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4meisu
 4 years ago
Given that 2sin^2 θ + sinθ  1 = 0, find the two values for sin θ
4meisu
 4 years ago
Given that 2sin^2 θ + sinθ  1 = 0, find the two values for sin θ

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.02sin² θ + sin θ  1 = 0 (2sin θ  1)(sin θ + 1) = 0

lgbasallote
 4 years ago
Best ResponseYou've already chosen the best response.0imagine \(\sin \theta = x\) so this thingy will become 2x^2 + x  1 = 0 do you know how to solve for x there?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so much can you understand ?

4meisu
 4 years ago
Best ResponseYou've already chosen the best response.0No I do not know how to solve for x.. What's next?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Now we can split that into two equations 2sin θ  1 = 0 and sin θ + 1 = 0 this much understood ?

4meisu
 4 years ago
Best ResponseYou've already chosen the best response.0sinθ = 1/2 and sinθ = 1 ?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Solving the first one: 2sin θ  1 = 0 sin θ = 1/2 θ = 30°, 150°

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Second: sin θ + 1 = 0 sin θ = 1 θ = 270°

4meisu
 4 years ago
Best ResponseYou've already chosen the best response.0The question is asking for only two values for theta though, which one would we choose?
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