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ashna

mole concept !

  • one year ago
  • one year ago

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  1. ashna
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    @waterineyes back here :)

    • one year ago
  2. waterineyes
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    Write your question here..

    • one year ago
  3. ashna
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    yea .. okay !

    • one year ago
  4. ashna
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    Calculate the mass of the following : (a) 0.5 mole of CO2. (b) 6.02 * 10^21 molecules of O2. (c) 1 * 10^23 molecules of H2S. (d) 56.8 L of SO2. (e) 1.5 mole of H2SO4.

    • one year ago
  5. waterineyes
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    I had said to write question here not questions here .. Ha ha ha.. Kidding..

    • one year ago
  6. ashna
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    i don't understand .. what did you want me to do actually ?

    • one year ago
  7. waterineyes
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    question means one question. questions means more than one questions.. Leave it.

    • one year ago
  8. ashna
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    oh i din see the < S > !

    • one year ago
  9. ashna
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    its one question my teacher gave !

    • one year ago
  10. ashna
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    there are many questions like this .. and water will solve everything :p

    • one year ago
  11. ashna
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    i hope so !

    • one year ago
  12. waterineyes
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    Ha ha ha..

    • one year ago
  13. ashna
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    :)

    • one year ago
  14. ashna
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    so you know this ?

    • one year ago
  15. waterineyes
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    Yes...

    • one year ago
  16. ashna
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    so teach !

    • one year ago
  17. waterineyes
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    For fist part: Find the molecular mass of \(CO_2\)..

    • one year ago
  18. waterineyes
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    *first..

    • one year ago
  19. ashna
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    molecular mass , mass and molar mass excluding the ( g ) all the same ?

    • one year ago
  20. waterineyes
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    I will say not to go this way..

    • one year ago
  21. ashna
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    then ?

    • one year ago
  22. waterineyes
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    See now you have studied What is Molar Mass.. Molar mass is mass of 1 mole of any substance. If that substance is CO2 then: Molar Mass is mass of 1 mole of CO2 So here basically you have to find Molar Mass.. For getting molar mass you will find the molecular mass of CO2 first same as you did for NaCl..

    • one year ago
  23. ashna
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    yeah okay .. so in the question we are asked to find the mass right ?

    • one year ago
  24. waterineyes
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    For atoms: we have atomic mass. For molecules we have molecular mass..

    • one year ago
  25. ashna
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    okay !

    • one year ago
  26. waterineyes
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    Yes.. Molar mass is nothing but mass only. Molar Mass is "Mass" of 1 mole of a substance in grams..

    • one year ago
  27. ashna
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    okay :)

    • one year ago
  28. ashna
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    so how to do (a) ?

    • one year ago
  29. ashna
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    mass of CO2 is 44 g ?

    • one year ago
  30. waterineyes
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    • one year ago
  31. waterineyes
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    According to the definition of molar mass: Molar mass is mass of 1 mole right ??

    • one year ago
  32. ashna
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    yeah !

    • one year ago
  33. waterineyes
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    But you have to find for 0.5 mole.. This you got mass for 1 mole.. can you find? for 1 mole it is 44g for 0.5 or half it will be ??

    • one year ago
  34. ashna
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    0.5 * 44 / 1 ?

    • one year ago
  35. ashna
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    right ?

    • one year ago
  36. waterineyes
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    Yep..

    • one year ago
  37. ashna
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    okay :)

    • one year ago
  38. waterineyes
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    Think logically also.. For 1 it is 44g for half that is 0.5 is nothing but half of 1: for 0.5 it will be 44/2 = 22g. Getting ??

    • one year ago
  39. ashna
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    partially !

    • one year ago
  40. ashna
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    yea yea .. on second thinking i understood !

    • one year ago
  41. ashna
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    i forgot half of 1 is 0.5 !

    • one year ago
  42. waterineyes
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    0.5 is 1/2 no ??

    • one year ago
  43. ashna
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    yea i got it !

    • one year ago
  44. waterineyes
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    This solves first one.. Getting ??

    • one year ago
  45. ashna
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    dont laugh !

