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are u sure about your question,because it has one negative irrational root and 2 complex conjugate roots...
yeah i am sure
it seems it's an application of the rational roots theorem and factor theorem...
can u tell me the methodology to factorise cubic equations?
1. Find one of the factors (maybe use rational roots theorem) 2. Divide the polynomial by that factor (the quotient will be a quadratic equation) 3. Factor out that quadratic equation (maybe using quadratic formula) that's how i do it...
i do follow that method !!! but then that doesn't get worked out for this prob
maybe it's prime then? could be...
yeahhh...wolfram cant factor it either :(
..well it can. but it isnt pretty
even wolfram giving -1.5986 and 1.8+/-0.718 i ??
yeah bt then i want that solved step by step...i wanted to knw how did they start
one thing's for sure...it wasnt algebra
wat abt this prob : : x^3-2x^2-2x+6
these are actually a part of a big ques... so it ought to be solved to solve the big prob!
its the same problem...
i only see it like x((x-2)x-2)+6