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urlilmami

  • 2 years ago

method of substitution 3a=5-b and 3a=2-b

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  1. Kaederfds
    • 2 years ago
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    i think that's just a wrong question, dude

  2. urlilmami
    • 2 years ago
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    use the method of substitution to solve the system of liner equations. 3a=5-b and 3a=2-b

  3. mathslover
    • 2 years ago
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    \[\large{3a=5-b\space ; 3a=2-b}\] \[\large{\color{red}{5-b=2-b}}\] \[\large{5-2=-b+b}\] \[\large{\color{blue}{3\ne 0}}\] hence no solutions

  4. urlilmami
    • 2 years ago
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    I thought you had to find the solution for one equation first

  5. mathslover
    • 2 years ago
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    what you say ok \[\large{\color{blue}{b=5-3a}}\] \[\large{\color{red}{3a=2-b}}\] \[\large{\color{green}{3a=2-5+3a}}\] \[\large{\color{orange}{3a=-3+3a}}\] \[\large{\color{brown}{0\ne -3}}\] no soln in this also

  6. mathslover
    • 2 years ago
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    got it @urlilmami ?

  7. lgbasallote
    • 2 years ago
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    lol @mathslover your posts really trigger epileptic shocks =))))

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