    • one year ago
  46. ashna
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    yeah :)

    • one year ago
  47. waterineyes
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    Ha ha ha ha.. Not I am not.. Ha ha ha..

    • one year ago
  48. ashna
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    lol yu are !

    • one year ago
  49. ashna
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    okay .. best medicine .. so laugh !

    • one year ago
  50. waterineyes
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    e> part is same.. Can you do that ??

    • one year ago
  51. ashna
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    let me try !

    • one year ago
  52. waterineyes
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    Take your time..

    • one year ago
  53. ashna
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    mass of 6.023 * 10^23 molecules of O2 = 32 mass of 6.02 * 10^21 molecules of O2 = x cross multiply ?

    • one year ago
  54. waterineyes
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    Go for last part.. e) part

    • one year ago
  55. ashna
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    okay !

    • one year ago
  56. waterineyes
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    This I tell you later on..

    • one year ago
  57. ashna
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    okay !

    • one year ago
  58. waterineyes
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    e part is same as a part. Just try that so that you will completely get it..

    • one year ago
  59. ashna
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    mass of 1 mole of CO2 = 44 g mass of 1.5 mole of CO2 = ? 44 * 1.5 / 1 = 66 g

    • one year ago
  60. ashna
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    @waterineyes

    • one year ago
  61. ashna
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    wrong ?

    • one year ago
  62. waterineyes
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    Yes concept is right..

    • one year ago
  63. waterineyes
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    Dear there is H2SO4 not CO2...

    • one year ago
  64. ashna
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    oh .. sorry !

    • one year ago
  65. ashna
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    okay let me do with H2SO4

    • one year ago
  66. waterineyes
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    Do the same for H2SO4..

    • one year ago
  67. waterineyes
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    I am in no hurry take your time..

    • one year ago
  68. waterineyes
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    Atomic Mass of H is : 1 Atomic Mass of S is : 28 Atomic Mass of O is : 16..

    • one year ago
  69. ashna
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    mass of 1 mole of H2SO4 = 98 g mass of 1.5 mole of H2SO4 = x = 98 * 1.5 / 1 = 147 g

    • one year ago
  70. ashna
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    atomic mass of s = 32 or 28 ?

    • one year ago
  71. ashna
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    @waterineyes there ?

    • one year ago
  72. waterineyes
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    I think you are right..

    • one year ago
  73. waterineyes
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    My mistake : Atomic Mass of Sulphur is 32..

    • one year ago
  74. ashna
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    okay !

    • one year ago
  75. waterineyes
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    Yes you have done that correctly: 98 + 49 = 147 g...

    • one year ago
  76. ashna
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    okay .. :)

    • one year ago
  77. waterineyes
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    Now we will do second part b)..

    • one year ago
  78. ashna
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    okay !

    • one year ago
  79. ashna
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    but i did that before right ?

    • one year ago
  80. ashna
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    is that wrong ?

    • one year ago
  81. waterineyes
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    Yes somewhat wrong..

    • one year ago
  82. ashna
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    okay .. so teach me :)

    • one year ago
  83. waterineyes
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    Sere have you remembered this: \[1 Mole (oxygen) = 6.023 \times 10^{23} \; Oxygen \; \; Molecules\]

    • one year ago
  84. ashna
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    okay

    • one year ago
  85. ashna
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    then .. how to do ? are you trying ?

    • one year ago
  86. waterineyes
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    Oh really very sorry.. You were doing it right

    • one year ago
  87. ashna
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    really ?

    • one year ago
  88. waterineyes
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    \[6.023 \times 10^{23} \implies 32g\] \[1 \implies \frac{32}{6.023 \times 10^{23}}\] \[6.023 \times 10^{21} \implies \frac{32}{6.023 \times 10^{232}} \times 6.023 \times 10^{21} = ??\]

    • one year ago
  89. waterineyes
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    Oh sorry there is mistake in denominator there power of 10 is 23 and not 232..

    • one year ago
  90. ashna
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    okay ..

    • one year ago
  91. waterineyes
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    There is mistake in denominator 10 has power 23 and not 232..

    • one year ago
  92. ashna
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    yeah you did mention it above !

    • one year ago
  93. ashna
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    so 32/100 = 0.32g ?

