## baddinlol Group Title Area under y = arctan(x) between x = 1 and x = 0 2 years ago 2 years ago

I don't understand how to integrate arctan(x) by hand

2. lgbasallote

i think i remember it having something to do with integration by parts...

3. mukushla

yep

We have to somehow use the tan function though

It says use the fact that y=artan(x) is the inverse of y = tan(x) to calculate the area between x = 1 and x =0

Any ideas?

We can also graph it for a hint

@baddinlol You have to use integration by parts here, $\int\limits \tan ^{-1}(x) \, dx$ $u=\tan^{-1}x~~~~~dv=dx \\ \\ du=\frac{1}{1+x^2} ~~~~~v=x$ $x \tan ^{-1}x-\int\limits \frac{x}{1+x^2} \, dx$ Then continue...