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hang254

  • 3 years ago

A=1/2h (b1 + b2) for b2

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  1. hal_stirrup
    • 3 years ago
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    whats your Q????

  2. hang254
    • 3 years ago
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    the one above

  3. kiamonstaa
    • 3 years ago
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    you need numbers or something

  4. hal_stirrup
    • 3 years ago
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    ?????

  5. hang254
    • 3 years ago
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    all it says is solve for the indicated variable. which appears to be b2

  6. hal_stirrup
    • 3 years ago
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    \[A=\frac{ 1 }{ 2h } (b1 + b2) \]

  7. hal_stirrup
    • 3 years ago
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    ok just to be clear i will multiply \[\frac{ 1 }{ 2h }\] by (b1+b2) we have A=b1/2h + b2/2h

  8. hang254
    • 3 years ago
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    ok, i am following you

  9. hal_stirrup
    • 3 years ago
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    to get rid of 2h on hte right side we multiply by 2h so >>> A(2h)=(2h)(b1/2h + b2/2h)

  10. hal_stirrup
    • 3 years ago
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    simplifying the equation we get>>>>> 2hA=b1+b2

  11. hal_stirrup
    • 3 years ago
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    are we clear??

  12. hang254
    • 3 years ago
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    yes, i am reading what u wrote right now

  13. hal_stirrup
    • 3 years ago
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    good

  14. hang254
    • 3 years ago
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    thanks

  15. hal_stirrup
    • 3 years ago
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    and finally 2hA-b1=b2.

  16. hang254
    • 3 years ago
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    thank you

  17. hal_stirrup
    • 3 years ago
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    your most welcome :)

  18. hal_stirrup
    • 3 years ago
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    try to think what operators you can use to get rid of fractions so you can simplify it.

  19. hang254
    • 3 years ago
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    ok. i will, thanks again

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