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cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.1first take out x: f(x) = x(x^2  5x + 6) = 0 (x(x  3)(x  2) = 0 can you continue?

gfields444
 2 years ago
Best ResponseYou've already chosen the best response.0i still do no understand

cwrw238
 2 years ago
Best ResponseYou've already chosen the best response.1did you understand why i took the x out?

gfields444
 2 years ago
Best ResponseYou've already chosen the best response.00, –3, 2 0, 3, –2 0, –3, –2 0, 3, 2 I got these four answers

jordyn77
 2 years ago
Best ResponseYou've already chosen the best response.0do you understand why there's three answers?

gfields444
 2 years ago
Best ResponseYou've already chosen the best response.0yes but i dont know which one is correct, i tried four different times and ended up with these ugh

imnotready
 2 years ago
Best ResponseYou've already chosen the best response.1The zeroes is just where y = 0. So pretend f(x) is your y and plug in 0. 0 = x^3 – 5x^2 + 6x Do you know how to solve this? Just ignore f(x)

imnotready
 2 years ago
Best ResponseYou've already chosen the best response.1I would start by factoring first, all of these numbers have a common factor, x. x (x^2  5x + 6) Now, factor it further by factoring x^25x+6 You get (x3)(x2) you're left with x(x3)(x2) Equal each of these expressions to zero. x=0 x  3 = 0, which is x=3 x  2 = 0, which is x =2
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