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tej18
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[9.05] Part 1: Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Identify the values of a, b, and c, and find the solutions using the quadratic formula. Show all work to receive credit.
Part 2: Using complete sentences, explain how you know that the equation from Part 1 cannot be solved by factoring, but can be solved by using the quadratic formula.
 2 years ago
 2 years ago
tej18 Group Title
[9.05] Part 1: Create your own quadratic equation that cannot be solved by factoring, but can be solved using the quadratic formula. Identify the values of a, b, and c, and find the solutions using the quadratic formula. Show all work to receive credit. Part 2: Using complete sentences, explain how you know that the equation from Part 1 cannot be solved by factoring, but can be solved by using the quadratic formula.
 2 years ago
 2 years ago

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tej18 Group TitleBest ResponseYou've already chosen the best response.0
i need help i am confused :(
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
x^2  x  7 = 0 a = 1, b = 1 and c = 7 subvstitute these values in the formula x =[ b + sqrt(b^2  4ac) ] / 2a and x =[ b  sqrt(b^2  4ac) ] / 2a to find the solutions
 2 years ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
can you do that?
 2 years ago

tej18 Group TitleBest ResponseYou've already chosen the best response.0
can i just have the answer cause my cousin is doing an online course and she needs help
 2 years ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
@cwrw238
 one year ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
i took your advice and it helped me so much
 one year ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
i got 3.195 and 2.195 are those right
 one year ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
is it
 one year ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
thank you so much you helped me immensely. can i ask your help for more questions in a couple of minutes.
 one year ago

cwrw238 Group TitleBest ResponseYou've already chosen the best response.2
i have to do some chores for a while but i'll be able to help in about 10 minutes
 one year ago

mathgirl2012 Group TitleBest ResponseYou've already chosen the best response.0
ok thx so much you helped me get 100 percent
 one year ago
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