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unkabogable
Group Title
a stone is dropped from a captive balloon at an elevation of 1000ft,. two sec later another stone is projected vertically upward from the ground with a velocity of 248ft per sec. if g is 32ft per sec squared when and where will the stones pass each other?
 2 years ago
 2 years ago
unkabogable Group Title
a stone is dropped from a captive balloon at an elevation of 1000ft,. two sec later another stone is projected vertically upward from the ground with a velocity of 248ft per sec. if g is 32ft per sec squared when and where will the stones pass each other?
 2 years ago
 2 years ago

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razor99 Group TitleBest ResponseYou've already chosen the best response.0
wow is that a physics question
 2 years ago

unkabogable Group TitleBest ResponseYou've already chosen the best response.1
obviously..yes :)
 2 years ago

razor99 Group TitleBest ResponseYou've already chosen the best response.0
this is the first time i ever saw a physics question lol cuz i study business stream
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
can u write a equation for the first stone distance travelled by it in t seconds
 2 years ago

unkabogable Group TitleBest ResponseYou've already chosen the best response.1
i know that: \[V _{01}=0 ft/s\] \[V _{02}=248 ft/s\] \[g=32.2 ft/s^2\] \[t _{1}=t _{2}+2\]
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
@unkabogable can u?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
So for the first stone distance travelled by it in t seconds is = ut + 1/2 at^2 = 16t^2
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
right?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
now find, for the first stone distance travelled by it in 2 seconds
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
can u?
 2 years ago

unkabogable Group TitleBest ResponseYou've already chosen the best response.1
yeah...wait: so i have these eq. \[Y _{1}=1000Y _{2}\] \[Y _{2}=V _{02}t _{2}1/2(32.2)t _{2}^2\] then i'll substitute and i'll verify my answer later
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Let me do it then, for the first stone distance travelled by it in 2 seconds=16*2^2 = 64ft now velocity of it after two seconds = (o^2 + 2*32 *64)^1/2 = 64ft/s
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Now,Now, after two seconds, height of the stone after t seonds =100064( ut+1/2 at^2) = 93664t  16t^2
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
then for the next stone: height of the stone after t seconds = ut + 1/2 at^2 = 248t + 1/2 (32) t^2 =248t  16t^2
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Now, when the the stones pass each other , 93664t  16t^2=248t  16t^2 936=312t t=3seconds
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
so the stone will pass each other at 3+2 seconds = 5 seconds
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
got it?
 2 years ago

unkabogable Group TitleBest ResponseYou've already chosen the best response.1
yes..thanks again!! :)
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
WElcome
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
No, can u find this where will the stones pass each other
 2 years ago

unkabogable Group TitleBest ResponseYou've already chosen the best response.1
(248)(52)\[(248)(52) \frac{ (32.2(52)^2) }{ 2} = 600 ft\] ??
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.2
Yep........ 600 ft above the ground
 2 years ago
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