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ashna

  • 2 years ago

calculate the number of atoms in (a) 52 moles of He (b) 52 g of He (c) 52 u of He

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  1. ashna
    • 2 years ago
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    @waterineyes :D

  2. waterineyes
    • 2 years ago
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    This site is not properly working for me.. So I did not get your messages...

  3. ashna
    • 2 years ago
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    oh .. :/

  4. ashna
    • 2 years ago
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    so .. you know to do this ?

  5. waterineyes
    • 2 years ago
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    Let us try..

  6. ashna
    • 2 years ago
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    okay :)

  7. waterineyes
    • 2 years ago
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    1 mole of He = \(6.023 \times 10^{23} \) atoms of He

  8. ashna
    • 2 years ago
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    okay !

  9. waterineyes
    • 2 years ago
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    So find for 52..

  10. ashna
    • 2 years ago
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    okay .. i'll try :)

  11. waterineyes
    • 2 years ago
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    Mention my name here I want to check I am getting notifications or not..

  12. ashna
    • 2 years ago
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    @waterineyes

  13. waterineyes
    • 2 years ago
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    No I am not getting any..

  14. waterineyes
    • 2 years ago
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    I am not able to see my Smart Score too and my username is written in red also no green..

  15. ashna
    • 2 years ago
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    |dw:1345194842168:dw|

  16. ashna
    • 2 years ago
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    blame the site :P

  17. ashna
    • 2 years ago
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    i wrote 52 its not seen

  18. ashna
    • 2 years ago
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    is it right to carry on ?

  19. waterineyes
    • 2 years ago
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    Yes you have to just multiply 52 with that Avagadro number.. What do you get on solving ??

  20. waterineyes
    • 2 years ago
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    Yes you are right have faith on yourself and carry on I am here to check your mistakes..

  21. waterineyes
    • 2 years ago
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    Oh wow playing hide and seek with me @ashna .. Where have you gone ???

  22. waterineyes
    • 2 years ago
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    One thing I want to say that your previous profile pic I like that than your this one..

  23. waterineyes
    • 2 years ago
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    b> part hint is : 52 g of He: 1 mole of He = 6.023 * 10^{23} atoms 4 g = 6.023 * 10^{23} atoms Solve it for 52 grams..

  24. waterineyes
    • 2 years ago
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    In third part I am not getting what is u there.. 52 u ??

  25. ashna
    • 2 years ago
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    @waterineyes lol you joke too

  26. ashna
    • 2 years ago
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    some problem with the net .. i said yu that b4 !

  27. ashna
    • 2 years ago
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    hey you turned green :P

  28. ashna
    • 2 years ago
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    what is u ?

  29. ashna
    • 2 years ago
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    okay i changed my profile picture .. atleast now come back :P

  30. ashna
    • 2 years ago
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    |dw:1345202157654:dw||dw:1345202309858:dw|

  31. ashna
    • 2 years ago
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    |dw:1345202536931:dw|

  32. ashna
    • 2 years ago
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    is u the atomic unit symbol or something ? am not exactly sure about it but in some part of my brain it is registerd like that !

  33. ashna
    • 2 years ago
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    water water everywhere nor any drop to drink .. n wen yu are not replayin .. i feel like sayn water water onlyn everytym but does not reply to my question :P

  34. waterineyes
    • 2 years ago
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    a) \(313.04 \times 10^{23}\) atoms b) \(78.299 \times 10^{23}\) atoms.

  35. waterineyes
    • 2 years ago
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    You have calculated them right @ashna Well Done..

  36. waterineyes
    • 2 years ago
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    Sorry my internet was creating problem at that time I was not getting any notifications also..

  37. waterineyes
    • 2 years ago
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    See @ashna : You know atomic mass of He is 4: So: 1 mole of He = \(6.023 \times 10^{23}\)atoms Or 4g = \(6.023 \times 10^{23}\)atoms Here it is 4g.. Look for g here..

  38. waterineyes
    • 2 years ago
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    Now I am explaining the third case that is 52 u.. There it was g(grams) and now it is u.. Helium has atomic mass of 4g. But if you write it as 4u, then it means 1 atom only.. I mean to say that 4u implies \(\color{red}{\text{One Atom of Helium}}\) Where as 4g implies \(\color{blue}{{6.023 \times 10^{23} \text{Atoms of Helium= 1 Mole of Helium..}}}\)

  39. waterineyes
    • 2 years ago
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    I give you other example: For Carbon the mass is 12. So: \(\color{green}{12g = 6.023 \times 10^{23} \text{Atoms of Carbon}}\) But: \(\color{magenta}{12u \implies \text{1 Atom of Carbon..}}\)

  40. waterineyes
    • 2 years ago
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    \(\color{navy}{\text{For third part now:}}\) \(\color{silver}{\text{Helium has atomic mass of 4..}}\) \(\color{cyan}{\mathcal{So:}}\) \(\color{magenta}{4u \implies \text{1 Atom of Helium..}}\) \(\color{pink}{\text{So,}}\) \(\color{orange}{\mathsf{52 u ~\;will~ \; contain ~\; how ~\; many ~\; atoms ??}}\)

  41. waterineyes
    • 2 years ago
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    \(\frak{\color{green}{\text{ashna},\color{blue}{\text{I suggest you to go through all you have studied about Mole Concept..}}}}\) \(\color{red}{\mathsf{Have \;a \;look \; on \; all \; the \;work..}}\) \(\color{green}{\text{How we solved each and every problem just go through once.}}\) \(\color{magenta}{\text{And if you have any doubt then let me know..}}\)

  42. ashna
    • 2 years ago
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    okay :) .. n loads of thanks for your help :)

  43. ashna
    • 2 years ago
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    |dw:1345254579291:dw|

  44. waterineyes
    • 2 years ago
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    Yep..

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