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factor it... treat it as a quadratic...

Lets just change the name of tanx.. lets call z.

Factor out tan(x) first..

\[z^2 - z = 0 \] can you do that one?

\[\tan(x)(\tan(x) - 1) = 0\]
\[\tan(x) = 0\]
And:
\[\tan(x) - 1 = 0\]
Now try to find x..

1/4?

x = arc tan(1)
x=??

pi/4

http://upload.wikimedia.org/wikipedia/commons/4/4c/Unit_circle_angles_color.svg

tan(x) = 0
Can you tell for what value of x tan(x) is 0 ??

:/ uhhh

huh...

tan(x) = 0
can't you find x from it??
\[x = \tan^{-1}(0)\]

I replied to helpingtutors, pi/4?

That is not right for this..

That is right for \(tan(x) = 1\)

Can you find the value of \(tan^{-1}(0)\) ??

Yes..

One value you are getting 0 and other pi/4
What could be the answer can you tell ??

By looking at the answer choices..

C.? Or can you reduce?

reduce?

Are you sure with C or not ??
Tell me this thing..

Yes

Then you are right..

tangent equals zero in two points in the unit circle

C. Thank you all for your help :) I appreciate it very much

Wait..

:/

Go with @nickhouraney

So not c.?

No..
My mistake there...

whats points in the unit circle will tangent equal zero

if you answer this ^ you will have your answer

Basically :
\(tan(x) = 0\)
\[\implies x = n \pi, n \in \mathbb{Z}\]

n is integer here..
Put n = 0 and 1 to find your answer..

b.?

Yep..

Ahhhh I see. Thanks guys

Welcome dear..