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The local radio station is giving away some tickets to the circus.Adult tickets cost the station $ 8 each while children's tickets cost $6. The station wants to spend no more than $172. Let x = the number of adult tickets and y= the number of children's tickets. show all possible solutions by graphing a linear inequality.
 one year ago
 one year ago
The local radio station is giving away some tickets to the circus.Adult tickets cost the station $ 8 each while children's tickets cost $6. The station wants to spend no more than $172. Let x = the number of adult tickets and y= the number of children's tickets. show all possible solutions by graphing a linear inequality.
 one year ago
 one year ago

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ParthKohliBest ResponseYou've already chosen the best response.0
I have some hints in store.  The money that they spend will be the \(\textbf{sum}\) of the money they spend on children and adults.  The money that they spend on guys will be \(\text{number of guys} \times \text{money for 1 guy}\).  The inequality sign that you use is less than or equal to/\(\le\)
 one year ago

ParthKohliBest ResponseYou've already chosen the best response.0
http://wolframalpha.com will help. Note that I am not the best teacher when it comes to graphing... :(
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
x=number of adult tickets adult tickets cost $8 hence total amount in $ of adult tickets = $8x y=number of children tickets children tickets cost $6 hence total amount in $ of children tickets = $6y the total of these tickets if all are sold should be equal to or less that how much is on budget that the radio station wants to spend, aka $172. hence, 8x + 6y \(\le \) 172
 one year ago

sasogeekBest ResponseYou've already chosen the best response.2
does the above logic make any sense?
 one year ago
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