## ashna Group Title calculate the number of atoms in (a) 52 moles of He (b) 52 g of He (c) 52 u of He 2 years ago 2 years ago

1. ashna Group Title

@waterineyes :D

2. waterineyes Group Title

This site is not properly working for me.. So I did not get your messages...

3. ashna Group Title

oh .. :/

4. ashna Group Title

so .. you know to do this ?

5. waterineyes Group Title

Let us try..

6. ashna Group Title

okay :)

7. waterineyes Group Title

1 mole of He = $$6.023 \times 10^{23}$$ atoms of He

8. ashna Group Title

okay !

9. waterineyes Group Title

So find for 52..

10. ashna Group Title

okay .. i'll try :)

11. waterineyes Group Title

Mention my name here I want to check I am getting notifications or not..

12. ashna Group Title

@waterineyes

13. waterineyes Group Title

No I am not getting any..

14. waterineyes Group Title

I am not able to see my Smart Score too and my username is written in red also no green..

15. ashna Group Title

|dw:1345194842168:dw|

16. ashna Group Title

blame the site :P

17. ashna Group Title

i wrote 52 its not seen

18. ashna Group Title

is it right to carry on ?

19. waterineyes Group Title

Yes you have to just multiply 52 with that Avagadro number.. What do you get on solving ??

20. waterineyes Group Title

Yes you are right have faith on yourself and carry on I am here to check your mistakes..

21. waterineyes Group Title

Oh wow playing hide and seek with me @ashna .. Where have you gone ???

22. waterineyes Group Title

One thing I want to say that your previous profile pic I like that than your this one..

23. waterineyes Group Title

b> part hint is : 52 g of He: 1 mole of He = 6.023 * 10^{23} atoms 4 g = 6.023 * 10^{23} atoms Solve it for 52 grams..

24. waterineyes Group Title

In third part I am not getting what is u there.. 52 u ??

25. ashna Group Title

@waterineyes lol you joke too

26. ashna Group Title

some problem with the net .. i said yu that b4 !

27. ashna Group Title

hey you turned green :P

28. ashna Group Title

what is u ?

29. ashna Group Title

okay i changed my profile picture .. atleast now come back :P

30. ashna Group Title

|dw:1345202157654:dw||dw:1345202309858:dw|

31. ashna Group Title

|dw:1345202536931:dw|

32. ashna Group Title

is u the atomic unit symbol or something ? am not exactly sure about it but in some part of my brain it is registerd like that !

33. ashna Group Title

water water everywhere nor any drop to drink .. n wen yu are not replayin .. i feel like sayn water water onlyn everytym but does not reply to my question :P

34. waterineyes Group Title

a) $$313.04 \times 10^{23}$$ atoms b) $$78.299 \times 10^{23}$$ atoms.

35. waterineyes Group Title

You have calculated them right @ashna Well Done..

36. waterineyes Group Title

Sorry my internet was creating problem at that time I was not getting any notifications also..

37. waterineyes Group Title

See @ashna : You know atomic mass of He is 4: So: 1 mole of He = $$6.023 \times 10^{23}$$atoms Or 4g = $$6.023 \times 10^{23}$$atoms Here it is 4g.. Look for g here..

38. waterineyes Group Title

Now I am explaining the third case that is 52 u.. There it was g(grams) and now it is u.. Helium has atomic mass of 4g. But if you write it as 4u, then it means 1 atom only.. I mean to say that 4u implies $$\color{red}{\text{One Atom of Helium}}$$ Where as 4g implies $$\color{blue}{{6.023 \times 10^{23} \text{Atoms of Helium= 1 Mole of Helium..}}}$$

39. waterineyes Group Title

I give you other example: For Carbon the mass is 12. So: $$\color{green}{12g = 6.023 \times 10^{23} \text{Atoms of Carbon}}$$ But: $$\color{magenta}{12u \implies \text{1 Atom of Carbon..}}$$

40. waterineyes Group Title

$$\color{navy}{\text{For third part now:}}$$ $$\color{silver}{\text{Helium has atomic mass of 4..}}$$ $$\color{cyan}{\mathcal{So:}}$$ $$\color{magenta}{4u \implies \text{1 Atom of Helium..}}$$ $$\color{pink}{\text{So,}}$$ $$\color{orange}{\mathsf{52 u ~\;will~ \; contain ~\; how ~\; many ~\; atoms ??}}$$

41. waterineyes Group Title

$$\frak{\color{green}{\text{ashna},\color{blue}{\text{I suggest you to go through all you have studied about Mole Concept..}}}}$$ $$\color{red}{\mathsf{Have \;a \;look \; on \; all \; the \;work..}}$$ $$\color{green}{\text{How we solved each and every problem just go through once.}}$$ $$\color{magenta}{\text{And if you have any doubt then let me know..}}$$

42. ashna Group Title