ashna
Calculate the volume occupied
(a) 16 g of O2.
(b) 1.5 mole of N2.
(c) 6.02 * 10^20 molecules.



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waterineyes
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Volume occupied??
Level of difficultly increasing for me with each your question..
Ha ha ha..

ashna
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:P .. so we'll both study together !

waterineyes
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1 mole of 02 = 22.4 L

waterineyes
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Would we use this concept here ??

ashna
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okay .. is this like one mole = 6.023810^23 molecules .
mole of an atom or compound = 22.4 L ?

ashna
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lol .. you asking me ?

waterineyes
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No I am not asking..
Ha ha ha..

ashna
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then ?

waterineyes
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Use this:
1 mole of 02 = 22.4 L
32g = 22.4
find for 16 g..

waterineyes
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Again 16g is half of 32g remember..

ashna
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okay .. so 22.4 * 16 / 32 = 358.4/32 = 11.2 L
correct ?

ashna
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@waterineyes

waterineyes
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Yep..

ashna
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okay :)

waterineyes
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Do the same for b part..

ashna
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okay !

waterineyes
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Do not convert that into grams..

ashna
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dw:1345182838119:dw

waterineyes
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Well Done...

ashna
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:D

waterineyes
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I think you can do for third one also..

ashna
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let me try !

waterineyes
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Sure take your time..

ashna
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dw:1345183076192:dwdw:1345183267780:dw

ashna
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my hand writing is not so worse actually !

ashna
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@waterineyes checking time :P

waterineyes
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Then give me that.
Ha ha ha..

ashna
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what ? .. the hand writing ?

ashna
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is my answer correct ?

waterineyes
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Small mistake can you find out ??
Give me that checking time..

ashna
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oh .. take it :)

waterineyes
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Can you find your mistake??
Look for very last step you did ..

ashna
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no .. :/

ashna
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its not the whole divided huh ?

ashna
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you better say :)

waterineyes
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You did the steps correctly.
But there is mistake in solving part..

waterineyes
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\[\frac{22.4}{1000} = ??\]

ashna
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0.0224

ashna
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is'nt it 22.4 / 100 ?

waterineyes
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dw:1345183883219:dw

ashna
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wow ..
am scared !

waterineyes
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\[\large \frac{10^{20}}{10^{23}} = ??\]

ashna
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okay .. 1000

waterineyes
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Be careful:
\[\large \frac{x^a}{x^b} = x^{ab}\]

waterineyes
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It is not 1000 but 1/1000..

ashna
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okay !

ashna
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thanks :D

waterineyes
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Welcome dear..