eAnthonyR
The diagonals of a square each measure 7 feet. Find the are of the square
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eAnthonyR
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@Loujoelou
ajprincess
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|dw:1345312296169:dw|
Use pythagoras theorem
\(a^2+a^2=7^2\)
\(2a^2=49\)
Area=\(a^2\)
find \(a^2\) from \(2a^2=49\)
eAnthonyR
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So 2a=49 and then divide both sides eright?
eAnthonyR
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or just leave thats cool too lol
ajprincess
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ya divide by 2 to find a^2
anonymous
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divide the diagonal by \(\sqrt{2}\) to get the length of the side, then square the result
eAnthonyR
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ok gotchu Next question.
Two sqaure are similar. The ratio of a set of sides is 2:4. whatis the ratio of their area?
anonymous
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if you call the diagonal \(d\) then the length of the side is \(\frac{d}{\sqrt{2}}\) and area is \(\frac{d^2}{2}\)
eAnthonyR
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ok gotchu Next question.
Two sqaure are similar. The ratio of a set of sides is 2:4. whatis the ratio of their area?
Loujoelou
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|dw:1345313796722:dw|
This is what the information gives us so far. It splits our square into 2 triangles and we can do pythageoren theorem what the sides are.
A^2+B^2=7^2. is the formula for the pythageroen theorem.
A^2+B^2=49. We simplified this here. They are both the same thing however because the sides of a square are equal so we really have 2A^2=49.
We divide both sides by 2, and get A^2=24.5
Now we have to do the opposite of squaring, and that's square root. Now we have
A^2= \[\sqrt{24.5} \]
This is one side of the square, and we would do \[\sqrt{24.5}*\sqrt{24.5}\] to get our area of this square
eAnthonyR
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Lol i got the answer xD thanks man :)
Next question
Two sqaure are similar. The ratio of a set of sides is 2:4. whatis the ratio of their area?
Loujoelou
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|dw:1345314609037:dw| with the info. above, that's what we get and for the first square, let's find the area. Area= 2*2; Area=4. So that means for our 1st square we have an area of 4. Now we do the same for the 2nd square, we do Area= 4*4; Area=16. That means the area of both squares is 4 & 16. We put this into a ratio, and we have 4:16, which can be simplified to 1:4 if needed.
eAnthonyR
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lol wow haha i wanted to make another question so i could give you another medal haha
Loujoelou
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Lol medals don't really matter that much to me. :) I enjoy helping others a lot more :D
eAnthonyR
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hah ok so we will stay here <3
eAnthonyR
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@Loujoelou
Loujoelou
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sure no prob. :)
eAnthonyR
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There you goo @Loujoelou
eAnthonyR
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if your yhere haha
Loujoelou
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I'm still here. :) Give me a bit of time to solve :D
eAnthonyR
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ok :)
Loujoelou
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K. so yeah that's the square and you labelled it corretly :). We would do the same thing as we would with regular numbers, and we will multiply (2x+10)(4), and that would give us 8x+40=80. Do you know how to do the rest? :)
eAnthonyR
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8x+40=80
-40 -40
8x=40
x=5<3
eAnthonyR
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am i right?
Loujoelou
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Yep good job!! :)
Loujoelou
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and if you wanted to double check this problem, you would put x back into the probolv e. 5 and solve. (2(5)+10)=20, and 20*4=80 so this would be correct :)
Loujoelou
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problem as*
eAnthonyR
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iight hold on i have to right the next one again <3
Loujoelou
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K and hey you got nice handwriting.
eAnthonyR
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haha ik all the girls love it <3
eAnthonyR
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Loujoelou
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K :) All you would do here, is find the area of the bigger rectangle first. 200*140=28000. Now we find the area of the pool. 30*15=450. Finally all we do is subtract them, 28000-450=answer ft.^2
eAnthonyR
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Thank you soo Much <3
eAnthonyR
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Let me plug in the answers into my hw brb give me a minute
Loujoelou
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No prob. :) and okay :)
eAnthonyR
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So the answer is 27,550ft^2?
Loujoelou
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Yeah :)
eAnthonyR
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Thank you :) hold on i have to look for another Hw page
Loujoelou
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do you do virtual school o.O?
eAnthonyR
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yes hahah
eAnthonyR
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Find the area of a rhombus with diagonals of 4ft and 5ft . :)
But im done wit virtual school im doing hw now
eAnthonyR
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@Loujoelou
Loujoelou
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Oh okay I do some virtual school as well :)
eAnthonyR
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cools xD
eAnthonyR
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Find the area of a rhombus with diagonals of 4ft and 5ft . :)
eAnthonyR
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if ur there xD
Loujoelou
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K so all we do is D1*D2/2=Area. D1=Diagonal 1 & D2= Diagonal 2
Loujoelou
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4*5/2=your answer :)
eAnthonyR
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so 4*5 =20/2=10 xD right?
Loujoelou
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Yep :)
eAnthonyR
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Hahah Yeahhh xD
Find the base of the parallelogram that has an area of 228meters squared and has a hheight of 12meters
eAnthonyR
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BRB GIVE ME A COUPLE OF mINUTES OK <3
Loujoelou
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K :)
Loujoelou
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@eAnthonyR
eAnthonyR
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YAYYYY xD ahah :p
eAnthonyR
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Find the base of the parallelogram that has an area of 228meters squared and has a hheight of 12meters
If you dont mind xD
Loujoelou
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K so the formula of a parallelogram is Area=Base*Height. From the info above, we got 228=b*12. Can you find the base now? :)
eAnthonyR
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Divide right :)?
Loujoelou
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Yep. divide 12 on both sides and get b=228/12
eAnthonyR
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Find the missing diagonal of the rhombus that has an area of 12 feet sqaures and one diagonal of 6ft.
If you may can you explain this one to me so i can understand alittle bit
Loujoelou
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K. To find the area of a rhombus we do D1+D2/2=Area. The D1/2 are the diagonals. Using the info. we have we get 6+D2/2=12
eAnthonyR
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So do we subtract 12-6? and then thats the D2?
Loujoelou
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No, here we multiply the 2 on both sides, so we get 6+D2=24. Then we subtract both sides by 6 and get D2=18 :)
Loujoelou
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No, here we multiply the 2 on both sides, so we get 6+D2=24. Then we subtract both sides by 6 and get D2=18 :)
eAnthonyR
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Ohhhh we multiply? Ok ok
eAnthonyR
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wait but 18 isnt an answer ..
Loujoelou
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Wait whoops yeah I made a mistake sry let me see.
eAnthonyR
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lol ok <3 its ok xD
Loujoelou
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No wait if we double-check what we got, in the formula D1+D2/2=12 and put 6 & 18 in, 18+6/2=12;24/2=12;12=12 it's right.
eAnthonyR
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thats weird cause 18 isnt an answer hold on maybe i made a mistake
Loujoelou
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What are the choices?
eAnthonyR
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4
6
8
2
eAnthonyR
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Nope i didnt make a mistake
Loujoelou
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I can't seem to find what I did wrong sry. :/ Try posting it as a question, other help you on that one.
eAnthonyR
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i posted it xD
eAnthonyR
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join it
Loujoelou
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Then once we find out what that one is I can help you w/ another one okay?
eAnthonyR
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okkk :)