anonymous
  • anonymous
Am I correct?
Mathematics
schrodinger
  • schrodinger
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anonymous
  • anonymous
anonymous
  • anonymous
@hawkfalcon I clearly have an answer down, but I'm just double checking to see if it's correct. If you don't like it, please don't comment on my stuff.
hawkfalcon
  • hawkfalcon
Well each angle of a hexagon is 120 degrees, so you subtract that from 180 and divide by two. That should help:)

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anonymous
  • anonymous
So, 60 divided by 2?
hawkfalcon
  • hawkfalcon
Try that:p
anonymous
  • anonymous
Try? Haha.
hawkfalcon
  • hawkfalcon
I can't say yes can I? :P
anonymous
  • anonymous
@jim_thompson5910 I think it's 18, and hawk thinks it's 30. Help?
hawkfalcon
  • hawkfalcon
I gave you the logic behind my reasoning, and explained how to do it:O
hawkfalcon
  • hawkfalcon
Why do you think it is 18?
jim_thompson5910
  • jim_thompson5910
Draw out a hexagon |dw:1345587910416:dw|
anonymous
  • anonymous
But I have reasoning, too...
anonymous
  • anonymous
Sorry, computer is being dumb. -___-
jim_thompson5910
  • jim_thompson5910
And extend one of the sides |dw:1345587933732:dw|
jim_thompson5910
  • jim_thompson5910
That exterior angle is 360/6 = 60 degrees
hawkfalcon
  • hawkfalcon
|dw:1345587963358:dw|
jim_thompson5910
  • jim_thompson5910
So the interior angle (which is supplementary to it) is 180 - 60 = 120 degrees
jim_thompson5910
  • jim_thompson5910
So if x is that unknown angle you want to find, then x+120+x = 180 2x+120 = 180 2x = 180-120 2x = 60 x = 60/2 x = 30
hawkfalcon
  • hawkfalcon
@jim_thompson5910 thats exactly what I told her >.<
jim_thompson5910
  • jim_thompson5910
true, I'm just using x and doing it in an algebraic way
hawkfalcon
  • hawkfalcon
@Ashley10116 do you believe me now?:P
anonymous
  • anonymous
@hawkfalcon Yah, I just needed another opinion. Haha. You said "try that" which made me a bit uneasy.
hawkfalcon
  • hawkfalcon
x_x I didn't think I was allowed to say yes

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