What are the zeros of the polynomial function: f(x) = x^3 – 5x^2 + 6x
Stacey Warren - Expert brainly.com
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first take out x:
f(x) = x(x^2 - 5x + 6) = 0
(x(x - 3)(x - 2) = 0
can you continue?
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did you understand why i took the x out?
0, –3, 2
0, 3, –2
0, –3, –2
0, 3, 2
I got these four answers
do you understand why there's three answers?
yes but i dont know which one is correct, i tried four different times and ended up with these ugh
The zeroes is just where y = 0. So pretend f(x) is your y and plug in 0.
0 = x^3 – 5x^2 + 6x
Do you know how to solve this? Just ignore f(x)
I would start by factoring first, all of these numbers have a common factor, x.
x (x^2 - 5x + 6)
Now, factor it further by factoring x^2-5x+6
You get (x-3)(x-2)
you're left with x(x-3)(x-2)
Equal each of these expressions to zero.
x - 3 = 0, which is x=3
x - 2 = 0, which is x =2