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Josizzle98 Group Title

r= 2/3t+v , solve for t Show work please, I'm stressing out on some of these problems... thanks :)

  • one year ago
  • one year ago

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  1. godorovg Group Title
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    r=2/3t+v so to solve for T.. first take minus the V on both sides like this v-r=2/3t you following this??

    • one year ago
  2. godorovg Group Title
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    next because we are solving for T we divide by 2/3 to get T my itself. so we have v-r/2/3=t

    • one year ago
  3. godorovg Group Title
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    hope this helps...

    • one year ago
  4. Josizzle98 Group Title
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    Thank you so much!

    • one year ago
  5. godorovg Group Title
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    not a problem any questions before I leave?

    • one year ago
  6. Josizzle98 Group Title
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    I have one last problem thats bugging me and that is -14n+q=rt-4n, solve for n.

    • one year ago
  7. godorovg Group Title
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    first what do you know already

    • one year ago
  8. Josizzle98 Group Title
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    do I need to subtract rt from both sides?

    • one year ago
  9. godorovg Group Title
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    yes you can do that, but we to collect a like terms first

    • one year ago
  10. Josizzle98 Group Title
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    Oh! The -14n and the -4n can go together.

    • one year ago
  11. godorovg Group Title
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    yes, but be careful here what happens with the sign when it crosses the equal? recall + becomes - and - becomes +

    • one year ago
  12. Josizzle98 Group Title
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    So, 18n+g=rt ?

    • one year ago
  13. godorovg Group Title
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    that is correct

    • one year ago
  14. godorovg Group Title
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    so now what do we need to get N standing alone?

    • one year ago
  15. godorovg Group Title
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    hint look at the g.

    • one year ago
  16. Josizzle98 Group Title
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    subtract the g on both sides, leaving me with 18n=rt-g

    • one year ago
  17. godorovg Group Title
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    yes

    • one year ago
  18. Josizzle98 Group Title
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    then divide by 18 to get n=rt-g/18 ?

    • one year ago
  19. godorovg Group Title
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    Nice job

    • one year ago
  20. Josizzle98 Group Title
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    Thank you SO much! I understand it now! :D You're a lifesaver.

    • one year ago
  21. godorovg Group Title
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    I want to be sure you understand so ask questions if you have any?

    • one year ago
  22. Josizzle98 Group Title
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    Okay, I have another problem that I know how to start off but not finish. ax+z=aw -y +y +y And that gives me ax+z+y=aw And thats where I'm not sure where to go from there...

    • one year ago
  23. godorovg Group Title
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    what are we solving for or what is the problem asking for?

    • one year ago
  24. Josizzle98 Group Title
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    whoops. the equation is ax+z=aw-y, solve for a. You add y on both sides giving you ax+z+y=aw. And then I don't know what else to do.

    • one year ago
  25. godorovg Group Title
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    okay this one is more tricky, but do able

    • one year ago
  26. godorovg Group Title
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    first let's look at the a terms here? are alike? no, but what we can do is them on side.

    • one year ago
  27. godorovg Group Title
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    so you can do this ax+z+y=aw take the ax-aw and than take -z-y so you should have the following ax-aw=-z-y

    • one year ago
  28. godorovg Group Title
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    got it?

    • one year ago
  29. Josizzle98 Group Title
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    yes.

    • one year ago
  30. godorovg Group Title
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    this is where it is tricky what can we do with the a's here?

    • one year ago
  31. Josizzle98 Group Title
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    add the 2 a's to get 2a(wx)=-z-y ?

    • one year ago
  32. godorovg Group Title
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    try factoring an a.

    • one year ago
  33. godorovg Group Title
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    did you factor an A?

    • one year ago
  34. Josizzle98 Group Title
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    I don't understand again..

    • one year ago
  35. godorovg Group Title
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    I have it 2a(wx)=-z-y ? from this point take the wx and divide by -z-y so therefore you would 2a=-z-y/wx next divide by 2 to get the a alone so you should have A=-z-y/2wx.

    • one year ago
  36. Josizzle98 Group Title
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    Okay thank you so much! I understand it now! :D

    • one year ago
  37. godorovg Group Title
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    really make sure you understand ask questions plz if something isn't clear?

    • one year ago
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