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\[\frac{ 5x ^{2}+9x-2 }{ x ^{2}+12x+20 } * \frac{ x ^{2}+17x+70 }{ 15x-3 }\]
can you factorize the respective numerators and denominators?
no, thats all i need help with & i can do the rest

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Other answers:

look for example at 5x^2+9x-2 look for 2 numbers whose product is -2*5=-10 and whose sum is 9
((x+2)(5x-1))/(x+10)(x+2)* ((x+7)(x+10)/3(5x-1) the way u apporach them is what numbers multiply to give lets say 70... well 7 and 10 . do they add to form the 17x yes cause 10 +7+17.
\[\frac{ (x+2)(5x+1) }{ (x+10)(x+2)} * \frac{ (x+10)(x+7) }{ 3(5x+1) }\] (5x+1) cancels (x + 10) cancels \[\frac{ x+2 }{ x+2 } * \frac{ x+7 }{ 3} = 1 * \frac{ x + 7 }{ 3 } = \frac{ x+7 }{ 3 }\] This, I cannot factor anymore.
can you help me with one more @Compassionate ?
great! .. hold on let me write it out
\[\frac{ x ^{2}+x-12 }{ x ^{2}-x-20 }\div \frac{ 3x ^{2}-24x+45 }{ 12x ^{2}-48x-60}\]
One sec, putting on music then I'll solve it. c:
okie dokie
Do you want me too factor it, or just give you the answer?
you can just give me the answer lol
Damn, this expression is walking all over me.
\[\frac{ (x+4)(x-3) }{ (x+4)(x-5) } - \frac{ 3(x-3)(x-5) }{ 4(3x^2-x-5) }\]
After this part I know what too do, I just can't figure out of to construct a common denominator.
okay thank you so much!

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