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a stone is dropped from a captive balloon at an elevation of 1000ft,. two sec later another stone is projected vertically upward from the ground with a velocity of 248ft per sec. if g is 32ft per sec squared when and where will the stones pass each other?
 one year ago
 one year ago
a stone is dropped from a captive balloon at an elevation of 1000ft,. two sec later another stone is projected vertically upward from the ground with a velocity of 248ft per sec. if g is 32ft per sec squared when and where will the stones pass each other?
 one year ago
 one year ago

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razor99Best ResponseYou've already chosen the best response.0
wow is that a physics question
 one year ago

razor99Best ResponseYou've already chosen the best response.0
this is the first time i ever saw a physics question lol cuz i study business stream
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
can u write a equation for the first stone distance travelled by it in t seconds
 one year ago

unkabogableBest ResponseYou've already chosen the best response.1
i know that: \[V _{01}=0 ft/s\] \[V _{02}=248 ft/s\] \[g=32.2 ft/s^2\] \[t _{1}=t _{2}+2\]
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
@unkabogable can u?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
So for the first stone distance travelled by it in t seconds is = ut + 1/2 at^2 = 16t^2
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
now find, for the first stone distance travelled by it in 2 seconds
 one year ago

unkabogableBest ResponseYou've already chosen the best response.1
yeah...wait: so i have these eq. \[Y _{1}=1000Y _{2}\] \[Y _{2}=V _{02}t _{2}1/2(32.2)t _{2}^2\] then i'll substitute and i'll verify my answer later
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Let me do it then, for the first stone distance travelled by it in 2 seconds=16*2^2 = 64ft now velocity of it after two seconds = (o^2 + 2*32 *64)^1/2 = 64ft/s
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now,Now, after two seconds, height of the stone after t seonds =100064( ut+1/2 at^2) = 93664t  16t^2
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
then for the next stone: height of the stone after t seconds = ut + 1/2 at^2 = 248t + 1/2 (32) t^2 =248t  16t^2
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Now, when the the stones pass each other , 93664t  16t^2=248t  16t^2 936=312t t=3seconds
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
so the stone will pass each other at 3+2 seconds = 5 seconds
 one year ago

unkabogableBest ResponseYou've already chosen the best response.1
yes..thanks again!! :)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
No, can u find this where will the stones pass each other
 one year ago

unkabogableBest ResponseYou've already chosen the best response.1
(248)(52)\[(248)(52) \frac{ (32.2(52)^2) }{ 2} = 600 ft\] ??
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.2
Yep........ 600 ft above the ground
 one year ago
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