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baddinlol Group TitleBest ResponseYou've already chosen the best response.0
I don't understand how to integrate arctan(x) by hand
 2 years ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
i think i remember it having something to do with integration by parts...
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
We have to somehow use the tan function though
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
It says use the fact that y=artan(x) is the inverse of y = tan(x) to calculate the area between x = 1 and x =0
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
Any ideas?
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
We can also graph it for a hint
 2 years ago

baddinlol Group TitleBest ResponseYou've already chosen the best response.0
But we haven't learned integration by parts yet
 2 years ago

.Sam. Group TitleBest ResponseYou've already chosen the best response.2
@baddinlol You have to use integration by parts here, \[\int\limits \tan ^{1}(x) \, dx\] \[u=\tan^{1}x~~~~~dv=dx \\ \\ du=\frac{1}{1+x^2} ~~~~~v=x\] \[x \tan ^{1}x\int\limits \frac{x}{1+x^2} \, dx\] Then continue...
 2 years ago
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