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hang254
 3 years ago
A=1/2h (b1 + b2) for b2
hang254
 3 years ago
A=1/2h (b1 + b2) for b2

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kiamonstaa
 3 years ago
Best ResponseYou've already chosen the best response.0you need numbers or something

hang254
 3 years ago
Best ResponseYou've already chosen the best response.0all it says is solve for the indicated variable. which appears to be b2

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1\[A=\frac{ 1 }{ 2h } (b1 + b2) \]

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1ok just to be clear i will multiply \[\frac{ 1 }{ 2h }\] by (b1+b2) we have A=b1/2h + b2/2h

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1to get rid of 2h on hte right side we multiply by 2h so >>> A(2h)=(2h)(b1/2h + b2/2h)

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1simplifying the equation we get>>>>> 2hA=b1+b2

hang254
 3 years ago
Best ResponseYou've already chosen the best response.0yes, i am reading what u wrote right now

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1and finally 2hAb1=b2.

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1your most welcome :)

hal_stirrup
 3 years ago
Best ResponseYou've already chosen the best response.1try to think what operators you can use to get rid of fractions so you can simplify it.

hang254
 3 years ago
Best ResponseYou've already chosen the best response.0ok. i will, thanks again
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