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hawkfalcon

  • 3 years ago

Find cos(theta) if tan(theta) = (-2/3) and sin(theta) > 0

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  1. hawkfalcon
    • 3 years ago
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    Find \[\cos \theta if \tan \theta = -2/3 and \sin \theta >0\]

  2. qpHalcy0n
    • 3 years ago
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    Here, you know that the tangent is opp/adjacent. Since the sine is positive, it must be in either the first or second quadrant right?

  3. hawkfalcon
    • 3 years ago
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    Yes.

  4. qpHalcy0n
    • 3 years ago
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    So the opposite leg must be positive, therefore since the tangent is negative the adjacent leg must be the negative one. So what quadrant is that?

  5. hawkfalcon
    • 3 years ago
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    Oh so you know o and a, you just need to find the h, and you can solve it :P

  6. qpHalcy0n
    • 3 years ago
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    Yep.

  7. qpHalcy0n
    • 3 years ago
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    Lets see what ya got when ya get it.

  8. hawkfalcon
    • 3 years ago
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    Thats 2nd quad

  9. hawkfalcon
    • 3 years ago
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    Okay:)

  10. qpHalcy0n
    • 3 years ago
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    Yep.

  11. hawkfalcon
    • 3 years ago
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    \[\frac{ -3 }{ \sqrt{13}}\]

  12. qpHalcy0n
    • 3 years ago
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    Thats it.

  13. hawkfalcon
    • 3 years ago
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    :D thank you!

  14. qpHalcy0n
    • 3 years ago
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    No prob.

  15. Yasir_se
    • 3 years ago
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    \[\frac{ x \sqrt{\left| x ^{2}-4 \right|} }{ x ^{2}-4 }-1>0\]

  16. hawkfalcon
    • 3 years ago
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    @Yasir_se wtf?

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