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shitol007

  • 3 years ago

write a function that takes a name as parameter and return the number of day in that months

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  1. coolbird143
    • 3 years ago
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    name are you asking to accept month's name ?

  2. shitol007
    • 3 years ago
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    yes

  3. coolbird143
    • 3 years ago
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    int function ( string temp ) { switch ( temp ) { case "january" : return 1; break; case "February" : return 2; break; case "march" : return 3; break; case "April" : return 4; break; . . . . default : return 0; }

  4. ktobah
    • 3 years ago
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    He said returns the number of days in that month, so for January for example it will be : case "january" : return 31; Good luck.

  5. RoamingBlue
    • 3 years ago
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    Though you'll need some extra logic for February (to account for leap year) - Step 1 - If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5. - Step 2 - If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4. - Step 3 - If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5. - Step 4 - The year is a leap year (it has 366 days). - Step 5 - The year is not a leap year (it has 365 days).

  6. PurpleNose
    • 3 years ago
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    cases January, March, May, July, August, October, December all have 31 days, so they can be nested. case February has either 28 or 29. the default would be 30.

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