am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)

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am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)

Mathematics
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8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches
no, the answer is not \[\Large \sum_{n=1}^{8}4+4n\] for part 1 Part 2 depends on part 1, so that is also incorrect
ok can you help me then @jim_thompson5910

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Other answers:

How many computers are we talking about here?
6
so you're not summing to 8 up at the top (of the sigma), you're summing to 6
thats the problem above says so i guess so
so it should be \[\Large \sum_{n = 1}^{6}4+4n\] for part 1
so is the first and 2nd part for part 2 right?
first part is, but the second is not...and you'd have to use 6 instead of 8
∑ 4 + 4n = 4 ∑ 1 + n 4 * 6 + 4 ∑ n 24 + 4 [6 * 7 / 2] 24 + 25 49 inches
?
4 [6 * 7 / 2] doesn't become 25
84? i added thats why
108 inches ?
it is 108 inches
108 is the total final answer for part 2
can you help me with another problem?
sure, what is it
help me with the steps i have an answer just don't know how? geometric partial sum ∑[i=1,5,3(-4)^(i-1)].
nevermind i found it
You're basically summing 3(-4)^(i-1) from i = 1 to i = 5 So add up 3(-4)^(i-1) five times like so 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) Then replace the first i with 1, the second i with 2, the third with 3, etc etc like this 3(-4)^(1-1) 3(-4)^(2-1) 3(-4)^(3-1) 3(-4)^(4-1) 3(-4)^(5-1) Now evaluate
but i do need help with What is the 5th partial sum of ∑[i=1,∞,-1+5n]
the answer i got for the last problem was 11,170
same thing, but you're now doing it with -1+5n
i got 60 ?
write out -1+5n five times -1+5n -1+5n -1+5n -1+5n -1+5n then replace the first n with 1, the second with 2, etc etc to get -1+5(1) -1+5(2) -1+5(3) -1+5(4) -1+5(5)
Evaluate each piece, then add them all up
70?
yes, you are correct the answer is 70

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