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How can u tell whether these lines are parallel or perpendicular or neither with out graphing?
line 1; through (1,9) and (6,6)
line 2; through (7,23) and (0,2)
 one year ago
 one year ago
How can u tell whether these lines are parallel or perpendicular or neither with out graphing? line 1; through (1,9) and (6,6) line 2; through (7,23) and (0,2)
 one year ago
 one year ago

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RyanL.Best ResponseYou've already chosen the best response.1
(1,9) and (6,6) : slope =3 (7,23) and (0,2): slope=3 same slope means lines are parallel
 one year ago

marird15Best ResponseYou've already chosen the best response.1
how did you figure that out with out graphing?
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
there is a formula to find the slope of line with 2 points given....
 one year ago

radarBest ResponseYou've already chosen the best response.0
They calculated the slope of each line using \[\Delta y \over \Delta x\] When the slopes are equal to each other (in this case they were both 3) they are parallel. If they were negative reciprocals like one was 3 and the other 1/3. then they would of been perpendicular.
 one year ago

hartnnBest ResponseYou've already chosen the best response.0
for perpendicular,slopes must be negative inverse
 one year ago

RyanL.Best ResponseYou've already chosen the best response.1
@radar I used that method....sorry for nothing showing my work.
 one year ago

marird15Best ResponseYou've already chosen the best response.1
ohhhh. okay i got it. and its okay @RyanL.
 one year ago

radarBest ResponseYou've already chosen the best response.0
@RyanL, good work, I was just trying to assist. I want to explain what a negative reciprocal is, because by the questions being submitted he is going to need to understand that too.
 one year ago

radarBest ResponseYou've already chosen the best response.0
One number is a negative reciprocal of another number if their product is 1.
 one year ago

marird15Best ResponseYou've already chosen the best response.1
its alright.. and okay thanks.. again. lol
 one year ago
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