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tiffybabyy
I have no idea where to begin. :l Helpp? In Triangle ABC shown below, side AB is 6 and side AC is 4. Which statement is needed to prove that segment DE is parallel to segment BC and half its length? Segment AD is 3 and segment AE is 4. Segment AD is 3 and segment AE is 2. Segment AD is 12 and segment AE is 8. Segment AD is 12 and segment AE is 4. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1000_Subtest_01_01/image0014e8c4ab2.jpg
for half length side must be in proportion so...can you guess now?
Segment AD is 3 and segment AE is 2.
Understood @tiffybabyy ?? or any doubt ??
So I would do this?? \[\frac{ 6 }{ 4 }=\frac{3}{ 2 }\] Cross multiple and if they equal out then its right?
so the answer will be "Segment AD is 3 and segment AE is 2." isnt it @TheViper ???
Okay(: Thank you guys !!
my pleasure and thanks viper :)
\[\frac{ AD }{ AB }=\frac{ AE }{ AC }\]
If this is a triangle (of any type) :-|dw:1345301124982:dw|& if \(\Large{AD=BD}\)& \(\Large{AE=EC}\)then \[\Large{DE \parallel BC}\] So answer is Segment AD is 3 and segment AE is 2.
@ghazi @annas @tiffybabyy now it's clear??
Yeah. I get it. Thanks you guys! :D
hmmm...... Ur welcome ;)
yeah i got it :) thanks viper dude
dude I like saying dude !!