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gfields444 Group Title

What are the zeros of the polynomial function: f(x) = x^3 – 5x^2 + 6x

  • one year ago
  • one year ago

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  1. cwrw238 Group Title
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    first take out x: f(x) = x(x^2 - 5x + 6) = 0 (x(x - 3)(x - 2) = 0 can you continue?

    • one year ago
  2. gfields444 Group Title
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    i still do no understand

    • one year ago
  3. gfields444 Group Title
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    not*

    • one year ago
  4. cwrw238 Group Title
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    did you understand why i took the x out?

    • one year ago
  5. gfields444 Group Title
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    no :(

    • one year ago
  6. gfields444 Group Title
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    0, –3, 2 0, 3, –2 0, –3, –2 0, 3, 2 I got these four answers

    • one year ago
  7. jordyn77 Group Title
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    do you understand why there's three answers?

    • one year ago
  8. gfields444 Group Title
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    yes but i dont know which one is correct, i tried four different times and ended up with these ugh

    • one year ago
  9. imnotready Group Title
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    The zeroes is just where y = 0. So pretend f(x) is your y and plug in 0. 0 = x^3 – 5x^2 + 6x Do you know how to solve this? Just ignore f(x)

    • one year ago
  10. imnotready Group Title
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    I would start by factoring first, all of these numbers have a common factor, x. x (x^2 - 5x + 6) Now, factor it further by factoring x^2-5x+6 You get (x-3)(x-2) you're left with x(x-3)(x-2) Equal each of these expressions to zero. x=0 x - 3 = 0, which is x=3 x - 2 = 0, which is x =2

    • one year ago
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