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natasha.aries
Group Title
PLEASE PLEASE PLEASE!
Simply this expression
log (base 5) 125 + 3^log(base5)125 + 3 log(base 1/5)5
 2 years ago
 2 years ago
natasha.aries Group Title
PLEASE PLEASE PLEASE! Simply this expression log (base 5) 125 + 3^log(base5)125 + 3 log(base 1/5)5
 2 years ago
 2 years ago

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lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
hint: \[\huge \log_5 (125) \implies \log_5 (5^3) \implies 3\] \[\huge \log_{\frac 15} (5) \implies \log_{(5^{1})} (5^{1})^{1} \implies 1\] does that help?
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
is the answer 29?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
that's what im getting too
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
okay thank you!
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
...wait i misread your answer..
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
what do you mean?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
\[\Large \log_5 125 + 3^{\log_5 125} + 3 \log_{\frac 15} 5\] using the ones i said this will give you \[\large 3 + 3^3 + 3(1)\] do yoou see it now?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
the answer shouldnt be 29
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
oh we forgot about that 3 so it would 32?
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
you forgot about the 1
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.1
btw... 3(1) means 3 TIMES 1 NOT 3 minus 1
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
h haha wjoops 27
 2 years ago

natasha.aries Group TitleBest ResponseYou've already chosen the best response.1
okay thank you!
 2 years ago
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