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Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.

Mathematics
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@waterineyes ....Can u Solve it out!
96

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Other answers:

\[\binom{5}3\frac{4!}{2!}-\binom433!\]
Did nt understand....
or The total number of permutation of letters (T)= 7!2!3! With two cc together (A)= 6!2! With three ss together (B)= 6!2!−5!2! With both ss and cc together (C)= 5!−4! Answer = T - A - B + C = 96
@Derp_Derpington Plzz mention the site from which u copied this..... http://math.stackexchange.com/questions/162394/arrangement-of-the-word-success
It is against the COD if u copy paste the answers
oh yeah sorry forgot to
thats ok...
@waterineyes plzz expl this.....i did nt understand
That will be 7!/2! 3! @Derp_Derpington right??
This site is not working properly for me @Yahoo!
is ans 96 only ?
@waterineyes yes it is!
im thinking a tree diagram would be rather long and involved eh
success; 7 tiers, 4 letters 3s1u2c1e s1 u c1 e c1 e s2 u s2 e u s2 c1 es2 c1s2 ec1 c2s2e c2ue uc2s2 s2c2 uc2 s2u it might go simpler on paper tho
wat is this
a tree diagram .... which was the idea i proposed :/
working it out on paper might go easier than trying to type it up readably on the computer screen tho

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