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 2 years ago
write a function that takes a name as parameter and return the number of day in that months
 2 years ago
write a function that takes a name as parameter and return the number of day in that months

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coolbird143
 2 years ago
Best ResponseYou've already chosen the best response.0name are you asking to accept month's name ?

coolbird143
 2 years ago
Best ResponseYou've already chosen the best response.0int function ( string temp ) { switch ( temp ) { case "january" : return 1; break; case "February" : return 2; break; case "march" : return 3; break; case "April" : return 4; break; . . . . default : return 0; }

ktobah
 2 years ago
Best ResponseYou've already chosen the best response.0He said returns the number of days in that month, so for January for example it will be : case "january" : return 31; Good luck.

RoamingBlue
 2 years ago
Best ResponseYou've already chosen the best response.1Though you'll need some extra logic for February (to account for leap year)  Step 1  If the year is evenly divisible by 4, go to step 2. Otherwise, go to step 5.  Step 2  If the year is evenly divisible by 100, go to step 3. Otherwise, go to step 4.  Step 3  If the year is evenly divisible by 400, go to step 4. Otherwise, go to step 5.  Step 4  The year is a leap year (it has 366 days).  Step 5  The year is not a leap year (it has 365 days).

PurpleNose
 2 years ago
Best ResponseYou've already chosen the best response.1cases January, March, May, July, August, October, December all have 31 days, so they can be nested. case February has either 28 or 29. the default would be 30.
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