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raytiller1 Group Title

am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)

  • 2 years ago
  • 2 years ago

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  1. raytiller1 Group Title
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    8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches

    • 2 years ago
  2. jim_thompson5910 Group Title
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    no, the answer is not \[\Large \sum_{n=1}^{8}4+4n\] for part 1 Part 2 depends on part 1, so that is also incorrect

    • 2 years ago
  3. raytiller1 Group Title
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    ok can you help me then @jim_thompson5910

    • 2 years ago
  4. jim_thompson5910 Group Title
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    How many computers are we talking about here?

    • 2 years ago
  5. raytiller1 Group Title
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    6

    • 2 years ago
  6. jim_thompson5910 Group Title
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    so you're not summing to 8 up at the top (of the sigma), you're summing to 6

    • 2 years ago
  7. raytiller1 Group Title
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    thats the problem above says so i guess so

    • 2 years ago
  8. jim_thompson5910 Group Title
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    so it should be \[\Large \sum_{n = 1}^{6}4+4n\] for part 1

    • 2 years ago
  9. raytiller1 Group Title
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    so is the first and 2nd part for part 2 right?

    • 2 years ago
  10. jim_thompson5910 Group Title
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    first part is, but the second is not...and you'd have to use 6 instead of 8

    • 2 years ago
  11. raytiller1 Group Title
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    ∑ 4 + 4n = 4 ∑ 1 + n 4 * 6 + 4 ∑ n 24 + 4 [6 * 7 / 2] 24 + 25 49 inches

    • 2 years ago
  12. raytiller1 Group Title
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    ?

    • 2 years ago
  13. jim_thompson5910 Group Title
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    4 [6 * 7 / 2] doesn't become 25

    • 2 years ago
  14. raytiller1 Group Title
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    84? i added thats why

    • 2 years ago
  15. raytiller1 Group Title
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    108 inches ?

    • 2 years ago
  16. jim_thompson5910 Group Title
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    it is 108 inches

    • 2 years ago
  17. jim_thompson5910 Group Title
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    108 is the total final answer for part 2

    • 2 years ago
  18. raytiller1 Group Title
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    can you help me with another problem?

    • 2 years ago
  19. jim_thompson5910 Group Title
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    sure, what is it

    • 2 years ago
  20. raytiller1 Group Title
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    help me with the steps i have an answer just don't know how? geometric partial sum ∑[i=1,5,3(-4)^(i-1)].

    • 2 years ago
  21. raytiller1 Group Title
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    nevermind i found it

    • 2 years ago
  22. jim_thompson5910 Group Title
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    You're basically summing 3(-4)^(i-1) from i = 1 to i = 5 So add up 3(-4)^(i-1) five times like so 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) Then replace the first i with 1, the second i with 2, the third with 3, etc etc like this 3(-4)^(1-1) 3(-4)^(2-1) 3(-4)^(3-1) 3(-4)^(4-1) 3(-4)^(5-1) Now evaluate

    • 2 years ago
  23. raytiller1 Group Title
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    but i do need help with What is the 5th partial sum of ∑[i=1,∞,-1+5n]

    • 2 years ago
  24. raytiller1 Group Title
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    the answer i got for the last problem was 11,170

    • 2 years ago
  25. jim_thompson5910 Group Title
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    same thing, but you're now doing it with -1+5n

    • 2 years ago
  26. raytiller1 Group Title
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    i got 60 ?

    • 2 years ago
  27. jim_thompson5910 Group Title
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    write out -1+5n five times -1+5n -1+5n -1+5n -1+5n -1+5n then replace the first n with 1, the second with 2, etc etc to get -1+5(1) -1+5(2) -1+5(3) -1+5(4) -1+5(5)

    • 2 years ago
  28. jim_thompson5910 Group Title
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    Evaluate each piece, then add them all up

    • 2 years ago
  29. raytiller1 Group Title
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    70?

    • 2 years ago
  30. jim_thompson5910 Group Title
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    yes, you are correct the answer is 70

    • 2 years ago
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