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ashna
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@waterineyes back here :)
waterineyes
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Write your question here..
ashna
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yea .. okay !
ashna
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Calculate the mass of the following :
(a) 0.5 mole of CO2.
(b) 6.02 * 10^21 molecules of O2.
(c) 1 * 10^23 molecules of H2S.
(d) 56.8 L of SO2.
(e) 1.5 mole of H2SO4.
waterineyes
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I had said to write question here not questions here ..
Ha ha ha..
Kidding..
ashna
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i don't understand .. what did you want me to do actually ?
waterineyes
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question means one question.
questions means more than one questions..
Leave it.
ashna
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oh i din see the < S > !
ashna
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its one question my teacher gave !
ashna
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there are many questions like this .. and water will solve everything :p
ashna
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i hope so !
waterineyes
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Ha ha ha..
ashna
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:)
ashna
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so you know this ?
waterineyes
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Yes...
ashna
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so teach !
waterineyes
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For fist part:
Find the molecular mass of \(CO_2\)..
waterineyes
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*first..
ashna
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molecular mass , mass and molar mass excluding the ( g ) all the same ?
waterineyes
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I will say not to go this way..
ashna
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then ?
waterineyes
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See now you have studied What is Molar Mass..
Molar mass is mass of 1 mole of any substance.
If that substance is CO2
then:
Molar Mass is mass of 1 mole of CO2
So here basically you have to find Molar Mass..
For getting molar mass you will find the molecular mass of CO2 first same as you did for NaCl..
ashna
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yeah okay .. so in the question we are asked to find the mass right ?
waterineyes
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For atoms: we have atomic mass.
For molecules we have molecular mass..
ashna
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okay !
waterineyes
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Yes..
Molar mass is nothing but mass only.
Molar Mass is "Mass" of 1 mole of a substance in grams..
ashna
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okay :)
ashna
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so how to do (a) ?
ashna
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mass of CO2 is 44 g ?
waterineyes
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waterineyes
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According to the definition of molar mass:
Molar mass is mass of 1 mole right ??
ashna
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yeah !
waterineyes
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But you have to find for 0.5 mole..
This you got mass for 1 mole..
can you find?
for 1 mole it is 44g
for 0.5 or half it will be ??
ashna
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0.5 * 44 / 1 ?
ashna
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right ?
waterineyes
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Yep..
ashna
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okay :)
waterineyes
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Think logically also..
For 1 it is 44g
for half that is 0.5 is nothing but half of 1:
for 0.5 it will be 44/2 = 22g.
Getting ??
ashna
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partially !
ashna
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yea yea .. on second thinking i understood !
ashna
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i forgot half of 1 is 0.5 !
waterineyes
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0.5 is 1/2 no ??
ashna
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yea i got it !
waterineyes
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This solves first one..
Getting ??
ashna
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dont laugh !
ashna
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yeah :)
waterineyes
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Ha ha ha ha..
Not I am not..
Ha ha ha..
ashna
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lol yu are !
ashna
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okay .. best medicine .. so laugh !
waterineyes
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e> part is same..
Can you do that ??
ashna
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let me try !
waterineyes
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Take your time..
ashna
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mass of 6.023 * 10^23 molecules of O2 = 32
mass of 6.02 * 10^21 molecules of O2 = x
cross multiply ?
waterineyes
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Go for last part..
e) part
ashna
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okay !
waterineyes
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This I tell you later on..
ashna
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okay !
waterineyes
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e part is same as a part.
Just try that so that you will completely get it..
ashna
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mass of 1 mole of CO2 = 44 g
mass of 1.5 mole of CO2 = ?
