anonymous
  • anonymous
Use an appropriate Riemann sum to evaluate the limit (see attached).
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
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anonymous
  • anonymous
Well your limit has x->infty but only mentions the variable n...
anonymous
  • anonymous
oh that was a typo on my part

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anonymous
  • anonymous
n-->infinity . and it's what the problem requires...
anonymous
  • anonymous
Here is a similar problem if it helps: steps are shown
anonymous
  • anonymous
Because any exponent in the denominator that is greater than the highest degree exponent in the numerator is zero
anonymous
  • anonymous
Yes, it's pretty retarded
anonymous
  • anonymous
I wrote that wrong but you know what I mean
anonymous
  • anonymous
I guess they're trying to drive the point home that a reimann sum with infinite rectangles is an integral...
anonymous
  • anonymous
Nvm what I said earlier. The sums are infinite, so they don't easily cancel out.
anonymous
  • anonymous
I think I'll just be like "Textbook is stupid. Answer is zero"... too much work

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