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MathSofiya

the vector \[e_v\] is a unit vector of v I guess \[\vec v=<3,-1>\] \[||v||=\sqrt{9+1}=\sqrt{10}\] so \[e_v=\frac{1}{||v||} \vec v=\left <\frac3{\sqrt{10}},\frac{-1}{\sqrt{10}}\right >\]

How did I do?

seems all right!!

Thank you!

hardly a probs :)

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