Here's the question you clicked on:
MIMI23
PLEASE HELP ME!The sail of a boat is in the shape of a right triangle, as shown below. Which expression shows the length, in meters, of the side adjacent to the 50 degree angle?
6 sin 50 6 cot 50 6/sec50 6/cot50
Is anyone going to help me ?
Are you familiar with SOH CAH TOA? SOH - opposite / hypotenuse CAH - adjacent / hypotenuse TOA - opposite / adjacent
You are given the angle, 50 degrees, and the length of the opposite side from the angle, which is 6m
Therefore, what trigonometric relation do you think you should work with, given that you want to find the length of the adjacent side for the angle
Which two sides do you have work with relative to the angle 50 degrees?
All right, let's figure it out. You have 3 sides, can you identify the hypotenuse in the picture?
You know that it is a right triangle, because there is a 90 degree angle at the bottom left of the triangle
Cool, which is which side? The left side, the bottom side, or the right side?
In a right triangle, 90 is the large possible angle, and in triangles, the largest side is opposite the largest angle
The left is the side that is 6m, that is the one you mean?
Cool, from the picture I drew, you're saying 'CB' is the hypotensue?
Right on, that's it! So in the picture of the sail, the hypotenuse is the right side, just like in the drawing
Now, can you tell me what the functions of angle B are in the drawing, use the line segments like you just did to identify the hypotenuse. sin(b) = ? cos(b) = ? tan(b) = ?