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kiamonstaa

  • 3 years ago

Part 1: Solve each of the quadratic equations below. Show your work. x2 – 36 = 0 and x2 = 8x – 12 Part 2: Describe what the solution(s) represent to the graph of each. Part 3: How are the graphs alike? How are they different?

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  1. Loujoelou
    • 3 years ago
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    K for part 1, all you have to know for the first problem is what factors when multiplied eqaul -36, do you know that? :)

  2. kiamonstaa
    • 3 years ago
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    ummm i want to say... 16 x 2

  3. kiamonstaa
    • 3 years ago
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    -16

  4. Loujoelou
    • 3 years ago
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    That doesn't equal -36 when multiplied, but -6*6 does :)

  5. kiamonstaa
    • 3 years ago
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    xd brain fart. i was thinking of some thing else.

  6. kiamonstaa
    • 3 years ago
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    so how would it be solved?

  7. Loujoelou
    • 3 years ago
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    Now all you would do is (x-6)(x+6) to factor the quadratic equation. Wait is that what you needed?

  8. kiamonstaa
    • 3 years ago
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    oh and how would you do the 2nd one?

  9. Loujoelou
    • 3 years ago
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    K so we have x^2= 8x-12. We can make this x^2-8x+12=0

  10. Loujoelou
    • 3 years ago
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    Now you need to find out what factors when multiplied to 12, add up to -8. Can you think of anY? :)

  11. kiamonstaa
    • 3 years ago
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    ohhh!! 4 -4?

  12. kiamonstaa
    • 3 years ago
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    sooo....(x+4) (x-4)

  13. Loujoelou
    • 3 years ago
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    Not necessarily. 4*-4=-16. We need two numbers like -6*-2 that equal 12 and add up to -8 :) Since those two numbers are it we can factor our quadratic equation as (x-6)(x-2)

  14. kiamonstaa
    • 3 years ago
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    oh....jumped the gun there. lol but thanks!!

  15. Loujoelou
    • 3 years ago
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    No problem :)

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