hawkfalcon
factoring question



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hawkfalcon
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\[5\cos^2x5\sin^2x+cosx+sinx\]

ILoveMath3006
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I think you should use the quadratic formula

hawkfalcon
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I have to factor it :P

ILoveMath3006
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oh sorry

hawkfalcon
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Its okay:3 Anyone?

hawkfalcon
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:(

hawkfalcon
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*crosses fingers*

jarmvel
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\[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosxsinx)+(sinx+cosx)\]
and now
\[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosxsinx +1)\]

hawkfalcon
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o.O Okay

anonymous
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if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor
\[5a^25b^2+a+b\]

hawkfalcon
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That makes sense

anonymous
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it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse

anonymous
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\[5a^25b^2+a+b=5(a+b)(ab)+a+b=(5(ab)+1)(a+b)\]

hawkfalcon
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:D figured it out! I can do "5a2−5b2+a+b" :P

hawkfalcon
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Thanks
:)