44 * 1.5 / 1 = 66 g
ashna
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@waterineyes
ashna
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wrong ?
waterineyes
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Yes concept is right..
waterineyes
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Dear there is H2SO4 not CO2...
ashna
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oh .. sorry !
ashna
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okay let me do with H2SO4
waterineyes
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Do the same for H2SO4..
waterineyes
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I am in no hurry take your time..
waterineyes
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Atomic Mass of H is : 1
Atomic Mass of S is : 28
Atomic Mass of O is : 16..
ashna
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mass of 1 mole of H2SO4 = 98 g
mass of 1.5 mole of H2SO4 = x
= 98 * 1.5 / 1
= 147 g
ashna
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atomic mass of s = 32 or 28 ?
ashna
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@waterineyes there ?
waterineyes
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I think you are right..
waterineyes
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My mistake : Atomic Mass of Sulphur is 32..
ashna
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okay !
waterineyes
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Yes you have done that correctly:
98 + 49 = 147 g...
ashna
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okay .. :)
waterineyes
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Now we will do second part b)..
ashna
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okay !
ashna
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but i did that before right ?
ashna
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is that wrong ?
waterineyes
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Yes somewhat wrong..
ashna
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okay .. so teach me :)
waterineyes
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Sere have you remembered this:
\[1 Mole (oxygen) = 6.023 \times 10^{23} \; Oxygen \; \; Molecules\]
ashna
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okay
ashna
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then .. how to do ? are you trying ?
waterineyes
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Oh really very sorry..
You were doing it right
ashna
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really ?
waterineyes
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\[6.023 \times 10^{23} \implies 32g\]
\[1 \implies \frac{32}{6.023 \times 10^{23}}\]
\[6.023 \times 10^{21} \implies \frac{32}{6.023 \times 10^{232}} \times 6.023 \times 10^{21} = ??\]
waterineyes
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Oh sorry there is mistake in denominator there power of 10 is 23 and not 232..
ashna
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okay ..
waterineyes
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There is mistake in denominator 10 has power 23 and not 232..
ashna
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yeah you did mention it above !
ashna
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so 32/100 = 0.32g ?
waterineyes
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Yes you were going right @ashna
Do it in your way if you did not understand my way..
ashna
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no both seems the same .. i can understand :)
waterineyes
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Yep you are right..
waterineyes
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Now c part is same as b..
waterineyes
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And there is H2S not O2.
Ha ha ha..
Just kidding..
ashna
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mass of 6.02*10^23 molecules of H2S = 34g
mass of 1*10^23 molecules of H2S = x
34 * 1*10^23 / 6.02 *10^23 = 34 / 6.02 = 5.6 g
ashna
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yea this time my eyes are wide :P
ashna
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correct ?
waterineyes
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Ha ha ha..
Yes you are right..
Now tell me what is L there with 56.8 I am not getting that..
waterineyes
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In part D..
ashna
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liter or litre not sure with the spelling .. !
waterineyes
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Do you have answers with you for all of these??
ashna
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not for everything !
waterineyes
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or have your teacher given example of How for Liters we find the mass ??
ashna
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yes .. you want that ?
waterineyes
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yes if you can..
ashna
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i guess the teacher has done this in class !
ashna
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let me check !
waterineyes
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okay..
ashna
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okay she's written something like 22.4 L .. What is that ?
waterineyes
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I think I am getting that 22.4 part..
ashna
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okay !
waterineyes
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There check:
Ideal Gas Volumes Part..
waterineyes
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Getting @ashna ..
ashna
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YES
waterineyes
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An ideal gas has Volume = 22.4 L at STP..
ashna
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okay
waterineyes
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So:
1 Mole of SO2 = 22.4 L
1L = 64/22.4
56.8 L = 64/22.4 * (56.8?
Right ??
ashna
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yes
waterineyes
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Can you do the solvation ??
ashna
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okay
waterineyes
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Understood ??
How to find all ??
ashna
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162.28 ?
waterineyes
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Yep..
ashna
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thank you :)
waterineyes
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Welcome dear..
ashna
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okay now .. next question ?
waterineyes
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I am gone..
New post please..
waterineyes
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Medal for solving c and e part.
Ha haha..
ashna
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:P .. i have to really give you , for spending so much time with me :)
ashna
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you are a good human and a good teacher ;)
waterineyes
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Really?
Well, I am not..
ashna
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what if i say you are one .. ?
waterineyes
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Then I simply:
\(\color{green}{\text{Refuse}}\)
ashna
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and why ?
waterineyes
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I said I am not that is why.
ashna
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well then .. never mind , i'll have it that way :P
waterineyes
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Never will I..
ashna
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it is just because you are down to earth you are saying like that !