anonymous
  • anonymous
Which of the following is the simplified form of 4y2-1/2y2+3-2
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
schrodinger
  • schrodinger
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
(4y^2-9)/(2y^2+y-3) always fully factor everything when you're simplifying! Top is a difference of squares expression, bottom you can simplify by factoring. TOP: (?y-?)(?y+?) First ? of each bracket is square root of first coefficient (4) Second? of each bracket is square root of second coefficient (9): (2y-3)(2y+3) BOTTOM: (2y^2 +y -3) 3 is negative, therefore one bracket is positive, the other is negative (?y-?)(?y+?) First ? of each bracket will be factors of first coefficient (2) Second ? of each bracket will be factors of last coefficinet (3) Mix and match until upon multiplying it out, you can get the middle term; 1y; (2y-3)(y+1) 2y^2 -3 -3y +2y 2y^2 -1y -3 Not quite, so let's switch the signs around: (2y+3)(y-1) 2y^2 -3 +3y -2y 2y^2 +y -3 Perfect, so our bottom is going to be: (2y+3)(y-1) SO NOW WE"VE SIMPLIFIED (4y^2-9)/(2y^2+y-3) INTO (2y+3)(2y-3)/(2y+3)(y-1) NOTE that the (2y+3)s cancel each other out, leaving you with 1(2y-3)/1(y-1) (2y-3)/(y-1) can't factor/simplify further, so this is the final answer. So it's going to be other option 2 or 4. TO FIND RESTRICTIONS, set each part containing 'y' IN ALL DENOMINATORS WE'VE ENCOUNTERED SO FAR equal to 0. The reason for this; anything multiplied by zero in the denominator makes the equation UNDEFINED, so we need to find out what those values are by setting them equal to 0 denominators we've come across: (2y+3) and (y-1) (2y+3)=0 and (y-1)=0 2y= -3 and y= 1 y= -3/2 and y= 1 THEREFORE the restrictions we have our y= cannot equal -3/2, 1, THEREFORE THE SECOND OPTION IS CORRECT
anonymous
  • anonymous
so wait whats the answer ? and the restrictions ? @abayomi12

Looking for something else?

Not the answer you are looking for? Search for more explanations.