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raytiller1 Group Title

am i right? A store displays six computers on a shelf side–by–side. If the first computer is eight inches wide and each successive computer is four inches wider than the previous one, find the total width of the computers on the shelf. Part 1: Describe the sigma notation used in answering the question above. (2 points) Part 2: Show all your work and answer the question. (3 points)

  • one year ago
  • one year ago

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  1. raytiller1 Group Title
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    8 ∑ 4 + 4n n=1 ∑ 4 + 4n = 4 ∑ 1 + n 4 * 8 + 4 ∑ n 32 + 4 [8 * 9 / 2] 32 + 40 72 inches

    • one year ago
  2. jim_thompson5910 Group Title
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    no, the answer is not \[\Large \sum_{n=1}^{8}4+4n\] for part 1 Part 2 depends on part 1, so that is also incorrect

    • one year ago
  3. raytiller1 Group Title
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    ok can you help me then @jim_thompson5910

    • one year ago
  4. jim_thompson5910 Group Title
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    How many computers are we talking about here?

    • one year ago
  5. raytiller1 Group Title
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    6

    • one year ago
  6. jim_thompson5910 Group Title
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    so you're not summing to 8 up at the top (of the sigma), you're summing to 6

    • one year ago
  7. raytiller1 Group Title
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    thats the problem above says so i guess so

    • one year ago
  8. jim_thompson5910 Group Title
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    so it should be \[\Large \sum_{n = 1}^{6}4+4n\] for part 1

    • one year ago
  9. raytiller1 Group Title
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    so is the first and 2nd part for part 2 right?

    • one year ago
  10. jim_thompson5910 Group Title
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    first part is, but the second is not...and you'd have to use 6 instead of 8

    • one year ago
  11. raytiller1 Group Title
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    ∑ 4 + 4n = 4 ∑ 1 + n 4 * 6 + 4 ∑ n 24 + 4 [6 * 7 / 2] 24 + 25 49 inches

    • one year ago
  12. raytiller1 Group Title
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    ?

    • one year ago
  13. jim_thompson5910 Group Title
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    4 [6 * 7 / 2] doesn't become 25

    • one year ago
  14. raytiller1 Group Title
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    84? i added thats why

    • one year ago
  15. raytiller1 Group Title
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    108 inches ?

    • one year ago
  16. jim_thompson5910 Group Title
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    it is 108 inches

    • one year ago
  17. jim_thompson5910 Group Title
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    108 is the total final answer for part 2

    • one year ago
  18. raytiller1 Group Title
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    can you help me with another problem?

    • one year ago
  19. jim_thompson5910 Group Title
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    sure, what is it

    • one year ago
  20. raytiller1 Group Title
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    help me with the steps i have an answer just don't know how? geometric partial sum ∑[i=1,5,3(-4)^(i-1)].

    • one year ago
  21. raytiller1 Group Title
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    nevermind i found it

    • one year ago
  22. jim_thompson5910 Group Title
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    You're basically summing 3(-4)^(i-1) from i = 1 to i = 5 So add up 3(-4)^(i-1) five times like so 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) 3(-4)^(i-1) Then replace the first i with 1, the second i with 2, the third with 3, etc etc like this 3(-4)^(1-1) 3(-4)^(2-1) 3(-4)^(3-1) 3(-4)^(4-1) 3(-4)^(5-1) Now evaluate

    • one year ago
  23. raytiller1 Group Title
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    but i do need help with What is the 5th partial sum of ∑[i=1,∞,-1+5n]

    • one year ago
  24. raytiller1 Group Title
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    the answer i got for the last problem was 11,170

    • one year ago
  25. jim_thompson5910 Group Title
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    same thing, but you're now doing it with -1+5n

    • one year ago
  26. raytiller1 Group Title
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    i got 60 ?

    • one year ago
  27. jim_thompson5910 Group Title
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    write out -1+5n five times -1+5n -1+5n -1+5n -1+5n -1+5n then replace the first n with 1, the second with 2, etc etc to get -1+5(1) -1+5(2) -1+5(3) -1+5(4) -1+5(5)

    • one year ago
  28. jim_thompson5910 Group Title
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    Evaluate each piece, then add them all up

    • one year ago
  29. raytiller1 Group Title
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    70?

    • one year ago
  30. jim_thompson5910 Group Title
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    yes, you are correct the answer is 70

    • one year ago
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