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yeller33

  • 3 years ago

logx-log6=log15

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  1. sauravshakya
    • 3 years ago
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    HINT: logx-log6 = log(x/6)

  2. sauravshakya
    • 3 years ago
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    Now, can u?

  3. TheViper
    • 3 years ago
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    so \(\frac{x}{6}=15\) ?? @sauravshakya

  4. sauravshakya
    • 3 years ago
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    Yep... @TheViper

  5. TheViper
    • 3 years ago
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    Yeah I hoped :) THANX ;)

  6. sauravshakya
    • 3 years ago
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    WElcome

  7. vishweshshrimali5
    • 3 years ago
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    @yeller33 see, log a- log b = log(a/b) and log a + log b = log (ab) remember these 2 formula for ever

  8. abayomi12
    • 3 years ago
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    log(x) - log(6) = log(15) Add log(6) to each side: log(x) = log(15) + log(6) = log(15 times 6) x = 15 times 6 x = 90

  9. vishweshshrimali5
    • 3 years ago
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    Gud

  10. sauravshakya
    • 3 years ago
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    |dw:1345303238963:dw|And , right? @vishweshshrimali5

  11. vishweshshrimali5
    • 3 years ago
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    Yes @sauravshakya absolutely correct

  12. yeller33
    • 3 years ago
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    okay i understand thanks guys!

  13. sauravshakya
    • 3 years ago
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    Welcome

  14. yeller33
    • 3 years ago
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    how do you do it if it has a number at the end. = log7+logx=2.... the 2 throws me off.

  15. Kaederfds
    • 3 years ago
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    x is 90

  16. sauravshakya
    • 3 years ago
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    log7 + logx=2 log(7*x)=2

  17. sauravshakya
    • 3 years ago
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    Does it help?

  18. vishweshshrimali5
    • 3 years ago
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    and remember that \[\large log_a a = 1\]

  19. yeller33
    • 3 years ago
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    x=2//7?? ( 7x=2 )

  20. vishweshshrimali5
    • 3 years ago
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    Thus u can write 2 = 2* 1 = \(\large 2* log_{10} 10\) also

  21. sauravshakya
    • 3 years ago
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    log7 + logx=2 log(7*x)=2 10^2 = 7*x 100/7=x

  22. vishweshshrimali5
    • 3 years ago
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    \[\large b\space log _a x = log_a (b^x)\]

  23. vishweshshrimali5
    • 3 years ago
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    That's how @sauravshakya got the third step

  24. sauravshakya
    • 3 years ago
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    got it? @yeller33

  25. vishweshshrimali5
    • 3 years ago
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    i can write 2 = \(\large \log_{10} (10^2)\)

  26. sauravshakya
    • 3 years ago
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    Yep @vishweshshrimali5

  27. vishweshshrimali5
    • 3 years ago
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    :)

  28. sauravshakya
    • 3 years ago
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    log7 + logx=2 log(7*x)=2 1/2 log(7x)=1 log{(7x)^1/2} = log10 (7x)^(1/2) = 10 7x = 100 x=100/7

  29. sauravshakya
    • 3 years ago
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    according to @vishweshshrimali5

  30. yeller33
    • 3 years ago
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    can you two see if i did this one correctly: logx+log8=1 log8*logx=1 8x=1 8x=10^1 10/8

  31. yeller33
    • 3 years ago
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    i tried to follow your explanations.

  32. sauravshakya
    • 3 years ago
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    dont think so

  33. sauravshakya
    • 3 years ago
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    your second step is wrong

  34. sauravshakya
    • 3 years ago
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    logx+log8= log8x

  35. sauravshakya
    • 3 years ago
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    and 1=log10

  36. sauravshakya
    • 3 years ago
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    got your mistake?

  37. yeller33
    • 3 years ago
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    i think so . thanks again!

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