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raytiller1

  • 2 years ago

am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)

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  1. raytiller1
    • 2 years ago
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    8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches

  2. jim_thompson5910
    • 2 years ago
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    no, the answer is not \[\Large \sum_{n=1}^{8}4+4n\] for part 1 Part 2 depends on part 1, so that is also incorrect

  3. raytiller1
    • 2 years ago
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    ok can you help me then @jim_thompson5910

  4. jim_thompson5910
    • 2 years ago
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    How many computers are we talking about here?

  5. raytiller1
    • 2 years ago
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    6

  6. jim_thompson5910
    • 2 years ago
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    so you're not summing to 8 up at the top (of the sigma), you're summing to 6

  7. raytiller1
    • 2 years ago
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    thats the problem above says so i guess so

  8. jim_thompson5910
    • 2 years ago
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    so it should be \[\Large \sum_{n = 1}^{6}4+4n\] for part 1

  9. raytiller1
    • 2 years ago
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    so is the first and 2nd part for part 2 right?

  10. jim_thompson5910
    • 2 years ago
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    first part is, but the second is not...and you'd have to use 6 instead of 8

  11. raytiller1
    • 2 years ago
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    ∑ 4 + 4n = 4 ∑ 1 + n 4 * 6 + 4 ∑ n 24 + 4 [6 * 7 / 2] 24 + 25 49 inches

  12. raytiller1
    • 2 years ago
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    ?

  13. jim_thompson5910
    • 2 years ago
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    4 [6 * 7 / 2] doesn't become 25

  14. raytiller1
    • 2 years ago
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    84? i added thats why

  15. raytiller1
    • 2 years ago
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    108 inches ?

  16. jim_thompson5910
    • 2 years ago
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    it is 108 inches

  17. jim_thompson5910
    • 2 years ago
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    108 is the total final answer for part 2

  18. raytiller1
    • 2 years ago
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    can you help me with another problem?

  19. jim_thompson5910
    • 2 years ago
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    sure, what is it

  20. raytiller1
    • 2 years ago
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    help me with the steps i have an answer just don't know how? geometric partial sum ∑[i=1,5,3(-4)^(i-1)].

  21. raytiller1
    • 2 years ago
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    nevermind i found it

  22. jim_thompson5910
    • 2 years ago
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    You're basically summing 3(-4)^(i-1) from i = 1 to i = 5 So add up 3(-4)^(i-1) five times like so 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) Then replace the first i with 1, the second i with 2, the third with 3, etc etc like this 3(-4)^(1-1) 3(-4)^(2-1) 3(-4)^(3-1) 3(-4)^(4-1) 3(-4)^(5-1) Now evaluate

  23. raytiller1
    • 2 years ago
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    but i do need help with What is the 5th partial sum of ∑[i=1,∞,-1+5n]

  24. raytiller1
    • 2 years ago
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    the answer i got for the last problem was 11,170

  25. jim_thompson5910
    • 2 years ago
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    same thing, but you're now doing it with -1+5n

  26. raytiller1
    • 2 years ago
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    i got 60 ?

  27. jim_thompson5910
    • 2 years ago
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    write out -1+5n five times -1+5n -1+5n -1+5n -1+5n -1+5n then replace the first n with 1, the second with 2, etc etc to get -1+5(1) -1+5(2) -1+5(3) -1+5(4) -1+5(5)

  28. jim_thompson5910
    • 2 years ago
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    Evaluate each piece, then add them all up

  29. raytiller1
    • 2 years ago
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    70?

  30. jim_thompson5910
    • 2 years ago
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    yes, you are correct the answer is 70

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