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## baddinlol Group Title Area under y = arctan(x) between x = 1 and x = 0 2 years ago 2 years ago

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1. baddinlol Group Title

I don't understand how to integrate arctan(x) by hand

2. lgbasallote Group Title

i think i remember it having something to do with integration by parts...

3. mukushla Group Title

yep

4. baddinlol Group Title

We have to somehow use the tan function though

5. baddinlol Group Title

It says use the fact that y=artan(x) is the inverse of y = tan(x) to calculate the area between x = 1 and x =0

6. baddinlol Group Title

Any ideas?

7. baddinlol Group Title

We can also graph it for a hint

8. baddinlol Group Title

But we haven't learned integration by parts yet

9. .Sam. Group Title

@baddinlol You have to use integration by parts here, $\int\limits \tan ^{-1}(x) \, dx$ $u=\tan^{-1}x~~~~~dv=dx \\ \\ du=\frac{1}{1+x^2} ~~~~~v=x$ $x \tan ^{-1}x-\int\limits \frac{x}{1+x^2} \, dx$ Then continue...