anonymous
  • anonymous
mole concept !
Chemistry
schrodinger
  • schrodinger
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anonymous
  • anonymous
@waterineyes back here :)
anonymous
  • anonymous
Write your question here..
anonymous
  • anonymous
yea .. okay !

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anonymous
  • anonymous
Calculate the mass of the following : (a) 0.5 mole of CO2. (b) 6.02 * 10^21 molecules of O2. (c) 1 * 10^23 molecules of H2S. (d) 56.8 L of SO2. (e) 1.5 mole of H2SO4.
anonymous
  • anonymous
I had said to write question here not questions here .. Ha ha ha.. Kidding..
anonymous
  • anonymous
i don't understand .. what did you want me to do actually ?
anonymous
  • anonymous
question means one question. questions means more than one questions.. Leave it.
anonymous
  • anonymous
oh i din see the < S > !
anonymous
  • anonymous
its one question my teacher gave !
anonymous
  • anonymous
there are many questions like this .. and water will solve everything :p
anonymous
  • anonymous
i hope so !
anonymous
  • anonymous
Ha ha ha..
anonymous
  • anonymous
:)
anonymous
  • anonymous
so you know this ?
anonymous
  • anonymous
Yes...
anonymous
  • anonymous
so teach !
anonymous
  • anonymous
For fist part: Find the molecular mass of \(CO_2\)..
anonymous
  • anonymous
*first..
anonymous
  • anonymous
molecular mass , mass and molar mass excluding the ( g ) all the same ?
anonymous
  • anonymous
I will say not to go this way..
anonymous
  • anonymous
then ?
anonymous
  • anonymous
See now you have studied What is Molar Mass.. Molar mass is mass of 1 mole of any substance. If that substance is CO2 then: Molar Mass is mass of 1 mole of CO2 So here basically you have to find Molar Mass.. For getting molar mass you will find the molecular mass of CO2 first same as you did for NaCl..
anonymous
  • anonymous
yeah okay .. so in the question we are asked to find the mass right ?
anonymous
  • anonymous
For atoms: we have atomic mass. For molecules we have molecular mass..
anonymous
  • anonymous
okay !
anonymous
  • anonymous
Yes.. Molar mass is nothing but mass only. Molar Mass is "Mass" of 1 mole of a substance in grams..
anonymous
  • anonymous
okay :)
anonymous
  • anonymous
so how to do (a) ?
anonymous
  • anonymous
mass of CO2 is 44 g ?
anonymous
  • anonymous
anonymous
  • anonymous
According to the definition of molar mass: Molar mass is mass of 1 mole right ??
anonymous
  • anonymous
yeah !
anonymous
  • anonymous
But you have to find for 0.5 mole.. This you got mass for 1 mole.. can you find? for 1 mole it is 44g for 0.5 or half it will be ??
anonymous
  • anonymous
0.5 * 44 / 1 ?
anonymous
  • anonymous
right ?
anonymous
  • anonymous
Yep..
anonymous
  • anonymous
okay :)
anonymous
  • anonymous
Think logically also.. For 1 it is 44g for half that is 0.5 is nothing but half of 1: for 0.5 it will be 44/2 = 22g. Getting ??
anonymous
  • anonymous
partially !
anonymous
  • anonymous
yea yea .. on second thinking i understood !
anonymous
  • anonymous
i forgot half of 1 is 0.5 !
anonymous
  • anonymous
0.5 is 1/2 no ??
anonymous
  • anonymous
yea i got it !
anonymous
  • anonymous
This solves first one.. Getting ??
anonymous
  • anonymous
dont laugh !
anonymous
  • anonymous
yeah :)
anonymous
  • anonymous
Ha ha ha ha.. Not I am not.. Ha ha ha..
anonymous
  • anonymous
lol yu are !
anonymous
  • anonymous
okay .. best medicine .. so laugh !
anonymous
  • anonymous
e> part is same.. Can you do that ??
anonymous
  • anonymous
let me try !
anonymous
  • anonymous
Take your time..
anonymous
  • anonymous
mass of 6.023 * 10^23 molecules of O2 = 32 mass of 6.02 * 10^21 molecules of O2 = x cross multiply ?
anonymous
  • anonymous
Go for last part.. e) part
anonymous
  • anonymous
okay !
anonymous
  • anonymous
This I tell you later on..
anonymous
  • anonymous
okay !
anonymous
  • anonymous
e part is same as a part. Just try that so that you will completely get it..
anonymous
  • anonymous
mass of 1 mole of CO2 = 44 g mass of 1.5 mole of CO2 = ? 44 * 1.5 / 1 = 66 g
anonymous
  • anonymous
anonymous
  • anonymous
wrong ?
anonymous
  • anonymous
Yes concept is right..
anonymous
  • anonymous
Dear there is H2SO4 not CO2...
anonymous
  • anonymous
oh .. sorry !
anonymous
  • anonymous
okay let me do with H2SO4
anonymous
  • anonymous
Do the same for H2SO4..
anonymous
  • anonymous
I am in no hurry take your time..
anonymous
  • anonymous
Atomic Mass of H is : 1 Atomic Mass of S is : 28 Atomic Mass of O is : 16..
anonymous
  • anonymous
mass of 1 mole of H2SO4 = 98 g mass of 1.5 mole of H2SO4 = x = 98 * 1.5 / 1 = 147 g
anonymous
  • anonymous
atomic mass of s = 32 or 28 ?
