## ongmon 3 years ago The local radio station is giving away some tickets to the circus.Adult tickets cost the station $8 each while children's tickets cost$6. The station wants to spend no more than $172. Let x = the number of adult tickets and y= the number of children's tickets. show all possible solutions by graphing a linear inequality. • This Question is Closed 1. ParthKohli I have some hints in store. - The money that they spend will be the $$\textbf{sum}$$ of the money they spend on children and adults. - The money that they spend on guys will be $$\text{number of guys} \times \text{money for 1 guy}$$. - The inequality sign that you use is less than or equal to/$$\le$$ 2. ongmon thank. how to graphing 3. ParthKohli http://wolframalpha.com will help. Note that I am not the best teacher when it comes to graphing... :( 4. sasogeek x=number of adult tickets adult tickets cost$8 hence total amount in $of adult tickets =$8x y=number of children tickets children tickets cost $6 hence total amount in$ of children tickets = $6y the total of these tickets if all are sold should be equal to or less that how much is on budget that the radio station wants to spend, aka$172. hence, 8x + 6y $$\le$$ 172

5. sasogeek

does the above logic make any sense?

6. ongmon