anonymous
  • anonymous
am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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jamiebookeater
  • jamiebookeater
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anonymous
  • anonymous
8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches
jim_thompson5910
  • jim_thompson5910
no, the answer is not \[\Large \sum_{n=1}^{8}4+4n\] for part 1 Part 2 depends on part 1, so that is also incorrect
anonymous
  • anonymous
ok can you help me then @jim_thompson5910

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jim_thompson5910
  • jim_thompson5910
How many computers are we talking about here?
anonymous
  • anonymous
6
jim_thompson5910
  • jim_thompson5910
so you're not summing to 8 up at the top (of the sigma), you're summing to 6
anonymous
  • anonymous
thats the problem above says so i guess so
jim_thompson5910
  • jim_thompson5910
so it should be \[\Large \sum_{n = 1}^{6}4+4n\] for part 1
anonymous
  • anonymous
so is the first and 2nd part for part 2 right?
jim_thompson5910
  • jim_thompson5910
first part is, but the second is not...and you'd have to use 6 instead of 8
anonymous
  • anonymous
∑ 4 + 4n = 4 ∑ 1 + n 4 * 6 + 4 ∑ n 24 + 4 [6 * 7 / 2] 24 + 25 49 inches
anonymous
  • anonymous
?
jim_thompson5910
  • jim_thompson5910
4 [6 * 7 / 2] doesn't become 25
anonymous
  • anonymous
84? i added thats why
anonymous
  • anonymous
108 inches ?
jim_thompson5910
  • jim_thompson5910
it is 108 inches
jim_thompson5910
  • jim_thompson5910
108 is the total final answer for part 2
anonymous
  • anonymous
can you help me with another problem?
jim_thompson5910
  • jim_thompson5910
sure, what is it
anonymous
  • anonymous
help me with the steps i have an answer just don't know how? geometric partial sum ∑[i=1,5,3(-4)^(i-1)].
anonymous
  • anonymous
nevermind i found it
jim_thompson5910
  • jim_thompson5910
You're basically summing 3(-4)^(i-1) from i = 1 to i = 5 So add up 3(-4)^(i-1) five times like so 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) Then replace the first i with 1, the second i with 2, the third with 3, etc etc like this 3(-4)^(1-1) 3(-4)^(2-1) 3(-4)^(3-1) 3(-4)^(4-1) 3(-4)^(5-1) Now evaluate
anonymous
  • anonymous
but i do need help with What is the 5th partial sum of ∑[i=1,∞,-1+5n]
anonymous
  • anonymous
the answer i got for the last problem was 11,170
jim_thompson5910
  • jim_thompson5910
same thing, but you're now doing it with -1+5n
anonymous
  • anonymous
i got 60 ?
jim_thompson5910
  • jim_thompson5910
write out -1+5n five times -1+5n -1+5n -1+5n -1+5n -1+5n then replace the first n with 1, the second with 2, etc etc to get -1+5(1) -1+5(2) -1+5(3) -1+5(4) -1+5(5)
jim_thompson5910
  • jim_thompson5910
Evaluate each piece, then add them all up
anonymous
  • anonymous
70?
jim_thompson5910
  • jim_thompson5910
yes, you are correct the answer is 70

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