## saifoo.khan 2 years ago Question:

1. saifoo.khan
2. mukushla

8?

3. Spacelimbus

$f(x) =125 \left( \frac{2}{5}\right)^x$ or am I too blue-eyed about this problem ?

4. saifoo.khan

How? Why?

5. ghazi

3.2

6. Yahoo!

3.2

7. Spacelimbus

yes, 3.2 for x=4

8. Spacelimbus

except of course this is something physical I fail to understand (-:

9. mukushla

lol...everybody got it except me..:D

10. ghazi

every time it bounces 2/5 of it's original height..but first bounce is counted when it went 125 inches

11. Yahoo!

125 *(2/5)^4

12. ghazi

and after that you need to count for four more

13. Yahoo!

@saifoo.khan Do u have the answer key

14. saifoo.khan

why are we inserting 4? Why not 3?

15. saifoo.khan

@Yahoo! , nope.

16. saifoo.khan

Because the first bounce has already happened. We are left with 3 of them now?

17. Spacelimbus

hmm, you have a point there @saifoo.khan

18. saifoo.khan

So @mukushla we correct? :D

19. ghazi

because question asked for four bounces after the ball dropped

20. saifoo.khan

"After the first bounce " it reaches the height of 125 @ghazi

21. Yahoo!

Yup.....@mukushla was correct

22. Spacelimbus

Yes I guess my interpretation of that text is flawed it is x=3, which are four bounces, for x=0 initial bounce at a height of 125

23. saifoo.khan

Yep!

24. saifoo.khan

So medals for Muk?

25. ghazi

agreed...!!

26. Spacelimbus

Funny formula in general, according to it the ball can do more than one hundred bounces :D Clearly a real world phenomenon!

27. saifoo.khan

Hehe. Thanks all.

28. ghazi

not only hundred ...it can go infinite theoretically