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baddinlolBest ResponseYou've already chosen the best response.0
I don't understand how to integrate arctan(x) by hand
 one year ago

lgbasalloteBest ResponseYou've already chosen the best response.0
i think i remember it having something to do with integration by parts...
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
We have to somehow use the tan function though
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
It says use the fact that y=artan(x) is the inverse of y = tan(x) to calculate the area between x = 1 and x =0
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
We can also graph it for a hint
 one year ago

baddinlolBest ResponseYou've already chosen the best response.0
But we haven't learned integration by parts yet
 one year ago

.Sam.Best ResponseYou've already chosen the best response.2
@baddinlol You have to use integration by parts here, \[\int\limits \tan ^{1}(x) \, dx\] \[u=\tan^{1}x~~~~~dv=dx \\ \\ du=\frac{1}{1+x^2} ~~~~~v=x\] \[x \tan ^{1}x\int\limits \frac{x}{1+x^2} \, dx\] Then continue...
 one year ago
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