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gfields444

  • 2 years ago

What are the zeros of the polynomial function: f(x) = x^3 – 5x^2 + 6x

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  1. cwrw238
    • 2 years ago
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    first take out x: f(x) = x(x^2 - 5x + 6) = 0 (x(x - 3)(x - 2) = 0 can you continue?

  2. gfields444
    • 2 years ago
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    i still do no understand

  3. gfields444
    • 2 years ago
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    not*

  4. cwrw238
    • 2 years ago
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    did you understand why i took the x out?

  5. gfields444
    • 2 years ago
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    no :(

  6. gfields444
    • 2 years ago
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    0, –3, 2 0, 3, –2 0, –3, –2 0, 3, 2 I got these four answers

  7. jordyn77
    • 2 years ago
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    do you understand why there's three answers?

  8. gfields444
    • 2 years ago
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    yes but i dont know which one is correct, i tried four different times and ended up with these ugh

  9. imnotready
    • 2 years ago
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    The zeroes is just where y = 0. So pretend f(x) is your y and plug in 0. 0 = x^3 – 5x^2 + 6x Do you know how to solve this? Just ignore f(x)

  10. imnotready
    • 2 years ago
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    I would start by factoring first, all of these numbers have a common factor, x. x (x^2 - 5x + 6) Now, factor it further by factoring x^2-5x+6 You get (x-3)(x-2) you're left with x(x-3)(x-2) Equal each of these expressions to zero. x=0 x - 3 = 0, which is x=3 x - 2 = 0, which is x =2

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