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same property means?

both triangles should have rational sides.

lol...not that easy

I think it will be enough to show just one side Am or MC rational

yeah..

beause if one is rational than the other must be rational

hmm..

sorry,,tanA=BC/Ab ,,but still rational..

ABC is right triangle !!?
work on
\[\sqrt{AB^2-MB^2}+\sqrt{BC^2-MB^2}=AM+MC\]

i thought its not right

hmm,,well,,how will sum of sides help ?

sorry that will not help..

AM^2 and MC^2 will be rational

right?

right

yep..thats where even i was wondering

this ques is a subpart of my previous ques,,do both have any relation ?

how ?

i mean ABC is a right triangle?

Dont think so

aha...thats what i had assumed!! so its not a right triangle!! hmm..

sauravshakya mentiond a good point
\[(AM+MC)^2=AC^2=AM^2+2AM.MC+MC^2\]so \(AM.MC\) is rational

YEP

well why were AM^2 and MC^2 rational ?

Take right triangle AMB and triangle BMC

ohh leave it
got it..

has to be an other way around..

yeah i was thinkin of that

hmm..

guys i gotta go...but i love to know what is the answer

hasn't this been solved yet?

its a diff ques..

i lost track of it ... it's fuzzy ... well what's the Q?

|dw:1345132117021:dw|if ABC has rational sides,
we have to show AMB and MBC also has rational sides.

@experimentX thats the question

typo:- Let's assume both to be irrational,

here is my proof|dw:1345140385316:dw|

lol ... your method is more obvious!!

aha..i see and understand both methods!
thanks again @mukushla and @experimentX