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raytiller1
Group Title
Which of the following is the simplified form of 4y21/2y2+32
 one year ago
 one year ago
raytiller1 Group Title
Which of the following is the simplified form of 4y21/2y2+32
 one year ago
 one year ago

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abayomi12 Group TitleBest ResponseYou've already chosen the best response.1
(4y^29)/(2y^2+y3) always fully factor everything when you're simplifying! Top is a difference of squares expression, bottom you can simplify by factoring. TOP: (?y?)(?y+?) First ? of each bracket is square root of first coefficient (4) Second? of each bracket is square root of second coefficient (9): (2y3)(2y+3) BOTTOM: (2y^2 +y 3) 3 is negative, therefore one bracket is positive, the other is negative (?y?)(?y+?) First ? of each bracket will be factors of first coefficient (2) Second ? of each bracket will be factors of last coefficinet (3) Mix and match until upon multiplying it out, you can get the middle term; 1y; (2y3)(y+1) 2y^2 3 3y +2y 2y^2 1y 3 Not quite, so let's switch the signs around: (2y+3)(y1) 2y^2 3 +3y 2y 2y^2 +y 3 Perfect, so our bottom is going to be: (2y+3)(y1) SO NOW WE"VE SIMPLIFIED (4y^29)/(2y^2+y3) INTO (2y+3)(2y3)/(2y+3)(y1) NOTE that the (2y+3)s cancel each other out, leaving you with 1(2y3)/1(y1) (2y3)/(y1) can't factor/simplify further, so this is the final answer. So it's going to be other option 2 or 4. TO FIND RESTRICTIONS, set each part containing 'y' IN ALL DENOMINATORS WE'VE ENCOUNTERED SO FAR equal to 0. The reason for this; anything multiplied by zero in the denominator makes the equation UNDEFINED, so we need to find out what those values are by setting them equal to 0 denominators we've come across: (2y+3) and (y1) (2y+3)=0 and (y1)=0 2y= 3 and y= 1 y= 3/2 and y= 1 THEREFORE the restrictions we have our y= cannot equal 3/2, 1, THEREFORE THE SECOND OPTION IS CORRECT
 one year ago

raytiller1 Group TitleBest ResponseYou've already chosen the best response.0
so wait whats the answer ? and the restrictions ? @abayomi12
 one year ago
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