• anonymous
the vector $e_v$ is a unit vector of v I guess $\vec v=<3,-1>$ $||v||=\sqrt{9+1}=\sqrt{10}$ so $e_v=\frac{1}{||v||} \vec v=\left <\frac3{\sqrt{10}},\frac{-1}{\sqrt{10}}\right >$
Mathematics

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