes exactly, so whatever number that is in the square root is either a) zero or b) positive

    • 2 years ago
  10. nickhouraney Group Title
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    if your finding the domain of a square root your rules are that the number cant be negative. if you were taking the domain of a fraction the rules would be you cant have a zero on the denominator

    • 2 years ago
  11. sara1234 Group Title
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    is the answer x ≤ 2

    • 2 years ago
  12. ganeshie8 Group Title
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    correct! good work !!

    • 2 years ago
  13. sara1234 Group Title
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    i missed you @ganeshie8

    • 2 years ago
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