## tiffybabyy 3 years ago I have no idea where to begin. :l Helpp? In Triangle ABC shown below, side AB is 6 and side AC is 4. Which statement is needed to prove that segment DE is parallel to segment BC and half its length? Segment AD is 3 and segment AE is 4. Segment AD is 3 and segment AE is 2. Segment AD is 12 and segment AE is 8. Segment AD is 12 and segment AE is 4. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1000_Subtest_01_01/image0014e8c4ab2.jpg

1. ghazi

for half length side must be in proportion so...can you guess now?

2. TheViper

Segment AD is 3 and segment AE is 2.

3. TheViper

Understood @tiffybabyy ?? or any doubt ??

4. tiffybabyy

So I would do this?? $\frac{ 6 }{ 4 }=\frac{3}{ 2 }$ Cross multiple and if they equal out then its right?

5. ghazi

yes

6. annas

so the answer will be "Segment AD is 3 and segment AE is 2." isnt it @TheViper ???

7. tiffybabyy

Okay(: Thank you guys !!

8. annas

my pleasure and thanks viper :)

9. ghazi

$\frac{ AD }{ AB }=\frac{ AE }{ AC }$

10. TheViper

If this is a triangle (of any type) :-|dw:1345301124982:dw|& if $$\Large{AD=BD}$$& $$\Large{AE=EC}$$then $\Large{DE \parallel BC}$ So answer is Segment AD is 3 and segment AE is 2.

11. TheViper

@ghazi @annas @tiffybabyy now it's clear??

12. tiffybabyy

Yeah. I get it. Thanks you guys! :D

13. TheViper

hmmm...... Ur welcome ;)

14. annas

yeah i got it :) thanks viper dude

15. TheViper

dude I like saying dude !!

16. annas

lol me too dude :P