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Please help! Having trouble with this Precalc/Trig problem :/ Click attached

Mathematics
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1 Attachment
factor it... treat it as a quadratic...
Lets just change the name of tanx.. lets call z.

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Other answers:

Factor out tan(x) first..
\[z^2 - z = 0 \] can you do that one?
\[\tan(x)(\tan(x) - 1) = 0\] \[\tan(x) = 0\] And: \[\tan(x) - 1 = 0\] Now try to find x..
1/4?
?
x = arc tan(1) x=??
pi/4
http://upload.wikimedia.org/wikipedia/commons/4/4c/Unit_circle_angles_color.svg
tan(x) = 0 Can you tell for what value of x tan(x) is 0 ??
:/ uhhh
huh...
tan(x) = 0 can't you find x from it?? \[x = \tan^{-1}(0)\]
I replied to helpingtutors, pi/4?
That is not right for this..
That is right for \(tan(x) = 1\)
Can you find the value of \(tan^{-1}(0)\) ??
0
Yes..
One value you are getting 0 and other pi/4 What could be the answer can you tell ??
By looking at the answer choices..
C.? Or can you reduce?
reduce?
Are you sure with C or not ?? Tell me this thing..
Yes
Then you are right..
tangent equals zero in two points in the unit circle
C. Thank you all for your help :) I appreciate it very much
Wait..
:/
So not c.?
No.. My mistake there...
whats points in the unit circle will tangent equal zero
if you answer this ^ you will have your answer
Basically : \(tan(x) = 0\) \[\implies x = n \pi, n \in \mathbb{Z}\]
n is integer here.. Put n = 0 and 1 to find your answer..
b.?
Yep..
Ahhhh I see. Thanks guys
Welcome dear..

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