The diagonals of a square each measure 7 feet. Find the are of the square

- anonymous

The diagonals of a square each measure 7 feet. Find the are of the square

- schrodinger

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- anonymous

@Loujoelou

- ajprincess

|dw:1345312296169:dw|
Use pythagoras theorem
\(a^2+a^2=7^2\)
\(2a^2=49\)
Area=\(a^2\)
find \(a^2\) from \(2a^2=49\)

- anonymous

So 2a=49 and then divide both sides eright?

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## More answers

- anonymous

or just leave thats cool too lol

- ajprincess

ya divide by 2 to find a^2

- anonymous

divide the diagonal by \(\sqrt{2}\) to get the length of the side, then square the result

- anonymous

ok gotchu Next question.
Two sqaure are similar. The ratio of a set of sides is 2:4. whatis the ratio of their area?

- anonymous

if you call the diagonal \(d\) then the length of the side is \(\frac{d}{\sqrt{2}}\) and area is \(\frac{d^2}{2}\)

- anonymous

- anonymous

|dw:1345313796722:dw|
This is what the information gives us so far. It splits our square into 2 triangles and we can do pythageoren theorem what the sides are.
A^2+B^2=7^2. is the formula for the pythageroen theorem.
A^2+B^2=49. We simplified this here. They are both the same thing however because the sides of a square are equal so we really have 2A^2=49.
We divide both sides by 2, and get A^2=24.5
Now we have to do the opposite of squaring, and that's square root. Now we have
A^2= \[\sqrt{24.5} \]
This is one side of the square, and we would do \[\sqrt{24.5}*\sqrt{24.5}\] to get our area of this square

- anonymous

Lol i got the answer xD thanks man :)
Next question
Two sqaure are similar. The ratio of a set of sides is 2:4. whatis the ratio of their area?

- anonymous

|dw:1345314609037:dw| with the info. above, that's what we get and for the first square, let's find the area. Area= 2*2; Area=4. So that means for our 1st square we have an area of 4. Now we do the same for the 2nd square, we do Area= 4*4; Area=16. That means the area of both squares is 4 & 16. We put this into a ratio, and we have 4:16, which can be simplified to 1:4 if needed.

- anonymous

lol wow haha i wanted to make another question so i could give you another medal haha

- anonymous

Lol medals don't really matter that much to me. :) I enjoy helping others a lot more :D

- anonymous

hah ok so we will stay here <3

- anonymous

@Loujoelou

- anonymous

sure no prob. :)

- anonymous

There you goo @Loujoelou

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- anonymous

if your yhere haha

- anonymous

I'm still here. :) Give me a bit of time to solve :D

- anonymous

ok :)

- anonymous

K. so yeah that's the square and you labelled it corretly :). We would do the same thing as we would with regular numbers, and we will multiply (2x+10)(4), and that would give us 8x+40=80. Do you know how to do the rest? :)

- anonymous

8x+40=80
-40 -40
8x=40
x=5<3

- anonymous

am i right?

- anonymous

Yep good job!! :)

- anonymous

and if you wanted to double check this problem, you would put x back into the probolv e. 5 and solve. (2(5)+10)=20, and 20*4=80 so this would be correct :)

- anonymous

problem as*

- anonymous

iight hold on i have to right the next one again <3

- anonymous

K and hey you got nice handwriting.

- anonymous

haha ik all the girls love it <3

- anonymous

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- anonymous

K :) All you would do here, is find the area of the bigger rectangle first. 200*140=28000. Now we find the area of the pool. 30*15=450. Finally all we do is subtract them, 28000-450=answer ft.^2

- anonymous

Thank you soo Much <3

- anonymous

Let me plug in the answers into my hw brb give me a minute

- anonymous

No prob. :) and okay :)

- anonymous

So the answer is 27,550ft^2?

- anonymous

Yeah :)

- anonymous

Thank you :) hold on i have to look for another Hw page

- anonymous

do you do virtual school o.O?

- anonymous

yes hahah

- anonymous

Find the area of a rhombus with diagonals of 4ft and 5ft . :)
But im done wit virtual school im doing hw now

- anonymous

@Loujoelou

- anonymous

Oh okay I do some virtual school as well :)

- anonymous

cools xD

- anonymous

Find the area of a rhombus with diagonals of 4ft and 5ft . :)

- anonymous

if ur there xD

- anonymous

K so all we do is D1*D2/2=Area. D1=Diagonal 1 & D2= Diagonal 2

- anonymous

4*5/2=your answer :)

- anonymous

so 4*5 =20/2=10 xD right?

- anonymous

Yep :)

- anonymous

Hahah Yeahhh xD
Find the base of the parallelogram that has an area of 228meters squared and has a hheight of 12meters

- anonymous

BRB GIVE ME A COUPLE OF mINUTES OK <3

- anonymous

K :)

- anonymous

@eAnthonyR

- anonymous

YAYYYY xD ahah :p

- anonymous

Find the base of the parallelogram that has an area of 228meters squared and has a hheight of 12meters
If you dont mind xD

- anonymous

K so the formula of a parallelogram is Area=Base*Height. From the info above, we got 228=b*12. Can you find the base now? :)

- anonymous

Divide right :)?

- anonymous

Yep. divide 12 on both sides and get b=228/12

- anonymous

Find the missing diagonal of the rhombus that has an area of 12 feet sqaures and one diagonal of 6ft.
If you may can you explain this one to me so i can understand alittle bit

- anonymous

K. To find the area of a rhombus we do D1+D2/2=Area. The D1/2 are the diagonals. Using the info. we have we get 6+D2/2=12

- anonymous

So do we subtract 12-6? and then thats the D2?

- anonymous

No, here we multiply the 2 on both sides, so we get 6+D2=24. Then we subtract both sides by 6 and get D2=18 :)

- anonymous

- anonymous

Ohhhh we multiply? Ok ok

- anonymous

wait but 18 isnt an answer ..

- anonymous

Wait whoops yeah I made a mistake sry let me see.

- anonymous

lol ok <3 its ok xD

- anonymous

No wait if we double-check what we got, in the formula D1+D2/2=12 and put 6 & 18 in, 18+6/2=12;24/2=12;12=12 it's right.

- anonymous

thats weird cause 18 isnt an answer hold on maybe i made a mistake

- anonymous

What are the choices?

- anonymous

4
6
8
2

- anonymous

Nope i didnt make a mistake

- anonymous

I can't seem to find what I did wrong sry. :/ Try posting it as a question, other help you on that one.

- anonymous

i posted it xD

- anonymous

join it

- anonymous

Then once we find out what that one is I can help you w/ another one okay?

- anonymous

okkk :)

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