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mariapernez11

  • 2 years ago

find the measure of each of the angles of a regular 8-sided polygon. The measure of each of the angles of a regular 8-sided polygon is?

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  1. sasogeek
    • 2 years ago
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    hi

  2. sasogeek
    • 2 years ago
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    umm do you have an idea what you're supposed to do?

  3. mariapernez11
    • 2 years ago
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    no I don't could u show me an example. I have two more of these two do

  4. sasogeek
    • 2 years ago
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    ok so let's see if you get this. if you can find the total sum of all the angles and divide it by the number of angles, you can get the value of one of the angles... makes sense?

  5. mariapernez11
    • 2 years ago
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    yes it makes sense

  6. sasogeek
    • 2 years ago
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    do you know how to find the sum of all the angles of a polygon though?

  7. mariapernez11
    • 2 years ago
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    no

  8. sasogeek
    • 2 years ago
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    there's a formula for it. Sum = (n-2)*180 where n is the number of sides of the polygon, in this case 8.. so let's do the first part. find the sum of the angles and tell me what you got :)

  9. mariapernez11
    • 2 years ago
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    ok

  10. mariapernez11
    • 2 years ago
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    1,080

  11. sasogeek
    • 2 years ago
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    well done :) now how many angles does an 8 sided polygon have...?

  12. mariapernez11
    • 2 years ago
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    5

  13. sasogeek
    • 2 years ago
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    let's find out

  14. sasogeek
    • 2 years ago
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    |dw:1345169715398:dw| \(\huge 8\ sides \ 8\ angles \)

  15. mariapernez11
    • 2 years ago
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    I see what I done wrong. thanks for showing me. I have one more problem if you can show me how to do it. It has to do finding coordinates.

  16. sasogeek
    • 2 years ago
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    what did u get as ur answer for this one?

  17. mariapernez11
    • 2 years ago
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    135

  18. sasogeek
    • 2 years ago
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    well done :) i hope you can do the rest now...

  19. mariapernez11
    • 2 years ago
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    P(0,0)>P_____ Q(-1,1)>Q_____ R(-9,-3)>R_____ S(7,14)>S_____ T(r,s)>T____

  20. sasogeek
    • 2 years ago
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    if you have another question, please post it as a new question :) on the left side x

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