A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.
anonymous
 4 years ago
Number of ways the word 'SUCCESS' can be arranged, such that no two S's and C's are together.

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Callisto @lgbasallote @amistre64 @shubhamsrg @Shane_B

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@waterineyes ....Can u Solve it out!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\binom{5}3\frac{4!}{2!}\binom433!\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Did nt understand....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or The total number of permutation of letters (T)= 7!2!3! With two cc together (A)= 6!2! With three ss together (B)= 6!2!−5!2! With both ss and cc together (C)= 5!−4! Answer = T  A  B + C = 96

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@Derp_Derpington Plzz mention the site from which u copied this..... http://math.stackexchange.com/questions/162394/arrangementofthewordsuccess

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0It is against the COD if u copy paste the answers

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh yeah sorry forgot to

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@waterineyes plzz expl this.....i did nt understand

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0That will be 7!/2! 3! @Derp_Derpington right??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0This site is not working properly for me @Yahoo!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73 @satellite73

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@amistre64 @amistre64 @amistre64 @amistre64

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@waterineyes yes it is!

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0im thinking a tree diagram would be rather long and involved eh

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0success; 7 tiers, 4 letters 3s1u2c1e s1 u c1 e c1 e s2 u s2 e u s2 c1 es2 c1s2 ec1 c2s2e c2ue uc2s2 s2c2 uc2 s2u it might go simpler on paper tho

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0a tree diagram .... which was the idea i proposed :/

amistre64
 4 years ago
Best ResponseYou've already chosen the best response.0working it out on paper might go easier than trying to type it up readably on the computer screen tho
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.