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hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
\[5\cos^2x5\sin^2x+cosx+sinx\]
 one year ago

ILoveMath3006 Group TitleBest ResponseYou've already chosen the best response.0
I think you should use the quadratic formula
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
I have to factor it :P
 one year ago

ILoveMath3006 Group TitleBest ResponseYou've already chosen the best response.0
oh sorry
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
Its okay:3 Anyone?
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
*crosses fingers*
 one year ago

jarmvel Group TitleBest ResponseYou've already chosen the best response.1
\[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosxsinx)+(sinx+cosx)\] and now \[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosxsinx +1)\]
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
o.O Okay
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor \[5a^25b^2+a+b\]
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
That makes sense
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse
 one year ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[5a^25b^2+a+b=5(a+b)(ab)+a+b=(5(ab)+1)(a+b)\]
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
:D figured it out! I can do "5a2−5b2+a+b" :P
 one year ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
Thanks :)
 one year ago
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