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tiffybabyy

  • 3 years ago

I have no idea where to begin. :l Helpp? In Triangle ABC shown below, side AB is 6 and side AC is 4. Which statement is needed to prove that segment DE is parallel to segment BC and half its length? Segment AD is 3 and segment AE is 4. Segment AD is 3 and segment AE is 2. Segment AD is 12 and segment AE is 8. Segment AD is 12 and segment AE is 4. http://learn.flvs.net/webdav/assessment_images/educator_geometry_v14/pool_Geom_3641_1000_Subtest_01_01/image0014e8c4ab2.jpg

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  1. ghazi
    • 3 years ago
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    for half length side must be in proportion so...can you guess now?

  2. TheViper
    • 3 years ago
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    Segment AD is 3 and segment AE is 2.

  3. TheViper
    • 3 years ago
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    Understood @tiffybabyy ?? or any doubt ??

  4. tiffybabyy
    • 3 years ago
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    So I would do this?? \[\frac{ 6 }{ 4 }=\frac{3}{ 2 }\] Cross multiple and if they equal out then its right?

  5. ghazi
    • 3 years ago
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    yes

  6. annas
    • 3 years ago
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    so the answer will be "Segment AD is 3 and segment AE is 2." isnt it @TheViper ???

  7. tiffybabyy
    • 3 years ago
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    Okay(: Thank you guys !!

  8. annas
    • 3 years ago
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    my pleasure and thanks viper :)

  9. ghazi
    • 3 years ago
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    \[\frac{ AD }{ AB }=\frac{ AE }{ AC }\]

  10. TheViper
    • 3 years ago
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    If this is a triangle (of any type) :-|dw:1345301124982:dw|& if \(\Large{AD=BD}\)& \(\Large{AE=EC}\)then \[\Large{DE \parallel BC}\] So answer is Segment AD is 3 and segment AE is 2.

  11. TheViper
    • 3 years ago
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    @ghazi @annas @tiffybabyy now it's clear??

  12. tiffybabyy
    • 3 years ago
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    Yeah. I get it. Thanks you guys! :D

  13. TheViper
    • 3 years ago
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    hmmm...... Ur welcome ;)

  14. annas
    • 3 years ago
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    yeah i got it :) thanks viper dude

  15. TheViper
    • 3 years ago
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    dude I like saying dude !!

  16. annas
    • 3 years ago
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    lol me too dude :P

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