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alfers101
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on a trip a family averaged 65km/hr for the first hour 50km/hr for the second hour and 58 km/hr for the third hour. what was their average speed?
 one year ago
 one year ago
alfers101 Group Title
on a trip a family averaged 65km/hr for the first hour 50km/hr for the second hour and 58 km/hr for the third hour. what was their average speed?
 one year ago
 one year ago

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mathslover Group TitleBest ResponseYou've already chosen the best response.2
a physics question @alfers101 please post this in physics section
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
though I will help you wait
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
given : 1) at t =1 hr. , average speed = 65 kmph 2) at t = 2hr. , average speed = 58 kmph so we know that: \[\large{\frac{\textbf{total distance travelled}}{\textbf{total time taken}}=\textbf{average speed}}\]
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
Oh sorry wait
 one year ago

lgbasallote Group TitleBest ResponseYou've already chosen the best response.0
also remember that \[\huge \frac{\text{speed}_1 + \text{speed}_2}{2} \ne \text{average speed}\] just saying
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
thanks? u got it soo soon @alfers101 ?
 one year ago

alfers101 Group TitleBest ResponseYou've already chosen the best response.0
no i still dont :( but i have the idea but i dont know how to answer this
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
oh k so what is the idea?
 one year ago

mathslover Group TitleBest ResponseYou've already chosen the best response.2
do you have the answer alfers101?
 one year ago

phi Group TitleBest ResponseYou've already chosen the best response.0
FIrst, find how far they drove. Use speed*time= distance they drove 65km/hr for the first hour: distance= 65*1 do the same thing for the 2nd hour (using the new speed), and the 3rd hour add up the distances now use speed*time= distance speed= distance/time distance will be the total distance time will be the total time ( 3 hours)
 one year ago
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