Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

Use an appropriate Riemann sum to evaluate the limit (see attached).

See more answers at
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer


To see the expert answer you'll need to create a free account at Brainly

1 Attachment
Well your limit has x->infty but only mentions the variable n...
oh that was a typo on my part

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

n-->infinity . and it's what the problem requires...
Here is a similar problem if it helps: steps are shown
Because any exponent in the denominator that is greater than the highest degree exponent in the numerator is zero
Yes, it's pretty retarded
I wrote that wrong but you know what I mean
I guess they're trying to drive the point home that a reimann sum with infinite rectangles is an integral...
Nvm what I said earlier. The sums are infinite, so they don't easily cancel out.
I think I'll just be like "Textbook is stupid. Answer is zero"... too much work

Not the answer you are looking for?

Search for more explanations.

Ask your own question