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raytiller1

  • 2 years ago

A tower in Centerville sends radio signal a certain distance (in miles) according to the equation: x2 + y2 = 3,600. The Martinez family lives 50 miles north and 70 miles east of Centerville. Part 1: Can the Martinez family receive the radio signal from Centerville?

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  1. Veelution
    • 2 years ago
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    Do you know the Pythagorean theorem

  2. Shane_B
    • 2 years ago
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    You're given the equation:\[x^2+y^2=3600\]and you should know this will be a right triangle where \[a^2+b^2=c^2\]Therefore first figure out what c is...that will be the range of the signal: \[3600 = c^2\]\[c=60 \space miles\]The problem states that the Martinez family lives 50 miles north and 70 miles east of Centerville...which means a = 50 and b = 70...what do you get for C using the same equation as above (Pythagorean Theorem)?

  3. raytiller1
    • 2 years ago
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    ok so 50^2+70^2=60^2 ?@Shane_B 2500+4900= 3600 ?

  4. raytiller1
    • 2 years ago
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    and so no they can't get the signal?

  5. Shane_B
    • 2 years ago
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    I think you got confused there. \[50^2+70^2= c^2\]You have to solve for c in that equation to get how far they are from the signal. If it's greater than 60 miles, they won't receive it.

  6. raytiller1
    • 2 years ago
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    i thought we solved for c already?

  7. Shane_B
    • 2 years ago
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    I first solved for c just to get the range of the signal based on x^2+y^2=c^2=3600. Then you have solve for how far they are away from it...using the same base equation of \[a^2+b^2=c^2\]

  8. Shane_B
    • 2 years ago
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    I don't want to confuse you more but since the question is only asking if their distance is greater than the signal's distance, you could essentially boil it down to this question: Is 3600 < 50^2+70^2?

  9. Shane_B
    • 2 years ago
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    Maybe that will make more sense to you

  10. Shane_B
    • 2 years ago
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    If the above equation is true, they will get the signal.

  11. raytiller1
    • 2 years ago
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    yes ok now i get it i think so 50^2 +70^2 > 3600 so they will get it?

  12. Shane_B
    • 2 years ago
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    If it's > than 3600...they are too far away...it must be <=

  13. raytiller1
    • 2 years ago
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    so yes they wont get it because 25000 + 49000=74000 >3600

  14. Shane_B
    • 2 years ago
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    That's correct. Maybe this will help clear this up. The range of the radio signal is:\[\sqrt{3600}=60 \space miles\]The distance the family is from it is:\[\sqrt{50^2+70^2}=86 \space miles\]

  15. Shane_B
    • 2 years ago
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    You can answer the question using either method...I probably should have started with the simpler one: 50^2+ 70^2 > 3600 so they are out of range.

  16. raytiller1
    • 2 years ago
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    ok thanks @Shane_B

  17. Shane_B
    • 2 years ago
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    You're welcome

  18. raytiller1
    • 2 years ago
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    ok i have another question...

  19. raytiller1
    • 2 years ago
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    am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points) a few moments agoEdit Question 8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches

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