r= 2/3t+v , solve for t
Show work please, I'm stressing out on some of these problems... thanks :)

- anonymous

r= 2/3t+v , solve for t
Show work please, I'm stressing out on some of these problems... thanks :)

- schrodinger

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- anonymous

r=2/3t+v so to solve for T.. first take minus the V on both sides like this v-r=2/3t you following this??

- anonymous

next because we are solving for T we divide by 2/3 to get T my itself. so we have v-r/2/3=t

- anonymous

hope this helps...

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- anonymous

Thank you so much!

- anonymous

not a problem any questions before I leave?

- anonymous

I have one last problem thats bugging me and that is -14n+q=rt-4n, solve for n.

- anonymous

first what do you know already

- anonymous

do I need to subtract rt from both sides?

- anonymous

yes you can do that, but we to collect a like terms first

- anonymous

Oh! The -14n and the -4n can go together.

- anonymous

yes, but be careful here what happens with the sign when it crosses the equal? recall + becomes - and - becomes +

- anonymous

So, 18n+g=rt ?

- anonymous

that is correct

- anonymous

so now what do we need to get N standing alone?

- anonymous

hint look at the g.

- anonymous

subtract the g on both sides, leaving me with 18n=rt-g

- anonymous

yes

- anonymous

then divide by 18 to get n=rt-g/18 ?

- anonymous

Nice job

- anonymous

Thank you SO much! I understand it now! :D You're a lifesaver.

- anonymous

I want to be sure you understand so ask questions if you have any?

- anonymous

Okay, I have another problem that I know how to start off but not finish.
ax+z=aw -y
+y +y
And that gives me ax+z+y=aw And thats where I'm not sure where to go from there...

- anonymous

what are we solving for or what is the problem asking for?

- anonymous

whoops. the equation is ax+z=aw-y, solve for a. You add y on both sides giving you ax+z+y=aw. And then I don't know what else to do.

- anonymous

okay this one is more tricky, but do able

- anonymous

first let's look at the a terms here? are alike? no, but what we can do is them on side.

- anonymous

so you can do this ax+z+y=aw take the ax-aw and than take -z-y so you should have the following ax-aw=-z-y

- anonymous

got it?

- anonymous

yes.

- anonymous

this is where it is tricky what can we do with the a's here?

- anonymous

add the 2 a's to get 2a(wx)=-z-y ?

- anonymous

try factoring an a.

- anonymous

did you factor an A?

- anonymous

I don't understand again..

- anonymous

I have it 2a(wx)=-z-y ? from this point take the wx and divide by -z-y so therefore you would 2a=-z-y/wx next divide by 2 to get the a alone so you should have A=-z-y/2wx.

- anonymous

Okay thank you so much! I understand it now! :D

- anonymous

really make sure you understand ask questions plz if something isn't clear?

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