Open study

is now brainly

With Brainly you can:

  • Get homework help from millions of students and moderators
  • Learn how to solve problems with step-by-step explanations
  • Share your knowledge and earn points by helping other students
  • Learn anywhere, anytime with the Brainly app!

A community for students.

help me solve this DE please. (2x+y)dx - (3x+2y-2)dy=0

Engineering
See more answers at brainly.com
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Join Brainly to access

this expert answer

SEE EXPERT ANSWER

To see the expert answer you'll need to create a free account at Brainly

I think that you must start by simplifying. Find the derivative of (2x+y) with respect to x, and then find the derivative o f (3x+2y-2) with respect to y. Let's look at the derivative you want to take with respect to x, (2x+y). Since dx is of both terms, you must take the derivative of each term with respect to x. It's just like 2x dx + y dx, right? 2x = 2(x^1) So to do the derivative, you multiply the term by x's exponent (1), and then you finish by subtract 1 from that exponent (so it's 1-1). (1) (2(x^(1-1))) = (1) (2(x^0)) = (1) (2(1)) = (1) (2) = 2. y = y(1), and 1 is the result of anything to the zeroeth power - even x to the zeroeth power. y = y(x^0) So do the same thing. You multiply the term by x's exponent (0), and then you finish by subtract 1 from that exponent (so it's 0-1). (0) (y(x^(0-1))) You can stop when you see something multiplied by "0". The whole term is obviously 0. That's what it would come down to, anyway. So 2x dx is 2 and y dx is 0. So (2x + y)dx is (2+0) = 2. For your whole equation, you must finish 2 - (3x + 2y - 2)dy = 0 So for (3x + 2y - 2) you'll be looking at the exponents of y in each term. Do 3x dy, then 2y dy, then 2 dy. Then calculate what's left. Do that and you'll show that, by simplifying the left side of the original equation, it obviously equals the right side of the equation.

Not the answer you are looking for?

Search for more explanations.

Ask your own question

Other answers:

Not the answer you are looking for?

Search for more explanations.

Ask your own question