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hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0\[5\cos^2x5\sin^2x+cosx+sinx\]

ILoveMath3006
 2 years ago
Best ResponseYou've already chosen the best response.0I think you should use the quadratic formula

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0I have to factor it :P

jarmvel
 2 years ago
Best ResponseYou've already chosen the best response.1\[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosxsinx)+(sinx+cosx)\] and now \[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosxsinx +1)\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor \[5a^25b^2+a+b\]

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse

satellite73
 2 years ago
Best ResponseYou've already chosen the best response.1\[5a^25b^2+a+b=5(a+b)(ab)+a+b=(5(ab)+1)(a+b)\]

hawkfalcon
 2 years ago
Best ResponseYou've already chosen the best response.0:D figured it out! I can do "5a2−5b2+a+b" :P
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