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- anonymous

The local radio station is giving away some tickets to the circus.Adult tickets cost the station $ 8 each while children's tickets cost $6. The station wants to spend no more than $172. Let x = the number of adult tickets and y= the number of children's tickets. show all possible solutions by graphing a linear inequality.

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- anonymous

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- ParthKohli

I have some hints in store.
- The money that they spend will be the \(\textbf{sum}\) of the money they spend on children and adults.
- The money that they spend on guys will be \(\text{number of guys} \times \text{money for 1 guy}\).
- The inequality sign that you use is less than or equal to/\(\le\)

- anonymous

thank. how to graphing

- ParthKohli

http://wolframalpha.com will help.
Note that I am not the best teacher when it comes to graphing... :(

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- sasogeek

x=number of adult tickets
adult tickets cost $8
hence total amount in $ of adult tickets = $8x
y=number of children tickets
children tickets cost $6
hence total amount in $ of children tickets = $6y
the total of these tickets if all are sold should be equal to or less that how much is on budget that the radio station wants to spend, aka $172.
hence,
8x + 6y \(\le \) 172

- sasogeek

does the above logic make any sense?

- anonymous

Thank you for answer

- sasogeek

can you graph that?

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