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anonymous
 4 years ago
mole concept !
anonymous
 4 years ago
mole concept !

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@waterineyes back here :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Write your question here..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Calculate the mass of the following : (a) 0.5 mole of CO2. (b) 6.02 * 10^21 molecules of O2. (c) 1 * 10^23 molecules of H2S. (d) 56.8 L of SO2. (e) 1.5 mole of H2SO4.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I had said to write question here not questions here .. Ha ha ha.. Kidding..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i don't understand .. what did you want me to do actually ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0question means one question. questions means more than one questions.. Leave it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh i din see the < S > !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its one question my teacher gave !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0there are many questions like this .. and water will solve everything :p

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For fist part: Find the molecular mass of \(CO_2\)..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0molecular mass , mass and molar mass excluding the ( g ) all the same ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I will say not to go this way..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0See now you have studied What is Molar Mass.. Molar mass is mass of 1 mole of any substance. If that substance is CO2 then: Molar Mass is mass of 1 mole of CO2 So here basically you have to find Molar Mass.. For getting molar mass you will find the molecular mass of CO2 first same as you did for NaCl..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah okay .. so in the question we are asked to find the mass right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0For atoms: we have atomic mass. For molecules we have molecular mass..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes.. Molar mass is nothing but mass only. Molar Mass is "Mass" of 1 mole of a substance in grams..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of CO2 is 44 g ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0According to the definition of molar mass: Molar mass is mass of 1 mole right ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0But you have to find for 0.5 mole.. This you got mass for 1 mole.. can you find? for 1 mole it is 44g for 0.5 or half it will be ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Think logically also.. For 1 it is 44g for half that is 0.5 is nothing but half of 1: for 0.5 it will be 44/2 = 22g. Getting ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea yea .. on second thinking i understood !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i forgot half of 1 is 0.5 !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This solves first one.. Getting ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ha ha ha ha.. Not I am not.. Ha ha ha..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay .. best medicine .. so laugh !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0e> part is same.. Can you do that ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of 6.023 * 10^23 molecules of O2 = 32 mass of 6.02 * 10^21 molecules of O2 = x cross multiply ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Go for last part.. e) part

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This I tell you later on..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0e part is same as a part. Just try that so that you will completely get it..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of 1 mole of CO2 = 44 g mass of 1.5 mole of CO2 = ? 44 * 1.5 / 1 = 66 g

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes concept is right..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Dear there is H2SO4 not CO2...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay let me do with H2SO4

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do the same for H2SO4..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am in no hurry take your time..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Atomic Mass of H is : 1 Atomic Mass of S is : 28 Atomic Mass of O is : 16..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of 1 mole of H2SO4 = 98 g mass of 1.5 mole of H2SO4 = x = 98 * 1.5 / 1 = 147 g

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0atomic mass of s = 32 or 28 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think you are right..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0My mistake : Atomic Mass of Sulphur is 32..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes you have done that correctly: 98 + 49 = 147 g...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now we will do second part b)..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0but i did that before right ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay .. so teach me :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sere have you remembered this: \[1 Mole (oxygen) = 6.023 \times 10^{23} \; Oxygen \; \; Molecules\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then .. how to do ? are you trying ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh really very sorry.. You were doing it right

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[6.023 \times 10^{23} \implies 32g\] \[1 \implies \frac{32}{6.023 \times 10^{23}}\] \[6.023 \times 10^{21} \implies \frac{32}{6.023 \times 10^{232}} \times 6.023 \times 10^{21} = ??\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Oh sorry there is mistake in denominator there power of 10 is 23 and not 232..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There is mistake in denominator 10 has power 23 and not 232..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah you did mention it above !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yes you were going right @ashna Do it in your way if you did not understand my way..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no both seems the same .. i can understand :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now c part is same as b..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0And there is H2S not O2. Ha ha ha.. Just kidding..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0mass of 6.02*10^23 molecules of H2S = 34g mass of 1*10^23 molecules of H2S = x 34 * 1*10^23 / 6.02 *10^23 = 34 / 6.02 = 5.6 g

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yea this time my eyes are wide :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ha ha ha.. Yes you are right.. Now tell me what is L there with 56.8 I am not getting that..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0liter or litre not sure with the spelling .. !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Do you have answers with you for all of these??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or have your teacher given example of How for Liters we find the mass ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes .. you want that ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0i guess the teacher has done this in class !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay she's written something like 22.4 L .. What is that ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think I am getting that 22.4 part..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you wait for just few minutes. I am having breakfast now.. Till then check this: http://www.ausetute.com.au/moledefs.html

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0There check: Ideal Gas Volumes Part..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0An ideal gas has Volume = 22.4 L at STP..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So: 1 Mole of SO2 = 22.4 L 1L = 64/22.4 56.8 L = 64/22.4 * (56.8? Right ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you do the solvation ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Understood ?? How to find all ??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay now .. next question ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I am gone.. New post please..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Medal for solving c and e part. Ha haha..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0:P .. i have to really give you , for spending so much time with me :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you are a good human and a good teacher ;)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Really? Well, I am not..

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what if i say you are one .. ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Then I simply: \(\color{green}{\text{Refuse}}\)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I said I am not that is why.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well then .. never mind , i'll have it that way :P

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is just because you are down to earth you are saying like that !
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