A community for students.
Here's the question you clicked on:
 0 viewing
raytiller1
 3 years ago
Which of the following is the simplified form of 4y21/2y2+32
raytiller1
 3 years ago
Which of the following is the simplified form of 4y21/2y2+32

This Question is Closed

abayomi12
 3 years ago
Best ResponseYou've already chosen the best response.1(4y^29)/(2y^2+y3) always fully factor everything when you're simplifying! Top is a difference of squares expression, bottom you can simplify by factoring. TOP: (?y?)(?y+?) First ? of each bracket is square root of first coefficient (4) Second? of each bracket is square root of second coefficient (9): (2y3)(2y+3) BOTTOM: (2y^2 +y 3) 3 is negative, therefore one bracket is positive, the other is negative (?y?)(?y+?) First ? of each bracket will be factors of first coefficient (2) Second ? of each bracket will be factors of last coefficinet (3) Mix and match until upon multiplying it out, you can get the middle term; 1y; (2y3)(y+1) 2y^2 3 3y +2y 2y^2 1y 3 Not quite, so let's switch the signs around: (2y+3)(y1) 2y^2 3 +3y 2y 2y^2 +y 3 Perfect, so our bottom is going to be: (2y+3)(y1) SO NOW WE"VE SIMPLIFIED (4y^29)/(2y^2+y3) INTO (2y+3)(2y3)/(2y+3)(y1) NOTE that the (2y+3)s cancel each other out, leaving you with 1(2y3)/1(y1) (2y3)/(y1) can't factor/simplify further, so this is the final answer. So it's going to be other option 2 or 4. TO FIND RESTRICTIONS, set each part containing 'y' IN ALL DENOMINATORS WE'VE ENCOUNTERED SO FAR equal to 0. The reason for this; anything multiplied by zero in the denominator makes the equation UNDEFINED, so we need to find out what those values are by setting them equal to 0 denominators we've come across: (2y+3) and (y1) (2y+3)=0 and (y1)=0 2y= 3 and y= 1 y= 3/2 and y= 1 THEREFORE the restrictions we have our y= cannot equal 3/2, 1, THEREFORE THE SECOND OPTION IS CORRECT

raytiller1
 3 years ago
Best ResponseYou've already chosen the best response.0so wait whats the answer ? and the restrictions ? @abayomi12
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.