anonymous
  • anonymous
@waterineyes there ?
anonymous
  • anonymous
I think you are right..
anonymous
  • anonymous
My mistake : Atomic Mass of Sulphur is 32..
anonymous
  • anonymous
okay !
anonymous
  • anonymous
Yes you have done that correctly: 98 + 49 = 147 g...
anonymous
  • anonymous
okay .. :)
anonymous
  • anonymous
Now we will do second part b)..
anonymous
  • anonymous
okay !
anonymous
  • anonymous
but i did that before right ?
anonymous
  • anonymous
is that wrong ?
anonymous
  • anonymous
Yes somewhat wrong..
anonymous
  • anonymous
okay .. so teach me :)
anonymous
  • anonymous
Sere have you remembered this: \[1 Mole (oxygen) = 6.023 \times 10^{23} \; Oxygen \; \; Molecules\]
anonymous
  • anonymous
okay
anonymous
  • anonymous
then .. how to do ? are you trying ?
anonymous
  • anonymous
Oh really very sorry.. You were doing it right
anonymous
  • anonymous
really ?
anonymous
  • anonymous
\[6.023 \times 10^{23} \implies 32g\] \[1 \implies \frac{32}{6.023 \times 10^{23}}\] \[6.023 \times 10^{21} \implies \frac{32}{6.023 \times 10^{232}} \times 6.023 \times 10^{21} = ??\]
anonymous
  • anonymous
Oh sorry there is mistake in denominator there power of 10 is 23 and not 232..
anonymous
  • anonymous
okay ..
anonymous
  • anonymous
There is mistake in denominator 10 has power 23 and not 232..
anonymous
  • anonymous
yeah you did mention it above !
anonymous
  • anonymous
so 32/100 = 0.32g ?
anonymous
  • anonymous
Yes you were going right @ashna Do it in your way if you did not understand my way..
anonymous
  • anonymous
no both seems the same .. i can understand :)
anonymous
  • anonymous
Yep you are right..
anonymous
  • anonymous
Now c part is same as b..
anonymous
  • anonymous
And there is H2S not O2. Ha ha ha.. Just kidding..
anonymous
  • anonymous
mass of 6.02*10^23 molecules of H2S = 34g mass of 1*10^23 molecules of H2S = x 34 * 1*10^23 / 6.02 *10^23 = 34 / 6.02 = 5.6 g
anonymous
  • anonymous
yea this time my eyes are wide :P
anonymous
  • anonymous
correct ?
anonymous
  • anonymous
Ha ha ha.. Yes you are right.. Now tell me what is L there with 56.8 I am not getting that..
anonymous
  • anonymous
In part D..
anonymous
  • anonymous
liter or litre not sure with the spelling .. !
anonymous
  • anonymous
Do you have answers with you for all of these??
anonymous
  • anonymous
not for everything !
anonymous
  • anonymous
or have your teacher given example of How for Liters we find the mass ??
anonymous
  • anonymous
yes .. you want that ?
anonymous
  • anonymous
yes if you can..
anonymous
  • anonymous
i guess the teacher has done this in class !
anonymous
  • anonymous
let me check !
anonymous
  • anonymous
okay..
anonymous
  • anonymous
okay she's written something like 22.4 L .. What is that ?
anonymous
  • anonymous
I think I am getting that 22.4 part..
anonymous
  • anonymous
okay !
anonymous
  • anonymous
Can you wait for just few minutes. I am having breakfast now.. Till then check this: http://www.ausetute.com.au/moledefs.html
anonymous
  • anonymous
There check: Ideal Gas Volumes Part..
anonymous
  • anonymous
Getting @ashna ..
anonymous
  • anonymous
YES
anonymous
  • anonymous
An ideal gas has Volume = 22.4 L at STP..
anonymous
  • anonymous
okay
anonymous
  • anonymous
So: 1 Mole of SO2 = 22.4 L 1L = 64/22.4 56.8 L = 64/22.4 * (56.8? Right ??
anonymous
  • anonymous
yes
anonymous
  • anonymous
Can you do the solvation ??
anonymous
  • anonymous
okay
anonymous
  • anonymous
Understood ?? How to find all ??
anonymous
  • anonymous
162.28 ?
anonymous
  • anonymous
Yep..
anonymous
  • anonymous
thank you :)
anonymous
  • anonymous
Welcome dear..
anonymous
  • anonymous
okay now .. next question ?
anonymous
  • anonymous
I am gone.. New post please..
anonymous
  • anonymous
Medal for solving c and e part. Ha haha..
anonymous
  • anonymous
:P .. i have to really give you , for spending so much time with me :)
anonymous
  • anonymous
you are a good human and a good teacher ;)
anonymous
  • anonymous
Really? Well, I am not..
anonymous
  • anonymous
what if i say you are one .. ?
anonymous
  • anonymous
Then I simply: \(\color{green}{\text{Refuse}}\)
anonymous
  • anonymous
and why ?
anonymous
  • anonymous
I said I am not that is why.
anonymous
  • anonymous
well then .. never mind , i'll have it that way :P
anonymous
  • anonymous
Never will I..
anonymous
  • anonymous
it is just because you are down to earth you are saying like that !

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