hawkfalcon
  • hawkfalcon
factoring question
Mathematics
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hawkfalcon
  • hawkfalcon
factoring question
Mathematics
chestercat
  • chestercat
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hawkfalcon
  • hawkfalcon
\[5\cos^2x-5\sin^2x+cosx+sinx\]
anonymous
  • anonymous
I think you should use the quadratic formula
hawkfalcon
  • hawkfalcon
I have to factor it :P

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anonymous
  • anonymous
oh sorry
hawkfalcon
  • hawkfalcon
Its okay:3 Anyone?
hawkfalcon
  • hawkfalcon
:(
hawkfalcon
  • hawkfalcon
*crosses fingers*
anonymous
  • anonymous
\[5 \cdot \cos^{2}x-5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosx-sinx)+(sinx+cosx)\] and now \[5 \cdot \cos^{2}x-5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosx-sinx +1)\]
hawkfalcon
  • hawkfalcon
o.O Okay
anonymous
  • anonymous
if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor \[5a^2-5b^2+a+b\]
hawkfalcon
  • hawkfalcon
That makes sense
anonymous
  • anonymous
it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse
anonymous
  • anonymous
\[5a^2-5b^2+a+b=5(a+b)(a-b)+a+b=(5(a-b)+1)(a+b)\]
hawkfalcon
  • hawkfalcon
:D figured it out! I can do "5a2−5b2+a+b" :P
hawkfalcon
  • hawkfalcon
Thanks :)

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