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anonymous
 4 years ago
How can u tell whether these lines are parallel or perpendicular or neither with out graphing?
line 1; through (1,9) and (6,6)
line 2; through (7,23) and (0,2)
anonymous
 4 years ago
How can u tell whether these lines are parallel or perpendicular or neither with out graphing? line 1; through (1,9) and (6,6) line 2; through (7,23) and (0,2)

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(1,9) and (6,6) : slope =3 (7,23) and (0,2): slope=3 same slope means lines are parallel

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0how did you figure that out with out graphing?

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.0there is a formula to find the slope of line with 2 points given....

radar
 4 years ago
Best ResponseYou've already chosen the best response.0They calculated the slope of each line using \[\Delta y \over \Delta x\] When the slopes are equal to each other (in this case they were both 3) they are parallel. If they were negative reciprocals like one was 3 and the other 1/3. then they would of been perpendicular.

hartnn
 4 years ago
Best ResponseYou've already chosen the best response.0for perpendicular,slopes must be negative inverse

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@radar I used that method....sorry for nothing showing my work.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ohhhh. okay i got it. and its okay @RyanL.

radar
 4 years ago
Best ResponseYou've already chosen the best response.0@RyanL, good work, I was just trying to assist. I want to explain what a negative reciprocal is, because by the questions being submitted he is going to need to understand that too.

radar
 4 years ago
Best ResponseYou've already chosen the best response.0One number is a negative reciprocal of another number if their product is 1.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0its alright.. and okay thanks.. again. lol
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