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Answer (i) 1 mole of C2H6 contains 2 moles of carbon atoms. Number of moles of carbon atoms in 3 moles of C2H6 = 2 × 3 = 6 (ii) 1 mole of C2H6 contains 6 moles of hydrogen atoms. Number of moles of carbon atoms in 3 moles of C2H6 = 3 × 6 = 18 (iii) 1 mole of C2H6 contains 6.023 × 10^23 molecules of ethane. Number of molecules in 3 moles of C2H6 = 3 × 6.023 × 10^23 = 18.069 × 10^23
what about atoms ?
have you copy pasted it @hanah ?
u have to find mole not atom
i know that .. i want for atoms too !
can you explain this ?
i had already checked the link .. only then did i come to open study
i didn't understand that .. so can you explain ?
its just as simple just multiply 3 as given in your question with the number of mole present in the formula of ethane
She is right.. But it seems you are not satisfied or you did not get that ?? Right??
See I give you another example so that you get some understanding: See; Let suppose we have Water (already you have too) \(H_2O\) Now tell me how many H and O are there ??
does that mean whenever the qn is find the moles i should multiply the given atoms with the number of moles present ? EVERY TIME ?
Wait go slow... I explain you everything.. Just tell me what I asked..
2 H and 1 O
If you look Atom wise: Then there are two atoms of H and one atom of O Right ??
So: For two H. there are 2 mole of H atom For one H there are 1 mole of H atom This is according to the atoms present in \(H_2O\).. Getting ??
Okay now moving forward: This is for single \(H_2O\) What if I said : for \(2 H_2O\)
4 H and 2 O ?
Yes.. So 4 moles of H and 2 moles of O..
Similarly in your question: you can just understand your question as : \(3(C_2H_4)\) How many C and H are there ??
6 C and 12 H
Sorry for \(C_2H_6\)..
okay 18 H
Yes now you are right.
is it just C2H6 OR 3(C2H6)
Ethane is just : \(C_2H_6\)
But you are given 3 moles of it : 3 Moles of \(C_2H_6\)
So you can write it as : \(C_2H_6 + C_2H_6 + C_2H_6 = 3 C_2H_6\)
oh okay .. understood .. so any qn like this ..i shud follow the same steps right ?
@hanah and @waterineyes thanks :)
Yes.. For calculating atoms in the molecule we follow the same steps..
Understood ?? c part you can do or not ??
yes that i know :)
can you see that in nana3456 you are still typing something ?
or is it just my comp wch makes me see like that ?
I am wondering by seeing that..
See this site stopped working for me when I was typing that reply.. Ha ha ha.
:P .. from the morning you are typing something and i were wondering why you wern't entering it :P
At that time I was replying to Nana and this site did not work properly for me then.. Sorry I could not reply to you..
its okay :)