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baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I don't understand how to integrate arctan(x) by hand
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i think i remember it having something to do with integration by parts...
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
We have to somehow use the tan function though
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
It says use the fact that y=artan(x) is the inverse of y = tan(x) to calculate the area between x = 1 and x =0
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
Any ideas?
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
We can also graph it for a hint
 one year ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
But we haven't learned integration by parts yet
 one year ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
@baddinlol You have to use integration by parts here, \[\int\limits \tan ^{1}(x) \, dx\] \[u=\tan^{1}x~~~~~dv=dx \\ \\ du=\frac{1}{1+x^2} ~~~~~v=x\] \[x \tan ^{1}x\int\limits \frac{x}{1+x^2} \, dx\] Then continue...
 one year ago
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