    • one year ago
  94. waterineyes
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    Yes you were going right @ashna Do it in your way if you did not understand my way..

    • one year ago
  95. ashna
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    no both seems the same .. i can understand :)

    • one year ago
  96. waterineyes
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    Yep you are right..

    • one year ago
  97. waterineyes
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    Now c part is same as b..

    • one year ago
  98. waterineyes
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    And there is H2S not O2. Ha ha ha.. Just kidding..

    • one year ago
  99. ashna
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    mass of 6.02*10^23 molecules of H2S = 34g mass of 1*10^23 molecules of H2S = x 34 * 1*10^23 / 6.02 *10^23 = 34 / 6.02 = 5.6 g

    • one year ago
  100. ashna
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    yea this time my eyes are wide :P

    • one year ago
  101. ashna
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    correct ?

    • one year ago
  102. waterineyes
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    Ha ha ha.. Yes you are right.. Now tell me what is L there with 56.8 I am not getting that..

    • one year ago
  103. waterineyes
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    In part D..

    • one year ago
  104. ashna
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    liter or litre not sure with the spelling .. !

    • one year ago
  105. waterineyes
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    Do you have answers with you for all of these??

    • one year ago
  106. ashna
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    not for everything !

    • one year ago
  107. waterineyes
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    or have your teacher given example of How for Liters we find the mass ??

    • one year ago
  108. ashna
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    yes .. you want that ?

    • one year ago
  109. waterineyes
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    yes if you can..

    • one year ago
  110. ashna
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    i guess the teacher has done this in class !

    • one year ago
  111. ashna
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    let me check !

    • one year ago
  112. waterineyes
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    okay..

    • one year ago
  113. ashna
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    okay she's written something like 22.4 L .. What is that ?

    • one year ago
  114. waterineyes
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    I think I am getting that 22.4 part..

    • one year ago
  115. ashna
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    okay !

    • one year ago
  116. waterineyes
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    Can you wait for just few minutes. I am having breakfast now.. Till then check this: http://www.ausetute.com.au/moledefs.html

    • one year ago
  117. waterineyes
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    There check: Ideal Gas Volumes Part..

    • one year ago
  118. waterineyes
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    Getting @ashna ..

    • one year ago
  119. ashna
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    YES

    • one year ago
  120. waterineyes
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    An ideal gas has Volume = 22.4 L at STP..

    • one year ago
  121. ashna
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    okay

    • one year ago
  122. waterineyes
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    So: 1 Mole of SO2 = 22.4 L 1L = 64/22.4 56.8 L = 64/22.4 * (56.8? Right ??

    • one year ago
  123. ashna
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    yes

    • one year ago
  124. waterineyes
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    Can you do the solvation ??

    • one year ago
  125. ashna
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    okay

    • one year ago
  126. waterineyes
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    Understood ?? How to find all ??

    • one year ago
  127. ashna
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    162.28 ?

    • one year ago
  128. waterineyes
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    Yep..

    • one year ago
  129. ashna
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    thank you :)

    • one year ago
  130. waterineyes
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    Welcome dear..

    • one year ago
  131. ashna
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    okay now .. next question ?

    • one year ago
  132. waterineyes
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    I am gone.. New post please..

    • one year ago
  133. waterineyes
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    Medal for solving c and e part. Ha haha..

    • one year ago
  134. ashna
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    :P .. i have to really give you , for spending so much time with me :)

    • one year ago
  135. ashna
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    you are a good human and a good teacher ;)

    • one year ago
  136. waterineyes
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    Really? Well, I am not..

    • one year ago
  137. ashna
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    what if i say you are one .. ?

    • one year ago
  138. waterineyes
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    Then I simply: \(\color{green}{\text{Refuse}}\)

    • one year ago
  139. ashna
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    and why ?

    • one year ago
  140. waterineyes
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    I said I am not that is why.

    • one year ago
  141. ashna
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    well then .. never mind , i'll have it that way :P

    • one year ago
  142. waterineyes
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    Never will I..

    • one year ago
  143. ashna
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    it is just because you are down to earth you are saying like that !

    • one year ago
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