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hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
\[5\cos^2x5\sin^2x+cosx+sinx\]
 2 years ago

ILoveMath3006 Group TitleBest ResponseYou've already chosen the best response.0
I think you should use the quadratic formula
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
I have to factor it :P
 2 years ago

ILoveMath3006 Group TitleBest ResponseYou've already chosen the best response.0
oh sorry
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
Its okay:3 Anyone?
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
*crosses fingers*
 2 years ago

jarmvel Group TitleBest ResponseYou've already chosen the best response.1
\[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(cosx+sinx)(cosxsinx)+(sinx+cosx)\] and now \[5 \cdot \cos^{2}x5 \cdot \sin^{2}x +sinx+cosx=5\cdot(sinx+cosx)(cosxsinx +1)\]
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
o.O Okay
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
if this is confusing, put \(a=\cos(x)\) and \(b=\sin(x)\) and factor \[5a^25b^2+a+b\]
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
That makes sense
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
it has nothing whatsoever to do with trig, but the all those trig functions will tend to confuse
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
\[5a^25b^2+a+b=5(a+b)(ab)+a+b=(5(ab)+1)(a+b)\]
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
:D figured it out! I can do "5a2−5b2+a+b" :P
 2 years ago

hawkfalcon Group TitleBest ResponseYou've already chosen the best response.0
Thanks :)
 2 years ago
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